Statistics for The Behavioral Sciences (MindTap Course List)
10th Edition
ISBN: 9781305504912
Author: Frederick J Gravetter, Larry B. Wallnau
Publisher: Cengage Learning
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Chapter 18, Problem 3P
- In problem 9 in Chapter 17, we described a study demonstrating that the colored is often associated with male dominance. Hill and Barton (2005) monitored the outcome of four combat sports, (boxing Tae Kwon Do, Greco-Roman wrestling, and freestyle wrestling) during the 2004 Olympic Games and found that participants wearing red outfits won significantly more often than those wearing blue.
- If athletes wearing red won 31 out of 50 matches is that sufficient to be significantly more than would be expected by chance? Use a two-tai led test with a = .05.
- If 62 out of 100 wearing red won, is that enough to be significant using a two-tailed test with a =.05.
- Note that the percentage of winning for red uniforms in part is identical to the percentage in part b (31/50= 62/100 = 62%) however, one is significant and the other is not. Explain why the two sample lead to different conclusions.
- The color red is often associated with anger and male dominance. Based on this observation, Hil1 and Barton (2005) monitored the outcome of four combat sports (boxing, tae kwan do, Greco-Roman wrestling, and freestyle wrestling, during the 2004 Olympic games and found that participants wearing red outfits won significantly more often than those wearing blue.
- In 50 wrestling matches involving red versus blue suppose that the red outfit won 31 times and lost 19 times. Is this sufficient to conclude that red wins significantly more than would be expected by chance? Test at the .05 level of significance. b. In 100 matches, suppose red won 62 times and lost 38. Is this sufficient to conclude that red wins sig nificantly more than would be expected by chance? Again, use a = .05.
c. Note that the winning percentage for red uniforms in part a is identical to the percentage in part b (31/50=62/100=62%). Although the two samples have an identical winning percentage, one is significant and the other is not. Explain why the two samples lead to different conclusions.
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Three players (one divider and two choosers) are going to divide a cake fairly using the lone divider method. The divider cuts the cake into three slices (s1, s2, and s3).
If the choosers' declarations are Chooser 1: {s1 , s2} and Chooser 2: {s2 , s3}.
Using the lone-divider method, how many different fair divisions of this cake are possible?
Theorem 2.6 (The Minkowski inequality)
Let p≥1. Suppose that X and Y are random variables, such that E|X|P <∞ and
E|Y P <00. Then
X+YpX+Yp
Theorem 1.2 (1) Suppose that P(|X|≤b) = 1 for some b > 0, that EX = 0, and
set Var X = 0². Then, for 0 0,
P(X > x) ≤e-x+1²²
P(|X|>x) ≤2e-1x+1²²
(ii) Let X1, X2...., Xn be independent random variables with mean 0, suppose
that P(X ≤b) = 1 for all k, and set oσ = Var X. Then, for
x > 0.
and
0x) ≤2 exp
Σ
k=1
(iii) If, in addition, X1, X2, X, are identically distributed, then
P(S|x) ≤2 expl-tx+nt²o).
Chapter 18 Solutions
Statistics for The Behavioral Sciences (MindTap Course List)
Ch. 18 - 1. Insurance companies charge young drivers more...Ch. 18 - 2. Güven, Elaimis, Binokay, and Tan (2003) studied...Ch. 18 - In problem 9 in Chapter 17, we described a study...Ch. 18 - 4. Problems 5 and 6 in Chapter 17 cited a study...Ch. 18 - 5. A researcher would like to determine whether...Ch. 18 - 6. A recent survey of practicing psychotherapists...Ch. 18 - 7. In 2005, Fung et al. published a study...Ch. 18 - 8. In problem 13 in Chapter 9, wepresented a study...Ch. 18 - Prob. 9PCh. 18 - Prob. 10P
Ch. 18 - Prob. 11PCh. 18 - 12. One of the original methods for testing ESP...Ch. 18 - Prob. 13PCh. 18 - Prob. 14PCh. 18 - 15. In Example 11.2 (p. 343) we presented a...Ch. 18 - Stressful or traumatic experiences can often...Ch. 18 - Prob. 17PCh. 18 - Prob. 18PCh. 18 - Prob. 19PCh. 18 - In Problem 14 in Chapter 11, we described a study...Ch. 18 - In problem 13 in Chapter 17, we Discussed a study...Ch. 18 - Prob. 22PCh. 18 - Prob. 23PCh. 18 - Prob. 24PCh. 18 - Prob. 25P
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