Explanation Given information: College town population of the citizens is as follows. District Population North 8 , 700 South 5 , 600 East 7 , 200 West 3 , 500 Each council member is to represent approximately 2 , 500 citizens. Number of representatives is 10 . Formula used: STANDARD QUOTA = TOTAL POPULATION STANDARD DIVISOR Use the following steps in HH’s plan. Step-1: Calculate the standard quota ( q ) using standard devisor for each state. Step-2: Find lower quota ( a ) and upper quota ( b ) . Step-3: Find geometric mean a b . Step-4: Round the standard quotas down; if the fractional part < a b and round up if fractional part is ≥ a b . Find the total of rounded numbers; the total will be correct or it will not. Step-5: If the total is not correct, lower or raise the standard divisor in small increments to find a modified divisor that will give modified quota that provide the appropriate total. Given number of representatives is 10 . Each council member is to represent approximately 2 , 500 citizens. So, the standard divisor is d = 2 , 500 . Divide the population of each state by standard divisor to find the standard quota for each state. S t a t e s Standard quota ( q ) Lower quota ( a ) Upper quota ( b ) Geometric Mean ( a b ) Rounded Value N o r t h 8 , 700 2 , 500 = 3

Nature of Mathematics (MindTap Course List)

13th Edition

ISBN: 9781133947257

Author: karl J. smith

Publisher: Cengage Learning

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Chapter 17.3, Problem 45PS

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HH’s apportionment plan assuming that there must be 10 representatives and each council member is to represent approximately 2,500 citizens for the following apportionment problem for College Town.

DistrictPopulationNorth8,700South5,600East7,200West3,500

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Chapter 17.3, Problem 44PS

Chapter 17.3, Problem 46PS

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Chapter 17 Solutions

Nature of Mathematics (MindTap Course List)

Ch. 17.1 - Prob. 1PS Ch. 17.1 - Prob. 2PS Ch. 17.1 - Prob. 3PS Ch. 17.1 - Prob. 4PS Ch. 17.1 - Prob. 5PS Ch. 17.1 - Prob. 6PS Ch. 17.1 - Prob. 7PS Ch. 17.1 - Prob. 8PS Ch. 17.1 - Prob. 9PS Ch. 17.1 - Prob. 10PS

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HH’s apportionment plan assuming that there must be 10 representatives and each council member is to represent approximately 2 , 500 citizens for the following apportionment problem for College Town. District Population North 8 , 700 South 5 , 600 East 7 , 200 West 3 , 500

Solution Summary: The author explains HH's apportionment plan assuming that there must be 10 representatives and each council member is to represent approximately 2,500 citizens.

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HH’s apportionment plan assuming that there must be 10 representatives and each council member is to represent approximately 2,500 citizens for the following apportionment problem for College Town.

DistrictPopulationNorth8,700South5,600East7,200West3,500

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Chapter 17 Solutions

HH’s apportionment plan assuming that there must be 10 representatives and each council member is to represent approximately 2 , 500 citizens for the following apportionment problem for College Town. District Population North 8 , 700 South 5 , 600 East 7 , 200 West 3 , 500

Solution Summary: The author explains HH's apportionment plan assuming that there must be 10 representatives and each council member is to represent approximately 2,500 citizens.

Concept explainers

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HH’s apportionment plan assuming that there must be 10 representatives and each council member is to represent approximately 2,500 citizens for the following apportionment problem for College Town. DistrictPopulationNorth8,700South5,600East7,200West3,500

Want to see the full answer?

Chapter 17 Solutions

HH’s apportionment plan assuming that there must be 10 representatives and each council member is to represent approximately 2,500 citizens for the following apportionment problem for College Town.

DistrictPopulationNorth8,700South5,600East7,200West3,500