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Chapter 18, Problem 2SA
Summary Introduction

To answer:

Why the hemolytic disease is not susceptible to a newborn with Rh- born to a Rh+ve mother.

Introduction:

Each person has different blood types when compared with others. Blood grouping is based on the ABO test and Rh test. People carry any one type of antigen in their red blood cells. The people with A antigens are grouped under A and people with B antigens are placed under B. The person with no antigen is placed under O group. Rh antigens are present in the red blood cells of the human. About 85% of humans have Rh+ve and 15% have Rh–ve antigens.

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How is Rh incompatibility involved in hemolytic disease of the newborn?  Is the mother Rh+ or Rh-? Is the fetus Rh+ or Rh-? Why is a second child that is Rh+ more susceptible to attack from the mother’s immune system.
Why might erythroblastosis fetalis occur when an Rh- mother becomes pregnant with a second Rh+ baby (after exposure to the previous Rh+ baby's blood)? A) Erythroblastosis fetalis can only occur when an Rh+ mother becomes pregnant with an Rh- baby. B) After primary exposure, if the Rh- mother has an Rh+ baby, then antibodies the mom produces can cross the placenta and attack the baby's blood. C) The Rh- mother always produces antibodies to the Rh+ blood, so erythroblastosis fetalis is a condition that can happen to any Rh+ baby (first or subsequent).
What will happen if an Rh-negative person receives a transfusion of Rh-positive blood? If a patient will receive a blood transfusion that is not matched to the patient’s blood type, what will happen? Explain briefly.

Chapter 18 Solutions

Microbiology with Diseases by Body System & Modified MasteringMicrobiology with Pearson eText -- ValuePack Access Card -- for Microbiology with Diseases by Body System Package

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