ORGANIC CHEMISTRY SAPLING ACCESS + ETEX
ORGANIC CHEMISTRY SAPLING ACCESS + ETEX
6th Edition
ISBN: 9781319306977
Author: LOUDON
Publisher: INTER MAC
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Chapter 18, Problem 18.73AP
Interpretation Introduction

Interpretation:

The reason as to why different stereoisomers on treatment with KOH give different products is to be stated.

Concept introduction:

In anti-elimination, β hydrogen is abstracted by base from the opposite side of the leaving the group. On the other hand, β hydrogen is abstracted by base from the same side of leaving the group. Anti-elimination is more favorable than syn-elimination.

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32. Consider a two-state system in which the low energy level is 300 J mol 1 and the higher energy level is 800 J mol 1, and the temperature is 300 K. Find the population of each level. Hint: Pay attention to your units. A. What is the partition function for this system? B. What are the populations of each level? Now instead, consider a system with energy levels of 0 J mol C. Now what is the partition function? D. And what are the populations of the two levels? E. Finally, repeat the second calculation at 500 K. and 500 J mol 1 at 300 K. F. What do you notice about the populations as you increase the temperature? At what temperature would you expect the states to have equal populations?
30. We will derive the forms of the molecular partition functions for atoms and molecules shortly in class, but the partition function that describes the translational and rotational motion of a homonuclear diatomic molecule is given by Itrans (V,T) = = 2πmkBT h² V grot (T) 4π²IKBT h² Where h is Planck's constant and I is molecular moment of inertia. The overall partition function is qmolec Qtrans qrot. Find the energy, enthalpy, entropy, and Helmholtz free energy for the translational and rotational modes of 1 mole of oxygen molecules and 1 mole of iodine molecules at 50 K and at 300 K and with a volume of 1 m³. Here is some useful data: Moment of inertia: I2 I 7.46 x 10- 45 kg m² 2 O2 I 1.91 x 101 -46 kg m²

Chapter 18 Solutions

ORGANIC CHEMISTRY SAPLING ACCESS + ETEX

Ch. 18 - Prob. 18.11PCh. 18 - Prob. 18.12PCh. 18 - Prob. 18.13PCh. 18 - Prob. 18.14PCh. 18 - Prob. 18.15PCh. 18 - Prob. 18.16PCh. 18 - Prob. 18.17PCh. 18 - Prob. 18.18PCh. 18 - Prob. 18.19PCh. 18 - Prob. 18.20PCh. 18 - Prob. 18.21PCh. 18 - Prob. 18.22PCh. 18 - Prob. 18.23PCh. 18 - Prob. 18.24PCh. 18 - Prob. 18.25PCh. 18 - Prob. 18.26PCh. 18 - Prob. 18.27PCh. 18 - Prob. 18.28PCh. 18 - Prob. 18.29PCh. 18 - Prob. 18.30PCh. 18 - Prob. 18.31PCh. 18 - Prob. 18.32PCh. 18 - Prob. 18.33PCh. 18 - Prob. 18.34PCh. 18 - Prob. 18.35PCh. 18 - Prob. 18.36PCh. 18 - Prob. 18.37PCh. 18 - Prob. 18.38PCh. 18 - Prob. 18.39PCh. 18 - Prob. 18.40PCh. 18 - Prob. 18.41PCh. 18 - Prob. 18.42PCh. 18 - Prob. 18.43PCh. 18 - Prob. 18.44PCh. 18 - Prob. 18.45PCh. 18 - Prob. 18.46APCh. 18 - Prob. 18.47APCh. 18 - Prob. 18.48APCh. 18 - Prob. 18.49APCh. 18 - Prob. 18.50APCh. 18 - Prob. 18.51APCh. 18 - Prob. 18.52APCh. 18 - Prob. 18.53APCh. 18 - Prob. 18.54APCh. 18 - Prob. 18.55APCh. 18 - Prob. 18.56APCh. 18 - Prob. 18.57APCh. 18 - Prob. 18.58APCh. 18 - Prob. 18.59APCh. 18 - Prob. 18.60APCh. 18 - Prob. 18.61APCh. 18 - Prob. 18.62APCh. 18 - Prob. 18.63APCh. 18 - Prob. 18.64APCh. 18 - Prob. 18.65APCh. 18 - Prob. 18.66APCh. 18 - Prob. 18.67APCh. 18 - Prob. 18.68APCh. 18 - Prob. 18.69APCh. 18 - Prob. 18.70APCh. 18 - Prob. 18.71APCh. 18 - Prob. 18.72APCh. 18 - Prob. 18.73APCh. 18 - Prob. 18.74APCh. 18 - Prob. 18.75APCh. 18 - Prob. 18.76APCh. 18 - Prob. 18.77APCh. 18 - Prob. 18.78APCh. 18 - Prob. 18.79APCh. 18 - Prob. 18.80APCh. 18 - Prob. 18.81APCh. 18 - Prob. 18.82APCh. 18 - Prob. 18.83APCh. 18 - Prob. 18.84APCh. 18 - Prob. 18.85APCh. 18 - Prob. 18.86APCh. 18 - Prob. 18.87APCh. 18 - Prob. 18.88APCh. 18 - Prob. 18.89APCh. 18 - Prob. 18.90APCh. 18 - Prob. 18.91APCh. 18 - Prob. 18.92AP
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