Explanation As per the above question15.0% by mass of NaOH solution It means 15.0 g of NaOH in 100 g of NaOH solution. So below formula will be used to calculate the volume of NaOH solution: - Volume of NaOH solution = mass of NaOH solution Density of Solution = 100 .0 g 1 .116 g/mL = 89 .6mL = 89 .6 × 1 L 1000 mL = 89 .6 × 10 − 3 L xs Now we have to calculate the number of mole of NaOH by the below formula: - Moles of NaOH = 15 .0 g × 1 mol NaOH 40 g NaOH = 0 .375 mol NaOH Below formula will be used to calculate the initial molarity: - M = Moles of NaOH Volume of solution M = 0 .375 mol NaOH 8 .96 × 10 -3 L = 4 .18 M As per the above question, we have to determine final Molarity M 2 . We know that pH + pOH = 14 10 ...

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ISBN: 9780321834683

Author: Nivaldo J. Tro

Publisher: PEARSON

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Chapter 17, Problem 88E

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To determine: volume of NaOH solution

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Chapter 17, Problem 87E

Chapter 17, Problem 89E

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