Engineering Mechanics: Statics & Dynamics (14th Edition)
14th Edition
ISBN: 9780133915426
Author: Russell C. Hibbeler
Publisher: PEARSON
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Chapter 17.4, Problem 85P
To determine
The internal normal force, shear force, and moment as a function of
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Chapter 17 Solutions
Engineering Mechanics: Statics & Dynamics (14th Edition)
Ch. 17.1 - Determine the moment of inertia Iy for the slender...Ch. 17.1 - The solid cylinder has an outer radius R1 height...Ch. 17.1 - Determine the moment of inertia of the thin ring...Ch. 17.1 - The paraboloid is formed by revolving the shaded...Ch. 17.1 - Determine the radius of gyration kr of the body....Ch. 17.1 - The sphere is formed by revolving the shaded area...Ch. 17.1 - The frustum is formed by rotating the shaded area...Ch. 17.1 - Prob. 8PCh. 17.1 - Prob. 9PCh. 17.1 - The pendulum consists of a 4-kg circular plate and...
Ch. 17.1 - The assembly is made of the slender rods that have...Ch. 17.1 - Prob. 12PCh. 17.1 - The wheel consists of a thin ring having a mass of...Ch. 17.1 - If the large ring, small ring and each of the...Ch. 17.1 - Determine the moment of inertia about an axis...Ch. 17.1 - Prob. 16PCh. 17.1 - Determine the location y of the center of mass G...Ch. 17.1 - Prob. 18PCh. 17.1 - Prob. 19PCh. 17.1 - Determine the moment of inertia of the wheel about...Ch. 17.1 - The pendulum consists of the 3-kg slender rod and...Ch. 17.1 - Prob. 22PCh. 17.1 - Determine the moment of inertia of the overhung...Ch. 17.3 - Draw the free-body and kinetic diagrams of the...Ch. 17.3 - Prob. 2PPCh. 17.3 - Prob. 1FPCh. 17.3 - Prob. 2FPCh. 17.3 - Prob. 3FPCh. 17.3 - Prob. 4FPCh. 17.3 - At the instant shown both rods of negligible mass...Ch. 17.3 - Prob. 6FPCh. 17.3 - The door has a weight of 200 lb and a center of...Ch. 17.3 - The door has a weight or 200 lb and a center of...Ch. 17.3 - The jet aircraft has a total mass of 22 Mg and a...Ch. 17.3 - The sports car has a weight of 4500 lb and center...Ch. 17.3 - The assembly has a mass of 8 Mg and is hoisted...Ch. 17.3 - The assembly has a mass of 4 Mg and is hoisted...Ch. 17.3 - The uniform girder AB has a mass of 8 Mg....Ch. 17.3 - A car having a weight of 4000 lb begins to skid...Ch. 17.3 - A force of P = 300 N is applied to the 60-kg cart....Ch. 17.3 - Determine the largest force P that can be applied...Ch. 17.3 - The trailer with its load has a mass of 150-kg and...Ch. 17.3 - The desk has a weight of 75 lb and a center of...Ch. 17.3 - The desk has a weight of 75 lb and a center of...Ch. 17.3 - The 150-kg uniform crate rests on the 10-kg cart....Ch. 17.3 - The 150-kg uniform crate rests on the 10-kg cart....Ch. 17.3 - The bar has a weight per length w and is supported...Ch. 17.3 - The smooth 180-lb pipe has a length of 20 ft and a...Ch. 17.3 - The smooth 180-lb pipe has a length of 20 ft and a...Ch. 17.3 - The uniform crate has a mass of 50 kg and rests on...Ch. 17.3 - Determine the acceleration of the 150-lb cabinet...Ch. 17.3 - Prob. 44PCh. 17.3 - Prob. 45PCh. 17.3 - Prob. 46PCh. 17.3 - Prob. 47PCh. 17.3 - The snowmobile has a weight of 250 lb, centered at...Ch. 17.3 - If the carts mass is 30 kg and it is subjected to...Ch. 17.3 - Prob. 50PCh. 17.3 - The pipe has a mass of 800 kg and is being towed...Ch. 17.3 - The pipe has a mass of 800 kg and is being towed...Ch. 17.3 - Prob. 53PCh. 17.3 - Prob. 54PCh. 17.3 - Prob. 55PCh. 17.3 - Prob. 56PCh. 17.4 - The 100-kg wheel has a radius of gyration about...Ch. 17.4 - Prob. 8FPCh. 17.4 - Prob. 9FPCh. 17.4 - Prob. 10FPCh. 17.4 - Prob. 11FPCh. 17.4 - Prob. 12FPCh. 17.4 - The 10-kg wheel has a radius of gyration kA = 200...Ch. 17.4 - The uniform 24-kg plate is released from rest at...Ch. 17.4 - The uniform slender rod has a mass m. If it is...Ch. 17.4 - The tent rod has a mass of 2 kg/m. If it is...Ch. 17.4 - If a horizontal force of P = 100 N is applied to...Ch. 17.4 - The 10-lb bar is pinned at its center O and...Ch. 17.4 - The 10-lb bar is pinned at its center O and...Ch. 17.4 - A cord is wrapped around the outer surface of the...Ch. 17.4 - Disk A has a weight of 5 lb and disk B has a...Ch. 17.4 - Prob. 66PCh. 17.4 - If the cord at B suddenly fails, determine the...Ch. 17.4 - Prob. 68PCh. 17.4 - The 20-kg roll of paper has a radius of gyration...Ch. 17.4 - The 20-kg roll of paper has a radius of gyration...Ch. 17.4 - The reel of cable has a mass of 400 kg and a...Ch. 17.4 - Prob. 72PCh. 17.4 - Cable is unwound from a spool supported on small...Ch. 17.4 - The 5-kg cylinder is initially at rest when it is...Ch. 17.4 - Prob. 75PCh. 17.4 - Prob. 76PCh. 17.4 - Disk D turns with a constant clockwise angular...Ch. 17.4 - Prob. 78PCh. 17.4 - Prob. 79PCh. 17.4 - Prob. 80PCh. 17.4 - Prob. 81PCh. 17.4 - Prob. 82PCh. 17.4 - Prob. 83PCh. 17.4 - Prob. 84PCh. 17.4 - Prob. 85PCh. 17.4 - Prob. 86PCh. 17.4 - Prob. 87PCh. 17.4 - The 100-kg pendulum has a center of mass at G and...Ch. 17.5 - The Catherine wheel is a firework that consists of...Ch. 17.5 - The uniform 60-kg slender bar is initially at rest...Ch. 17.5 - Prob. 14FPCh. 17.5 - Prob. 15FPCh. 17.5 - The 20- kg sphere rolls down the inclined plane...Ch. 17.5 - The 200-kg spool has a radius of gyration about...Ch. 17.5 - The 12-kg slender rod is pinned to a small roller...Ch. 17.5 - If the disk in Fig. 17-19 rolls without slipping,...Ch. 17.5 - The 20-kg punching bag has a radius of gyration...Ch. 17.5 - The uniform 150-lb beam is initially at rest when...Ch. 17.5 - The tire has a weight of 30 lb and a radius of...Ch. 17.5 - The tire has a weight of 30 lb and a radius of...Ch. 17.5 - The spool has a mass of 100 kg and a radius of...Ch. 17.5 - Solve Prob.17-96 if the cord and force P = 50 N...Ch. 17.5 - The spool has a mass of 100 kg and a radius of...Ch. 17.5 - The 12-kg uniform bar is supported by a roller at...Ch. 17.5 - A force of F= 10 N is applied to the 10-kg ring as...Ch. 17.5 - If the coefficient of static friction at C is s =...Ch. 17.5 - The 25-lb slender rod has a length of 6 ft. Using...Ch. 17.5 - The 15-lb circular plate is suspended from a pin...Ch. 17.5 - If P = 30 lb, determine the angular acceleration...Ch. 17.5 - If the coefficient of static friction between the...Ch. 17.5 - The uniform bar of mass m and length L is balanced...Ch. 17.5 - Solve Prob.17-106 if the roller is removed and the...Ch. 17.5 - The semicircular disk having a mass of 10 leg is...Ch. 17.5 - The 500-kg concrete culvert has a mean radius of...Ch. 17.5 - The 15-lb disk rests on the 5-lb plate. A cord is...Ch. 17.5 - The semicircular disk having a mass of 10 kg is...Ch. 17.5 - The circular concrete culvert rols with an angular...Ch. 17.5 - The uniform disk of mass m is rotating with an...Ch. 17.5 - The uniform disk of mass m is rotating with an...Ch. 17.5 - A cord is wrapped around each of the two 10-kg...Ch. 17.5 - The disk of mass m and radius r rolls without...Ch. 17.5 - The uniform beam has a weight W. If it is...Ch. 17.5 - The 500-lb beam is supported at A and B when it is...Ch. 17.5 - The solid ball of radius rand mass m rolls without...Ch. 17.5 - By pressing down with the finger at B, a thin ring...Ch. 17.5 - Prob. 1RPCh. 17.5 - Prob. 2RPCh. 17.5 - Prob. 3RPCh. 17.5 - Prob. 4RPCh. 17.5 - Prob. 5RPCh. 17.5 - Prob. 6RPCh. 17.5 - Prob. 7RPCh. 17.5 - Prob. 8RP
