Explanation Given: Mass of cylinder is m b = 4 kg , mass of the wedge A is m a = 3 kg anddistance of cylinder s = 180 mm . Concept used: Expression for newton’s second law of motion in translation is given as follows: ∑ F n e t = m a …… (1) Here,net vertical force is ∑ F n e t and mass of walled pipe is m . Expression for newton’s second law of motion in rotation is given as follows: ∑ T n e t = I α …… (2) Here, net torque on the system is ∑ T n e t , mass moment of inertia is I and angular acceleration of the system is α . Calculation: Free body diagram for the cylinder is given as follows: Substitute m g sin θ − F for ∑ F n e t in equation (1). m g sin θ − F = m a Substitute F × r for ∑ T n e t in equation (1). F × r = I α F = m r 2 2 r α F = m a 2 To determine (b) The velocity of wedge.

12th Edition

ISBN: 9781259977305

Author: BEER, Ferdinand P. (ferdinand Pierre), Johnston, E. Russell (elwood Russell), Cornwell, Phillip J., SELF, Brian P.

Publisher: Mcgraw-hill Education,

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Chapter 17.2, Problem 17.94P

To determine

(a)

Angular velocity of cylinder.

To determine

(b)

The velocity of wedge.

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Chapter 17.2, Problem 17.93P

Chapter 17.2, Problem 17.95P

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(a) Angular velocity of cylinder.

Solution Summary: The author explains the angular velocity of cylinder, the mass of the wedge, and the expression for newton's second law of motion in translation.