Organic Chemistry
Organic Chemistry
5th Edition
ISBN: 9780078021558
Author: Janice Gorzynski Smith Dr.
Publisher: McGraw-Hill Education
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Chapter 18, Problem 18.49P

For each N-substituted benzene, predict whether the compound reacts faster than, slower than, or at a similar rate to benzene in electrophilic aromatic substitution. Then draw the major product(s) formed when each compound reacts with a general electrophile E + .

a. Chapter 18, Problem 18.49P, 18.49 For each N-substituted benzene, predict whether the compound reacts faster than, slower than, , example  1 b. Chapter 18, Problem 18.49P, 18.49 For each N-substituted benzene, predict whether the compound reacts faster than, slower than, , example  2 c. Chapter 18, Problem 18.49P, 18.49 For each N-substituted benzene, predict whether the compound reacts faster than, slower than, , example  3 d. Chapter 18, Problem 18.49P, 18.49 For each N-substituted benzene, predict whether the compound reacts faster than, slower than, , example  4

Expert Solution
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Interpretation Introduction

(a)

Interpretation: The given compound reacts faster than, slower than, or at equal rate to benzene in electrophilic aromatic substitution is to be predicted and the major product(s) formed by the reaction between given compound and general electrophile E+ is to be drawn.

Concept introduction: The replacement or substitution of one functional group with another different functional group in any chemical reaction is termed as substitution reaction. The electron deficient chemical species that contains positive charge are known as electrophile. In electrophilic aromatic substitution reaction, electrophile takes the position of hydrogen atom by attacking the electron rich carbon atom of benzene.

Answer to Problem 18.49P

The given compound reacts faster in electrophilic substitution reaction than benzene ring. The major product formed by the reaction between given compound and general electrophile E+ is shown below:

Organic Chemistry, Chapter 18, Problem 18.49P , additional homework tip  1

Explanation of Solution

The electron donating groups or activating groups make benzene ring more electron rich, as a result the compound reacts faster in electrophilic substitution reaction than benzene ring. On the other hand, the electron withdrawing groups or deactivating groups make benzene ring less electron rich; as a result the compound reacts slower in electrophilic substitution reaction than benzene ring.

In the given compound, benzene ring is attached to NR2 group, which is a strong electron donating group. Therefore, the given compound reacts faster in electrophilic substitution reaction than benzene ring.

The activating groups are ortho, para directing whereas the deactivating groups are meta directing. The major product formed by the reaction between given compound and general electrophile E+ is shown in Figure 1.

Organic Chemistry, Chapter 18, Problem 18.49P , additional homework tip  2

Figure 1

Conclusion

The given compound reacts faster in electrophilic substitution reaction than benzene ring. The major product formed by the reaction between given compound and general electrophile E+ is shown in Figure 1.

Expert Solution
Check Mark
Interpretation Introduction

(b)

Interpretation: The given compound reacts faster than, slower than, or at equal rate to benzene in electrophilic aromatic substitution is to be predicted and the major product(s) formed by the reaction between given compound and general electrophile E+ is to be drawn.

Concept introduction: The replacement or substitution of one functional group with another different functional group in any chemical reaction is termed as substitution reaction. The electron deficient chemical species that contains positive charge are known as electrophile. In electrophilic aromatic substitution reaction, electrophile takes the position of hydrogen atom by attacking the electron rich carbon atom of benzene.

Answer to Problem 18.49P

The given compound reacts slower in electrophilic substitution reaction than benzene ring. The major product formed by the reaction between given compound and general electrophile E+ is shown below:

Organic Chemistry, Chapter 18, Problem 18.49P , additional homework tip  3

Explanation of Solution

The electron donating groups or activating groups make benzene ring more electron rich, as a result the compound reacts faster in electrophilic substitution reaction than benzene ring. On the other hand, the electron withdrawing groups or deactivating groups make benzene ring less electron rich; as a result the compound reacts slower in electrophilic substitution reaction than benzene ring.

