Explanation Determine the stagnation temperature of air. T 0 = T + V 2 2 c p (I) Here, the static temperature of air is T , the specific heat of pressure for air is c p , and the velocity of the air flow is V . Determine the stagnation pressure of air. P 0 = P ( T 0 T ) k / ( k − 1 ) (II) Here, the static pressure of air is P , the specific heat ratio of air is k . Conclusion: Convert the unit ° C to K . T = 25 ° C = ( 25 + 273.2 ) K =298 .2 K From the Table A-2, “Ideal-gas specific heats of various common gases” to obtain value of specific heat of pressure of air and the specific heat ratio of air at 300 K temperature as 1.005 kJ / kg ⋅ K and 1.4 . Substitute 298.2 K for T , 250 m / s for V , and 1.005 kJ / kg ⋅ K for c p in Equation (I). T 0 = ( 298.2 K ) + ( 250 m / s ) 2 2 × ( 1.005 kJ / kg ⋅ K ) = ( 298.2 K ) + ( 62500 m 2 / s 2 ) 2 × ( 1

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Chapter 17.7, Problem 155FEP

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The stagnation pressure of air.

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Chapter 17.7, Problem 154FEP

Chapter 17.7, Problem 156FEP

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Chapter 17 Solutions

EBK THERMODYNAMICS: AN ENGINEERING APPR

Ch. 17.7 - A high-speed aircraft is cruising in still air....Ch. 17.7 - What is dynamic temperature?Ch. 17.7 - Prob. 3P Ch. 17.7 - Prob. 4P Ch. 17.7 - Prob. 5P Ch. 17.7 - Calculate the stagnation temperature and pressure...Ch. 17.7 - Prob. 7P Ch. 17.7 - Prob. 8P Ch. 17.7 - Prob. 9P Ch. 17.7 - Prob. 10P

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