Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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Expert Solution & Answer
Chapter 18, Problem 19E
Explanation of Solution
Forest protocol not ensuring serializability
- Consider a system with two trees.
- The first tree consists of n1 as the parent node and n3, n4 as the child node of n1. n7 is the child node of n3 and n8, n9 are the child nodes of n4.
- The second tree consists of n2 as the parent node and n5, n6 as the child node of n2. n10 is the child node of n5 and n11, n12 as the child node of n6.
- There are two transactions T1 and T2.
- The legal schedule include:
T1 T2
lock(n1)
lock(n3)
write(n3)
unlock(n3)
lock(n2)
lock(n5)
...
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Students have asked these similar questions
1. Create a Book record that implements the Comparable interface, comparing the
Book objects by year
- title: String
>
- author: String
- year: int
Book
+ compareTo(other Book: Book): int
+ toString(): String
Submit your source code on Canvas (Copy
your code to text box or upload.java file)
>
Comparable
2. Create a main method in Book record.
1) In the main method, create an array of 2 objects of Book with your choice of
title, author, and year.
2) Sort the array by year
3) Print the object. Override the toString in Book to match the example output:
@Javadoc Declaration Console X Properties
Book [Java Application] /Users/kuan/.p2/pool/plugins/org.eclipse.justj.openjdk.hotspo
[Book: year=1901, Book: year=2010]
Q5-The efficiency of a 200 KVA, single phase transformer is 98% when operating at full load 0.8
lagging p.f. the iron losses in the transformer is 2000 watt. Calculate the i) Full load copper losses ii)
half load copper losses and efficiency at half load. Ans: 1265.306 watt, 97.186%
2. Consider the following pseudocode for partition:
function partition (A,L,R)
pivotkey = A [R]
t = L
for i
L to R-1 inclusive:
if A[i] A[i]
t = t + 1
end if
end for
A [t] A[R]
return t
end function
Suppose we call partition (A,0,5) on A=[10,1,9,2,8,5]. Show the state of the list at the
indicated instances.
Initial A
After i=0 ends
After 1 ends
After i 2 ends
After i = 3 ends
After i = 4 ends
After final swap
10 19 285
[12 pts]
Chapter 18 Solutions
Database System Concepts
Ch. 18 - Prob. 1PECh. 18 - Prob. 2PECh. 18 - Prob. 3PECh. 18 - Prob. 4PECh. 18 - Prob. 5PECh. 18 - Prob. 6PECh. 18 - Prob. 7PECh. 18 - Prob. 8PECh. 18 - Prob. 9PECh. 18 - Prob. 10PE
Ch. 18 - Prob. 11PECh. 18 - Prob. 12PECh. 18 - Prob. 13PECh. 18 - Prob. 14PECh. 18 - Prob. 17ECh. 18 - Prob. 18ECh. 18 - Prob. 19ECh. 18 - Prob. 20ECh. 18 - Prob. 21ECh. 18 - Prob. 22ECh. 18 - Prob. 23ECh. 18 - Prob. 24ECh. 18 - Prob. 25ECh. 18 - Prob. 26ECh. 18 - Prob. 27ECh. 18 - Prob. 28ECh. 18 - Prob. 29ECh. 18 - Prob. 30ECh. 18 - Prob. 31ECh. 18 - Prob. 32ECh. 18 - Prob. 33ECh. 18 - Prob. 34ECh. 18 - Prob. 35ECh. 18 - Prob. 36E
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