Explanation Given information: College town population of the citizens is as follows. District Population North 8 , 700 South 5 , 600 East 7 , 200 West 3 , 500 Each council member is to represent approximately 2 , 500 citizens. Number of representatives is 10 . Formula used: STANDARD QUOTA = TOTAL POPULATION STANDARD DIVISOR In Jefferson’s plan, use the following steps: Step-1: Calculate the standard quota ( q ) using standard devisor ( d ) for each district Step-2: Round the standard quotas down to get lower quotas and these quotas together to find total number of representatives. It will be correct or it will be too small Step-3: If it will be small, lower the standard divisor in small increments to find a modified divisor that will give modified quotas that provide the appropriate total. Given number of representatives is 10 . Each council member is to represent approximately 2 , 500 citizens. So, the standard divisor is d = 2 , 500 . Divide the population of each district by standard divisor to find the standard quota for each district. States Standard quota ( q ) Lower quota North 8 , 700 2 , 500 = 3.48 3 South 5 , 600 2 , 500 = 2.24 2 East 7 , 200 2 , 500 = 2.88 2 West 3 , 500 2 , 500 = 1

Nature of Mathematics (MindTap Course List)

13th Edition

ISBN: 9781133947257

Author: karl J. smith

Publisher: Cengage Learning

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Chapter 17.3, Problem 42PS

To determine

Jefferson’s apportionment plan assuming that there must be 10 representatives and each council member is to represent approximately 2,500 citizens for the following apportionment problem for college town.

DistrictPopulationNorth8,700South5,600East7,200West3,500

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Chapter 17.3, Problem 41PS

Chapter 17.3, Problem 43PS

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Chapter 17 Solutions

Nature of Mathematics (MindTap Course List)

Ch. 17.1 - Prob. 1PS Ch. 17.1 - Prob. 2PS Ch. 17.1 - Prob. 3PS Ch. 17.1 - Prob. 4PS Ch. 17.1 - Prob. 5PS Ch. 17.1 - Prob. 6PS Ch. 17.1 - Prob. 7PS Ch. 17.1 - Prob. 8PS Ch. 17.1 - Prob. 9PS Ch. 17.1 - Prob. 10PS

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Jefferson’s apportionment plan assuming that there must be 10 representatives and each council member is to represent approximately 2 , 500 citizens for the following apportionment problem for college town. District Population North 8 , 700 South 5 , 600 East 7 , 200 West 3 , 500

Solution Summary: The author explains Jefferson's apportionment plan assuming that there must be 10 representatives and each council member is to represent approximately 2,500 citizens.

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Jefferson’s apportionment plan assuming that there must be 10 representatives and each council member is to represent approximately 2,500 citizens for the following apportionment problem for college town.

DistrictPopulationNorth8,700South5,600East7,200West3,500

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Chapter 17 Solutions

Jefferson’s apportionment plan assuming that there must be 10 representatives and each council member is to represent approximately 2 , 500 citizens for the following apportionment problem for college town. District Population North 8 , 700 South 5 , 600 East 7 , 200 West 3 , 500

Solution Summary: The author explains Jefferson's apportionment plan assuming that there must be 10 representatives and each council member is to represent approximately 2,500 citizens.

Concept explainers

Videos

Jefferson’s apportionment plan assuming that there must be 10 representatives and each council member is to represent approximately 2,500 citizens for the following apportionment problem for college town. DistrictPopulationNorth8,700South5,600East7,200West3,500

Want to see the full answer?

Chapter 17 Solutions

Jefferson’s apportionment plan assuming that there must be 10 representatives and each council member is to represent approximately 2,500 citizens for the following apportionment problem for college town.

DistrictPopulationNorth8,700South5,600East7,200West3,500