In the given compound, benzene ring is attached to N+H(CH3)2 group, which is a strong electron withdrawing group. Therefore, the given compound reacts slower in electrophilic substitution reaction than benzene ring.

The activating groups are ortho, para directing whereas the deactivating groups are meta directing. The major product formed by the reaction between given compound and general electrophile E+ is shown in Figure 2.

Organic Chemistry, Chapter 18, Problem 18.49P , additional homework tip  4

Figure 2

Conclusion

The given compound reacts slower in electrophilic substitution reaction than benzene ring. The major product formed by the reaction between given compound and general electrophile E+ is shown in Figure 2.

Expert Solution
Check Mark
Interpretation Introduction

(c)

Interpretation: The given compound reacts faster than, slower than, or at equal rate to benzene in electrophilic aromatic substitution is to be predicted and the major product(s) formed by the reaction between given compound and general electrophile E+ is to be drawn.

Concept introduction: The replacement or substitution of one functional group with another different functional group in any chemical reaction is termed as substitution reaction. The electron deficient chemical species that contains positive charge are known as electrophile. In electrophilic aromatic substitution reaction, electrophile takes the position of hydrogen atom by attacking the electron rich carbon atom of benzene.

Answer to Problem 18.49P

The given compound reacts slower in electrophilic substitution reaction than benzene ring. The major product formed by the reaction between given compound and general electrophile E+ is shown below:

Organic Chemistry, Chapter 18, Problem 18.49P , additional homework tip  5

Explanation of Solution

The electron donating groups or activating groups make benzene ring more electron rich, as a result the compound reacts faster in electrophilic substitution reaction than benzene ring. On the other hand, the electron withdrawing groups or deactivating groups make benzene ring less electron rich; as a result the compound reacts slower in electrophilic substitution reaction than benzene ring.

In the given compound, benzene ring is attached to NO2 and N+(CH3)3 groups. Both of these groups are strong electron withdrawing group. Therefore, the given compound reacts slower in electrophilic substitution reaction than benzene ring.

The activating groups are ortho, para directing whereas the deactivating groups are meta directing. The major product formed by the reaction between given compound and general electrophile E+ is shown in Figure 3.

Organic Chemistry, Chapter 18, Problem 18.49P , additional homework tip  6

Figure 3

Conclusion

The given compound reacts slower in electrophilic substitution reaction than benzene ring. The major product formed by the reaction between given compound and general electrophile E+ is shown in Figure 3.

Expert Solution
Check Mark
Interpretation Introduction

(d)

Interpretation: The given compound reacts faster than, slower than, or at equal rate to benzene in electrophilic aromatic substitution is to be predicted and the major product(s) formed by the reaction between given compound and general electrophile E+ is to be drawn.

Concept introduction: The replacement or substitution of one functional group with another different functional group in any chemical reaction is termed as substitution reaction. The electron deficient chemical species that contains positive charge are known as electrophile. In electrophilic aromatic substitution reaction, electrophile takes the position of hydrogen atom by attacking the electron rich carbon atom of benzene.

Answer to Problem 18.49P

The given compound reacts at a similar rate to benzene in electrophilic substitution reaction. The major product formed by the reaction between given compound and general electrophile E+ is shown below:

Organic Chemistry, Chapter 18, Problem 18.49P , additional homework tip  7

Explanation of Solution

The electron donating groups or activating groups make benzene ring more electron rich, as a result the compound reacts faster in electrophilic substitution reaction than benzene ring. On the other hand, the electron withdrawing groups or deactivating groups make benzene ring less electron rich; as a result the compound reacts slower in electrophilic substitution reaction than benzene ring.

In the given compound, benzene ring is attached to NR2 and NO2 groups. The NO2 group is a strong electron withdrawing group and NR2 group is a strong electron donating group. Therefore, the given compound reacts at a similar rate to benzene in electrophilic substitution reaction.

The activating groups are ortho, para directing whereas the deactivating groups are meta directing. The major product formed by the reaction between given compound and general electrophile E+ is shown in Figure 4.

