Consider a voltaic cell at 25°C in which the following reaction takes place. 3 H 2 O 2 ( a q ) + 6 H + ( a q ) + 2 Au ( s ) → 2 Au 3 + ( a q ) + 6 H 2 O (a) Calculate E °. (b) Write the Nernst equation for the cell. (c) Calculate E when [ Au 3 + ] = 0.250 M , [ H + ] = 1.25 M , [ H 2 O 2 ] = 1.50 M .
Consider a voltaic cell at 25°C in which the following reaction takes place. 3 H 2 O 2 ( a q ) + 6 H + ( a q ) + 2 Au ( s ) → 2 Au 3 + ( a q ) + 6 H 2 O (a) Calculate E °. (b) Write the Nernst equation for the cell. (c) Calculate E when [ Au 3 + ] = 0.250 M , [ H + ] = 1.25 M , [ H 2 O 2 ] = 1.50 M .
Solution Summary: The author explains that the value of E o for the given voltaic cell needs to be determined.
Consider a voltaic cell at 25°C in which the following reaction takes place.
3
H
2
O
2
(
a
q
)
+
6
H
+
(
a
q
)
+
2
Au
(
s
)
→
2
Au
3
+
(
a
q
)
+
6
H
2
O
(a) Calculate E°. (b) Write the Nernst equation for the cell. (c) Calculate E when
[
Au
3
+
]
=
0.250
M
,
[
H
+
]
=
1.25
M
,
[
H
2
O
2
]
=
1.50
M
.
13.84. Chlorine atoms react with methane, forming HCI
and CH3. The rate constant for the reaction is
6.0 × 107 M¹ s¹ at 298 K. When the experiment
was run at three other temperatures, the following data
were collected:
T (K)
k (M-1 s-1)
303
6.5 × 107
308
7.0 × 107
313
7.5 x 107
a. Calculate the values of the activation energy and the
frequency factor for the reaction.
b. What is the value of the rate constant in the lower
stratosphere, where T = 218 K?
My Organic Chemistry textbook says about the formation of cyclic hemiacetals, "Such intramolecular reactions to form five- and six-membered rings are faster than the corresponding intermolecular reactions. The two reacting functional groups, in this case OH and C=O, are held in close proximity, increasing the probability of reaction."According to the book, the formation of cyclic hemiacetals occurs in acidic conditions. So my question is whether the carbonyl group in this reaction reacts first with the end alcohol on the same molecule or with the ethylene glycol. And, given the explanation in the book, if it reacts first with ethylene glycol before its own end alcohol, why would it? I don't need to know the final answer. I need to know WHY it would not undergo an intermolecular reaction prior to reacting with the ethylene glycol if that is the case. Please do not use an AI answer.
Don't used hand raiting and don't used Ai solution
Chapter 17 Solutions
OWLv2 for Masterton/Hurley's Chemistry: Principles and Reactions, 8th Edition, [Instant Access], 1 term (6 months)
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