(a) Explanation Given information: The Tunnel length is 2.00 km , the speed of sound in air is 343 m / s The general expression frequency for open tube is, f = n v 2 L (1) Here, v is the speed of sound in air. f is the frequency of sound. L is the length of the piston from end. Substitute 2.00 km for L and 343 m / s for v in (1) (b) To determine To explain: Whether it would be good to make a rule against blowing in tunnel.

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN: 9781305116399

Author: Raymond A. Serway, John W. Jewett

Publisher: Cengage Learning

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Chapter 18, Problem 18.48P

(a)

To determine

Thefrequency at which air tunnel resonate.

(b)

To determine

To explain:Whether it would be good to make a rule against blowing in tunnel.

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Chapter 18, Problem 18.47P

Chapter 18, Problem 18.49P

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Physics for Scientists and Engineers, Technology Update (No access codes included)

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Thefrequency at which air tunnel resonate.

Solution Summary: The author explains that the frequency at which air tunnel resonate is 0.086Hz.

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Thefrequency at which air tunnel resonate.

To explain:Whether it would be good to make a rule against blowing in tunnel.

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Chapter 18 Solutions