INTRO.TO GENERAL,ORGAN...-OWLV2 ACCESS
INTRO.TO GENERAL,ORGAN...-OWLV2 ACCESS
12th Edition
ISBN: 9781337915977
Author: Bettelheim
Publisher: CENGAGE L
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Chapter 18, Problem 36P
Interpretation Introduction

Interpretation:

Show the amide formation from the amino acids.

Concept introduction:

Polyamides are formed between the reaction of dicarboxylic acids and diamines. They are step-growth polymers. Macromolecule is defined as the molecule containing large number of atoms like nucleic acid and proteins.

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Are carboxylic acids or carboxylate ions more acidic? I'm confused about the terms and how to determine the acidity.  Here is my current understanding: Carboxylic acids have the ability to donate a hydrogen ion and become deprotonated, therefore it is acidic. Carboxylate ions are already deprotonated and have already become acidic. Is this correct?
The carbonyl group > C = O is an important functional group in biology and chemistry. Discuss this statement briefly with reference to the bonding in amides
Note these acronyms: HOAC = Acetic Acid; NaOAc = Sodium Acetate; THF = tetrahydrofuran Ph = Phenyl = C6H5; DMSO = Dimethyl Sulfoxide, H3C-O-H = methanol, NBS = N-Bromo succinimide, LDA = Lithium Diisopropylamide, DIA = Diisopropyl Amine, ACN=Acetonitrile Acetone = Acetic Acid = THF= DMSO= Ph= H3C CH3 H3C HO. H3C CH3 1. Circle the bromide below that most rapidly undergoes E2 reaction with NaOH in DMSO. The R group is tertiary butyl. Use conformational analysis to explain your answer. 2. Write the major alkene product formed when the bromides below react with the specified base. NaOH, DMSO solvent -Br -Ph Br NaOH, DMSO solvent Ph
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Acid-Base Titration | Acids, Bases & Alkalis | Chemistry | FuseSchool; Author: FuseSchool - Global Education;https://www.youtube.com/watch?v=yFqx6_Y6c2M;License: Standard YouTube License, CC-BY