Chapter 1.2, Problem 26P

A bike rider is traveling at a speed of 15 feet per second. Write an expression for the distance the rider has traveled after $s$ seconds. Make a table that records the distance for 3.0, 5.8, 11.1, and 14.0 seconds.

To determine

To find: The algebraic expression for the distance the rider travelled after s seconds and also the table to find the distance for the given seconds.

Answer to Problem 26P

The algebraic expression is $15s$ and the table is

Seconds (s)	Distance (15s) in ft.
3.0	45
5.8	87
11.1	166.5
14.0	210

Explanation of Solution

Given information: The bike rider is travelling at a speed of 15ft per second. The rider travelled s seconds.

Calculation:

The speed of bike rider is 15ft per second.

The rider travelled after s seconds

$15\times s=15s$ ft.

$\therefore$ The expression is $15s$ .

For 3.0 seconds, the distance will be

$15\times 3.0=45$ ft.

For 5.8 seconds, the distance will be

$15\times 5.8=87$ ft.

For 11.1 seconds, the distance will be

$15\times 11.1=166.5$ ft.

For 14.0 seconds, the distance will be

$15\times 14.0=210$ ft.

The table is

Seconds (s)	Distance (15s) in ft.
3.0	45
5.8	87
11.1	166.5
14.0	210