Explanation Position 1: ν 1 = 0 ω 1 = 0 T 1 = 0 ν 2 = l 2 ω 2 Position 2: T 2 = Kinetic energy due to linear velocity ν 2 +Kinetic energy due to angular velocity ω 2 . T 2 = 1 2 m ν 2 2 + 1 2 I ω 2 2 Here, I = Moment of inertia of the rod = 1 12 m l 2 Put the value of ν 2 = l 2 ω 2 and moment of inertia I = 1 12 m l 2 in above equation, we get: T 2 = 1 2 m ( l 2 ω 2 ) 2 + 1 2 ( 1 12 m l 2 ) ω 2 2 ⇒ T 2 = 1 8 m l 2 ω 2 2 + 1 24 m l 2 ω 2 To determine (ii) The angular velocity of the rod as it passes through a vertical position and determine the corresponding reaction at the pivot for W=1.8lb and l= 3 ft.

Vector Mechanics for Engineers: Dynamics

11th Edition

ISBN: 9780077687342

Author: Ferdinand P. Beer, E. Russell Johnston Jr., Phillip J. Cornwell, Brian Self

Publisher: McGraw-Hill Education

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Chapter 17.1, Problem 17.16P

To determine

(i)

The angular velocity of the rod as it passes through a vertical position and determines the corresponding reaction at the pivot.

To determine

(ii)

The angular velocity of the rod as it passes through a vertical position and determine the corresponding reaction at the pivot for W=1.8lb and l= 3 ft.

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Chapter 17.1, Problem 17.15P

Chapter 17.1, Problem 17.17P

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(i) The angular velocity of the rod as it passes through a vertical position and determines the corresponding reaction at the pivot.

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