Concept explainers
(a)
Interpretation:
The given
Concept introduction:
The aqueous of acidic, basic or neutral is identified by using following method.
The depending on an ion’s ability to react with water,
If the solution is neutral, the anion from strong acid and the cation from strong base.
If the solution is acidic, the anion from strong acid (or highly charged metal cation) and the cation from weak base.
If the solution is basic, the anion from weak acid and the cation from strong base.
Acidic solution:
If the solution is acidic, I would form from cation of weak base and anion of strong acid.
In addition, small, highly charged metal cation and anion of strong acid are acidic solution.
The
Basic solution:
If the solution is basic, I would form from cation of strong base and anion of weak acid.
Neutral solution:
If the solution is neutral, I would form from cation of strong base and anion of strong acid.
The
(b)
Interpretation:
The given
Concept introduction:
The aqueous of acidic, basic or neutral is identified by using following method.
The depending on an ion’s ability to react with water,
If the solution is neutral, the anion from strong acid and the cation from strong base.
If the solution is acidic, the anion from strong acid (or highly charged metal cation) and the cation from weak base.
If the solution is basic, the anion from weak acid and the cation from strong base.
Acidic solution:
If the solution is acidic, I would form from cation of weak base and anion of strong acid.
In addition, small, highly charged metal cation and anion of strong acid are acidic solution.
The
Basic solution:
If the solution is basic, I would form from cation of strong base and anion of weak acid.
Neutral solution:
If the solution is neutral, I would form from cation of strong base and anion of strong acid.
The
(c)
Interpretation:
The given
Concept introduction:
The aqueous of acidic, basic or neutral is identified by using following method.
The depending on an ion’s ability to react with water,
If the solution is neutral, the anion from strong acid and the cation from strong base.
If the solution is acidic, the anion from strong acid (or highly charged metal cation) and the cation from weak base.
If the solution is basic, the anion from weak acid and the cation from strong base.
Acidic solution:
If the solution is acidic, I would form from cation of weak base and anion of strong acid.
In addition, small, highly charged metal cation and anion of strong acid are acidic solution.
The
Basic solution:
If the solution is basic, I would form from cation of strong base and anion of weak acid.
Neutral solution:
If the solution is neutral, I would form from cation of strong base and anion of strong acid.
The
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Chapter 18 Solutions
CHEM 212:CHEMISTSRY V 2
- Do the electrons on the OH participate in resonance with the ring through a p orbital? How many pi electrons are in the ring, 4 (from the two double bonds) or 6 (including the electrons on the O)?arrow_forwardPredict and draw the product of the following organic reaction:arrow_forwardNonearrow_forward
- Redraw the molecule below as a skeletal ("line") structure. Be sure to use wedge and dash bonds if necessary to accurately represent the direction of the bonds to ring substituents. Cl. Br Click and drag to start drawing a structure. : ☐ ☑ Parrow_forwardK m Choose the best reagents to complete the following reaction. L ZI 0 Problem 4 of 11 A 1. NaOH 2. CH3CH2CH2NH2 1. HCI B OH 2. CH3CH2CH2NH2 DII F1 F2 F3 F4 F5 A F6 C CH3CH2CH2NH2 1. SOCl2 D 2. CH3CH2CH2NH2 1. CH3CH2CH2NH2 E 2. SOCl2 Done PrtScn Home End FA FQ 510 * PgUp M Submit PgDn F11arrow_forwardNonearrow_forward
- Add curved arrows to the reactants in this reaction. A double-barbed curved arrow is used to represent the movement of a pair of electrons. Draw curved arrows. : 0: si H : OH :: H―0: Harrow_forwardConsider this step in a radical reaction: Br N O hv What type of step is this? Check all that apply. Draw the products of the step on the right-hand side of the drawing area below. If more than one set of products is possible, draw any set. Also, draw the mechanism arrows on the left-hand side of the drawing area to show how this happens. O primary Otermination O initialization O electrophilic O none of the above × ☑arrow_forwardNonearrow_forward
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