Engineering Fundamentals: An Introduction to Engineering
6th Edition
ISBN: 9780357391273
Author: Saeed Moaveni
Publisher: Cengage Learning US
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Chapter 17.5, Problem 1BYG
To determine
Explain the difference between the softwood and hardwood.
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Use the Force Method to analyse the structure. After the analysis, draw Bending Moment and Shear Force diagrams. Redundants need to be put at 'j' and 'k' as moments (EI is constant all across the structure)I am so confused as to how to approach the problem. I would really appreciate an answer with a little explanation, or helpful working out!
I got 5.97 mm please show your work clearly. thank you
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SK-> VE
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T
A=52 E=29000 ksi
diagonal members
6' A=30.25.72 E=1800 ksi for
horizontal & vertical member
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B
Oc
AD
8
Primary Structures remove roller @C make D a roller
For Primary
and Cut BF
For redundant
Ik ↑
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Ik = @D
Ik @BF
Chapter 17 Solutions
Engineering Fundamentals: An Introduction to Engineering
Ch. 17.1 - Give examples of properties that engineers...Ch. 17.1 - Prob. 2BYGCh. 17.1 - Prob. 3BYGCh. 17.1 - Prob. 4BYGCh. 17.1 - Prob. 5BYGCh. 17.1 - Prob. BYGVCh. 17.2 - Prob. 1BYGCh. 17.2 - Prob. 2BYGCh. 17.2 - Prob. 3BYGCh. 17.2 - In your own words, explain what is meant by the...
Ch. 17.2 - Prob. 5BYGCh. 17.2 - Prob. BYGVCh. 17.3 - What is a lightweight metal?Ch. 17.3 - Prob. 2BYGCh. 17.3 - Prob. 3BYGCh. 17.3 - Prob. 4BYGCh. 17.3 - Give examples of copper use.Ch. 17.3 - VocabularyState the meaning of the following...Ch. 17.4 - What are the main ingredients of concrete?Ch. 17.4 - Why is water sprayed on newly poured concrete for...Ch. 17.4 - Prob. 3BYGCh. 17.4 - Prob. BYGVCh. 17.5 - Prob. 1BYGCh. 17.5 - Prob. 2BYGCh. 17.5 - Prob. 3BYGCh. 17.5 - Prob. 4BYGCh. 17.5 - Prob. 5BYGCh. 17.5 - Prob. 6BYGCh. 17.5 - Prob. BYGVCh. 17.6 - Prob. 1BYGCh. 17.6 - Prob. 2BYGCh. 17.6 - Prob. 3BYGCh. 17.6 - Prob. 4BYGCh. 17.6 - Prob. BYGVCh. 17 - Prob. 1PCh. 17 - Prob. 2PCh. 17 - Prob. 3PCh. 17 - Prob. 4PCh. 17 - Prob. 5PCh. 17 - Prob. 6PCh. 17 - Prob. 7PCh. 17 - Prob. 8PCh. 17 - Prob. 9PCh. 17 - Prob. 11PCh. 17 - Prob. 12PCh. 17 - Prob. 13PCh. 17 - Prob. 14PCh. 17 - Prob. 16PCh. 17 - Prob. 18PCh. 17 - Prob. 20PCh. 17 - Prob. 22PCh. 17 - Prob. 27PCh. 17 - Prob. 28PCh. 17 - Prob. 29PCh. 17 - Prob. 30PCh. 17 - Prob. 32P
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- Determine the smallest value of yield stress Fy, for which a W-, M-, or S-shape from the list below will become slender. bf/2tfh/tw Shape W12 × 72 8.99 22.6 W12 × 26 8.54 47.2 M4 × 6 11.9 22.0 M12 x 11.8 6.81 62.5 M6 × 4.4 5.39 47.0 S24 × 80 4.02 41.4 S10 × 35 5.03 13.4 (Express your answer to three significant figures.) Fy = ksi To which shape does this value apply? -Select- ✓arrow_forwardCompute the nominal shear strength of an M12 × 11.8 of A572 Grade 60 steel (Fy = 60 ksi). For M12 x 11.8: d = 12 in., tw = 0.177 in., h/tw = 62.5. Vn = kipsarrow_forwardA flexural member is fabricated from two flange plates 1/2 × 71/2 and a web plate 3/8 × 19. The yield stress of the steel is 50 ksi. a. Compute the plastic section modulus Z and the plastic moment Mp with respect to the major principal axis. (Express your answers to three significant figures.) Z = Mp = in. 3 ft-kips b. Compute the elastic section modulus S and the yield moment My with respect to the major principal axis. (Express your answers to three significant figures.) S = My = in.3 ft-kipsarrow_forward
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