Principles of Foundation Engineering (MindTap Course List)
9th Edition
ISBN: 9781337705028
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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Chapter 18, Problem 18.3P
To determine
Find the required actual depth of the sheet pile.
Select suitable section of sheet pile.
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P.3.3
Oil of sp.gr. 0.9 flows through a vertical pipe (upwards). Two points A and B one
above the other 40 cm apart in a pipe are connected by a U-tube carrying mercury. If
the difference of pressure between A and B is 0.2 kg/cm²,
1- Find the reading of the manometer.
2- If the oil flows through a horizontal pipe, find the reading in manometer for the
same difference in pressure between A and B.
Ans. 1- R= 0.12913 m, 2- R = 0.1575 m,
Please solve the question by hand with a detailed explanation of the steps.
Please solve the question by hand with a detailed explanation of the steps.
Chapter 18 Solutions
Principles of Foundation Engineering (MindTap Course List)
Ch. 18 - Refer to Figure 18.9. A cantilever sheet pile is...Ch. 18 - Prob. 18.2PCh. 18 - Prob. 18.3PCh. 18 - Refer to Figure 18.13. Given L1 = 1.5 m, L2 = 3 m;...Ch. 18 - In Problem 18.4, find the maximum bending moment...Ch. 18 - Prob. 18.6PCh. 18 - Prob. 18.7PCh. 18 - Prob. 18.8PCh. 18 - Refer to Figure 18.23. Given L1=3m, L2=6m,...Ch. 18 - Prob. 18.10P
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.Similar questions
- P.3.4 A mercury U-tube manometer is used to measure the pressure drop across an orifice in pipe. If the liquid that flowing through the orifice is brine of sp.gr. 1.26 and upstream pressure is 2 psig and the downstream pressure is (10 in Hg) vacuum, find the reading of manometer. Ans. R=394 mm Hgarrow_forwardProject management questionarrow_forwardQ5/B with Explantion plsarrow_forward
- project management question Q5/Barrow_forwardProblem 1: Given: In a given floor system, a 5-in concrete slab supported by T-beams of 24-ft spans, supporting 354 psf live load. The T-beams are spaced 2x4 ft on center, and bw (width of the beam web) = 15 inches. Total T-beam height is 25 inches. f'c = 4,000psi, fy = 60,000psi. Design the T-beam. Show all steps. Sketch your Design. Problem 2: Given: A 25"x25" column is subject to a factored axial load of Pu=1,200 kips, and factored design moment of Mu-354 kips-ft. f'c 4,000psi, fy = 60,000psi. Determine the required steel ratio (p) and ties. Sketch the design. 2.0 0.08 INTERACTION DIAGRAM R4-60.9 fc-4 ksi 1.8 1,- 60 ksi 0.07 Y=0.9 16 1.6 0.06 Kmax 0.05 1.4 f/f, = 0 0.04 00 K₁ = P₁/f'c Ag 1.2 12 0.03 0.25 1.0 10 0.02 0.01 0.8 0.6 0.4 €,= 0.0035 0.2 €,= 0.0050 0.0 h yh 0.50 0.75 1.0. 0.00 0.05 0.10 0.15 0.20 0.25 0.30 0.35 0.40 0.45 0.50 R₁ = P₁e/f'Agharrow_forwardGiven: In a given floor system, a 5-in concrete slab supported by T-beams of 24-ft spans, supporting 354 psf live load. The T-beams are spaced 2x4 ft on center, and bw (width of the beam web) = 15 inches. Total T-beam height is 25 inches. f'c = 4,000psi, fy = 60,000psi. Design the T-beam. Show all steps. Sketch your Design.arrow_forward
- Problem 2: Given: A 25"x25" column is subject to a factored axial load of Pu=1,200 kips, and factored design moment of Mu-354 kips-ft. f'c 4,000psi, fy = 60,000psi. Determine the required steel ratio (p) and ties. Sketch the design. 2.0 P=0.08 INTERACTION DIAGRAM R4-60.9 fc-4 ksi 1.8 1,- 60 ksi 0.07 7=0.9 1.6 16 0.06 Kmax 0.05 1.4 f/f, = 0 0.04 90 K₁ = P₁/f'Ag 1.2 0.03 0.25 0.02 1.0 0.01 0.8 0.6 0.4 €= 0.0035 0.2 €,= 0.0050 0.0 h yh 0.50 0.75 1.0. 0.00 0.05 0.10 0.15 0.20 0.25 0.30 0.35 0.40 0.45 0.50 R₁ = P₁e/f'Aharrow_forwardGiven: A 25"x25" column is subject to a factored axial load of Pu=1,200 kips, and factored design moment of Mu=354 kips-ft. f'c 4,000psi, fy = 60,000psi. Determine the required steel ratio () and ties. Sketch the design.arrow_forwardSee Figure (1) below. A 14 in. wide and 2 in. thick plate subject to tensile loading has staggered holes as shown. Compute An and Ae. P 2.00 3.00 4.00 3.00 2.00 ΕΙ T A B C F G D S = 2.50 3/4" bolts in 13/16" holes 14x12 PL Parrow_forward
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