Chapter 18, Problem 18.62P

Interpretation Introduction

Interpretation:

It has to be shown that a plot of $\ln k$ versus $1/T$ is linear and the value of activation energy has to be calculated from the slop of the plot.

Concept Introduction:

Arrhenius Equation:

  $\ln k=-\frac{E_a}{RT}+\ln A$

Where, $k$ is the equilibrium constant, $E_a$ is the activation energy, $T$ is the absolute temperature, $R$ is the universal gas constant and $A$ is the frequency factor.

The plot of $\ln k$ versus $1/T$ results into a straight line of the form $y=mx+b$ with a slope of $-\frac{E_a}{R}$ and an intercept of $\ln A.$