Chapter 18, Problem 18.121P

(a)

Interpretation Introduction

Interpretation:

Aqueous solution of ${\text{SnCl}}_{\text{2}}$ is whether the solution is acidic, basic or neutral has to be identified with equation and calculation.

Concept introduction:

The aqueous of acidic, basic or neutral is identified by using following method.

The depending on an ion’s ability to react with water,

If the solution is neutral, then the anion is from strong acid and the cation from strong base.

If the solution is acidic, then the anion is from strong acid (or highly charged metal cation) and the cation from weak base.

If the solution is basic, then the anion is from weak acid and the cation from strong base.

(b)

Interpretation Introduction

Interpretation:

Aqueous solution of $\text{NaHS}$ is whether the solution is acidic, basic or neutral has to be identified with equation and calculation.

Concept introduction:

The aqueous of acidic, basic or neutral is identified by using following method.

The depending on an ion’s ability to react with water,

If the solution is neutral, then the anion is from strong acid and the cation from strong base.

If the solution is acidic, then the anion is from strong acid (or highly charged metal cation) and the cation from weak base.

If the solution is basic, then the anion is from weak acid and the cation from strong base.

(c)

Interpretation Introduction

Interpretation:

Aqueous solution of ${\text{Zn(CH}}_{\text{3}}{\text{COO)}}_{\text{2}}$ is whether the solution is acidic, basic or neutral has to be identified with equation and calculation.

Concept introduction:

The aqueous of acidic, basic or neutral is identified by using following method.

The depending on an ion’s ability to react with water,

If the solution is neutral, then the anion is from strong acid and the cation from strong base.

If the solution is acidic, then the anion is from strong acid (or highly charged metal cation) and the cation from weak base.

If the solution is basic, then the anion is from weak acid and the cation from strong base.

The ${\text{K}}_{\text{b}}$ value is calculating by using following formula,

${\text{K}}_{\text{w}}{\text{ = K}}_{\text{a}}{\text{ × K}}_{\text{b}}$