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- determine the direction and magnitude of angular velocity ω3 of link CD in the four-bar linkage using the relative velocity graphical methodarrow_forwardFour-bar linkage mechanism, AB=40mm, BC=60mm, CD=70mm, AD=80mm, =60°, w1=10rad/s. Determine the direction and magnitude of w3 using relative motion graphical method. A B 2 3 77777 477777arrow_forwardFour-bar linkage mechanism, AB=40mm, BC=60mm, CD=70mm, AD=80mm, =60°, w1=10rad/s. Determine the direction and magnitude of w3 using relative motion graphical method. A B 2 3 77777 477777arrow_forward
- The evaporator of a vapor compression refrigeration cycle utilizing R-123 as the refrigerant isbeing used to chill water. The evaporator is a shell and tube heat exchanger with the water flowingthrough the tubes. The water enters the heat exchanger at a temperature of 54°F. The approachtemperature difference of the evaporator is 3°R. The evaporating pressure of the refrigeration cycleis 4.8 psia and the condensing pressure is 75 psia. The refrigerant is flowing through the cycle witha flow rate of 18,000 lbm/hr. The R-123 leaves the evaporator as a saturated vapor and leaves thecondenser as a saturated liquid. Determine the following:a. The outlet temperature of the chilled waterb. The volumetric flow rate of the chilled water (gpm)c. The UA product of the evaporator (Btu/h-°F)d. The heat transfer rate between the refrigerant and the water (tons)arrow_forward(Read image) (Answer given)arrow_forwardProblem (17): water flowing in an open channel of a rectangular cross-section with width (b) transitions from a mild slope to a steep slope (i.e., from subcritical to supercritical flow) with normal water depths of (y₁) and (y2), respectively. Given the values of y₁ [m], y₂ [m], and b [m], calculate the discharge in the channel (Q) in [Lit/s]. Givens: y1 = 4.112 m y2 = 0.387 m b = 0.942 m Answers: ( 1 ) 1880.186 lit/s ( 2 ) 4042.945 lit/s ( 3 ) 2553.11 lit/s ( 4 ) 3130.448 lit/sarrow_forward
- Problem (14): A pump is being used to lift water from an underground tank through a pipe of diameter (d) at discharge (Q). The total head loss until the pump entrance can be calculated as (h₁ = K[V²/2g]), h where (V) is the flow velocity in the pipe. The elevation difference between the pump and tank surface is (h). Given the values of h [cm], d [cm], and K [-], calculate the maximum discharge Q [Lit/s] beyond which cavitation would take place at the pump entrance. Assume Turbulent flow conditions. Givens: h = 120.31 cm d = 14.455 cm K = 8.976 Q Answers: (1) 94.917 lit/s (2) 49.048 lit/s ( 3 ) 80.722 lit/s 68.588 lit/s 4arrow_forwardProblem (13): A pump is being used to lift water from the bottom tank to the top tank in a galvanized iron pipe at a discharge (Q). The length and diameter of the pipe section from the bottom tank to the pump are (L₁) and (d₁), respectively. The length and diameter of the pipe section from the pump to the top tank are (L2) and (d2), respectively. Given the values of Q [L/s], L₁ [m], d₁ [m], L₂ [m], d₂ [m], calculate total head loss due to friction (i.e., major loss) in the pipe (hmajor-loss) in [cm]. Givens: L₁,d₁ Pump L₂,d2 오 0.533 lit/s L1 = 6920.729 m d1 = 1.065 m L2 = 70.946 m d2 0.072 m Answers: (1) 3.069 cm (2) 3.914 cm ( 3 ) 2.519 cm ( 4 ) 1.855 cm TABLE 8.1 Equivalent Roughness for New Pipes Pipe Riveted steel Concrete Wood stave Cast iron Galvanized iron Equivalent Roughness, & Feet Millimeters 0.003-0.03 0.9-9.0 0.001-0.01 0.3-3.0 0.0006-0.003 0.18-0.9 0.00085 0.26 0.0005 0.15 0.045 0.000005 0.0015 0.0 (smooth) 0.0 (smooth) Commercial steel or wrought iron 0.00015 Drawn…arrow_forwardThe flow rate is 12.275 Liters/s and the diameter is 6.266 cm.arrow_forward
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