Organic Chemistry, Chapter 18, Problem 18.49P , additional homework tip  8

Figure 4

Conclusion

The given compound reacts at a similar rate to benzene in electrophilic substitution reaction. The major product formed by the reaction between given compound and general electrophile E+ is shown in Figure 4.

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Chapter 18 Solutions

Organic Chemistry

Ch. 18 - Prob. 18.11PCh. 18 - Prob. 18.12PCh. 18 - Prob. 18.13PCh. 18 - Problem 18.14 Draw all resonance structures for...Ch. 18 - Problem 18.15 Classify each substituent as...Ch. 18 - Prob. 18.16PCh. 18 - Problem 18.17 Label each compound as more or less...Ch. 18 - Problem 18.18 Rank the following compounds in...Ch. 18 - Prob. 18.19PCh. 18 - Problem 18.20 Draw the products of each...Ch. 18 - Prob. 18.21PCh. 18 - Problem 18.22 Draw the products formed when each...Ch. 18 - Problem 18.23 Devise a synthesis of each compound...Ch. 18 - Problem 18.24 Draw the products of each...Ch. 18 - Problem 18.25 Draw a stepwise mechanism for the...Ch. 18 - Problem 18.26 Draw the products of each...Ch. 18 - Prob. 18.27PCh. 18 - Prob. 18.28PCh. 18 - Problem 18.29 How could you use ethylbenzene to...Ch. 18 - Prob. 18.30PCh. 18 - Problem 18.31 What steps are needed to convert...Ch. 18 - Problem 18.32 Synthesize each compound from...Ch. 18 - Problem 18.33 Synthesize each compound from...Ch. 18 - Prob. 18.34PCh. 18 - 18.35 What is the major product formed by an...Ch. 18 - 18.36 Draw the products formed when phenol is...Ch. 18 - Problem 18.37 Draw the products formed when each...Ch. 18 - 18.38 Draw the products of each reaction. a. d....Ch. 18 - 18.39 What products are formed when benzene is...Ch. 18 - 18.40 Draw the products of each reaction. c. d....Ch. 18 - 18.41 You have learned two ways to make an alkyl...Ch. 18 - 18.42 Draw the structure of A, an intermediate in...Ch. 18 - Prob. 18.43PCh. 18 - Prob. 18.44PCh. 18 - 18.45 Explain why each of the following reactions...Ch. 18 - Prob. 18.46PCh. 18 - 18.47 For each of the following substituted...Ch. 18 - 18.48 Consider the tetracyclic aromatic compound...Ch. 18 - 18.49 For each N-substituted benzene, predict...Ch. 18 - Prob. 18.50PCh. 18 - 18.51 Using resonance structures, explain why a...Ch. 18 - Prob. 18.52PCh. 18 - 18.53 Rank the aryl halides in each group in order...Ch. 18 - 18.54 Draw a stepwise mechanism for the following...Ch. 18 - Prob. 18.55PCh. 18 - 18.56 Draw a stepwise, detailed mechanism for the...Ch. 18 - Prob. 18.57PCh. 18 - 18.58 Draw a stepwise mechanism for the following...Ch. 18 - Prob. 18.59PCh. 18 - Prob. 18.60PCh. 18 - Prob. 18.61PCh. 18 - Prob. 18.62PCh. 18 - 18.63 Synthesize each compound from benzene and...Ch. 18 - Problem 18.64 Synthesize each compound from...Ch. 18 - Prob. 18.65PCh. 18 - Prob. 18.66PCh. 18 - Prob. 18.67PCh. 18 - Prob. 18.68PCh. 18 - Problem 18.69 Identify the structures of isomers A...Ch. 18 - Prob. 18.70PCh. 18 - Problem 18.71 Compound X (molecular formula ) was...Ch. 18 - 18.72 Reaction of p-cresol with two equivalents of...Ch. 18 - Prob. 18.73PCh. 18 - The NMR spectrum of phenol () shows three...Ch. 18 - Explain the reactivity and orientation effects...Ch. 18 - Prob. 18.76PCh. 18 - Prob. 18.77PCh. 18 - Prob. 18.78PCh. 18 - Prob. 18.79P
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