DeGarmo's Materials and Processes in Manufacturing
12th Edition
ISBN: 9781118987674
Author: J. T. Black, Ronald A. Kohser
Publisher: WILEY
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Chapter 17, Problem 62RQ
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The warm working.
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CORRECT AND DETAILED HANDWRITTEN SOLUTION WITH FBD ONLY. I WILL UPVOTE THANK YOU. CORRECT ANSWER IS ALREADY PROVIDED.
18: Determine the maximum shear and moment that would be experienced by a 10 m beam if a three-wheelmoving load of 10 kN, 30 kN, and 5 kN respectively will pass it by. The distance between the 1st and 2nd load is 1 m and the distance between the 2nd and 3rd load is 3 m.ANS: Vmax = 40 kN ; Mmax = 100.014 kN-m
CORRECT AND DETAILED HANDWRITTEN SOLUTION WITH FBD ONLY. I WILL UPVOTE THANK YOU. CORRECT ANSWER IS ALREADY PROVIDED.
5: A 12-m simply supported bridge is constructed with 100-mm concrete slab deck supported by precastconcrete stringers spaced 800 mm on center. Analyze the stringers when subjected to a moving load consisting of 3 evenly spaced axle loads at 3 m and equivalent to 20 kN, 30 kN and 40 kN respectively. The self-weight of the stringers is 8.5 kN/m and the concrete deck has a unit weight of 24 kN/m3 . Neglect all other superimposed loads. Calculate: (a) the maximum shear force in the stringers; (b) the maximum bending moment in the stringers.
Answer: Vmax = 135.020 KN, Mmax = 477.388 KN-M
CORRECT AND DETAILED HANDWRITTEN SOLUTION WITH FBD ONLY. I WILL UPVOTE THANK YOU. CORRECT ANSWER IS ALREADY PROVIDED.
19: A 22-wheeler truck is crossing over 25 m bridge. The dimensions between the axles of the truck are shownin the figure below. Axles 1 to 3 carry a 90 kN load each, axles 4 and 5 carry a 65 kN load each, and the axle directly below the cab of the truck has a load of 100 kN. Determine the maximum shear and moment on the bridge.ANS: Vmax = 374.92 kN ; Mmax = 1,702.229 kN-m
Chapter 17 Solutions
DeGarmo's Materials and Processes in Manufacturing
Ch. 17 - What is plasticity?Ch. 17 - What are some of the general assets of the...Ch. 17 - Why might large production quantities be necessary...Ch. 17 - What types of deformation may occur in forming...Ch. 17 - What is an independent variable in a...Ch. 17 - What are some considerations regarding selection...Ch. 17 - What is the significance of tool and die geometry...Ch. 17 - Why is lubrication often a major concern in metal...Ch. 17 - What are some of the secondary effects that may...Ch. 17 - Prob. 10RQ
Ch. 17 - Why is it important to be able to predict the...Ch. 17 - Prob. 12RQCh. 17 - Prob. 13RQCh. 17 - Prob. 14RQCh. 17 - Prob. 15RQCh. 17 - Prob. 16RQCh. 17 - Prob. 17RQCh. 17 - What are some of the features that may be...Ch. 17 - What features have contributed to the expanded use...Ch. 17 - What are some of the uses or applications of...Ch. 17 - Prob. 21RQCh. 17 - Prob. 22RQCh. 17 - Prob. 23RQCh. 17 - What type of information about the material being...Ch. 17 - Prob. 25RQCh. 17 - Why is friction such an important parameter in...Ch. 17 - Why are friction effects in metalworking difficult...Ch. 17 - Prob. 28RQCh. 17 - Prob. 29RQCh. 17 - Prob. 30RQCh. 17 - Prob. 31RQCh. 17 - Discuss the significance of wear in metal forming:...Ch. 17 - Lubricants are often selected for properties in...Ch. 17 - What is tribology?Ch. 17 - What are some of the common types of metal forming...Ch. 17 - What is hydrodynamic lubrication? What are some of...Ch. 17 - If the temperature of a material is increased,...Ch. 17 - Define the various regimes of cold working, warm...Ch. 17 - What is an acceptable definition of hot working?...Ch. 17 - What are some of the attractive manufacturing and...Ch. 17 - What are some of the negative aspects of hot...Ch. 17 - Prob. 42RQCh. 17 - Prob. 43RQCh. 17 - If the deformed grains recrystallize during hot...Ch. 17 - Why might a rolled thread offer improved strength...Ch. 17 - How might the temperature of a deforming workpiece...Ch. 17 - Why are heated dies or tools often employed in...Ch. 17 - What generally restricts the upper temperature to...Ch. 17 - What is the primary cause of residual stresses in...Ch. 17 - What is cold working?Ch. 17 - Compared to hot working, what are some of the...Ch. 17 - What are some of the disadvantages of...Ch. 17 - How could cold working be used to reduce the cost...Ch. 17 - Why are cold�forming processes best suited for...Ch. 17 - How can the tensile test properties of a metal be...Ch. 17 - Why is elastic springback an important...Ch. 17 - What is pickling, and how does it remove surface...Ch. 17 - Prob. 58RQCh. 17 - What engineering properties are likely to decline...Ch. 17 - Prob. 60RQCh. 17 - Prob. 61RQCh. 17 - Prob. 62RQCh. 17 - What are some of the advantages of warm forming...Ch. 17 - Prob. 64RQCh. 17 - What material feature is considered to be the...Ch. 17 - Why is isothermal forming considerably more...Ch. 17 - Prob. 67RQCh. 17 - Prob. 1PCh. 17 - Prob. 2PCh. 17 - List and discuss the various economic factors that...Ch. 17 - Prob. 4PCh. 17 - Prob. 5PCh. 17 - Prob. 6PCh. 17 - Prob. 1CSCh. 17 - Prob. 2CSCh. 17 - Which stainless steel would you recommend? Begin...Ch. 17 - Prob. 4CSCh. 17 - Prob. 5CSCh. 17 - After drawing and perforating, the residual...
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- CORRECT AND DETAILED HANDWRITTEN SOLUTION WITH FBD ONLY. I WILL UPVOTE THANK YOU. CORRECT ANSWER IS ALREADY PROVIDED. 1. A H = 6 m cantilever retaining wall is subjected to a soil pressurelinearly varying from zero at the top to 90 kPa at the bottom. As an additionalsupport, it is anchored at depth y = 2 m. with maximum tension equal to 25kN. Assume that the stem provides fully retrained support. Draw the shearand moment diagram of the wall to calculate the following: (a) Maximumpositive bending moment per linear meter; (b) maximum negative bendingmoment per linear meter; (c) maximum shear force per linear meter. answer: +MMax = 440 kn-m, -Mmax = 0kn-M, Vmax = 245 KNarrow_forwardCORRECT AND DETAILED HANDWRITTEN SOLUTION WITH FBD ONLY. I WILL UPVOTE THANK YOU. CORRECT ANSWER IS ALREADY PROVIDED. 17: A simply supported beam with the section shown below has an allowableflexural shearing stress of 43 MPa. (a) Determine the maximum allowable shearing force onthe section. And (b) what is the minimum thickness of plate that should be welded at theflanges if the section is to withstand a total shearing force of 200 kN. The additional plate willhave its base dimension equal to the flange dimension.ANS: V = 179.333 kN ; t = 23.181 mmarrow_forwardCORRECT AND DETAILED HANDWRITTEN SOLUTION WITH FBD ONLY. I WILL UPVOTE THANK YOU. CORRECT ANSWER IS ALREADY PROVIDED. Answer: A = 0.207 L(M)arrow_forward
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