ORGANIC CHEMISTRY-PRINT COMPANION (LL)
ORGANIC CHEMISTRY-PRINT COMPANION (LL)
4th Edition
ISBN: 9781119659594
Author: Klein
Publisher: WILEY
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Chapter 17, Problem 62IP
Interpretation Introduction

Interpretation: The structure of a given molecular formula C9H10O to be predicted using spectrum details.

Concept Introduction:

  • In the IR spectrum, the signal just above 3000 cm-1 confirms the presence of  aromatic ring
  • Aromatic compound also produces a series of signals between 1450 and 1650 cm-1 in the IR spectrum
  • In the 1HNMR spectrum, the signals between 6.5 and 8ppm confirms the aromatic ring. The presence of a multiplet near 7 ppm is one of the best way to verify the aromatic ring
  • 1HNMR : The 1HNMR spectrum gives information on the different electronic environment of protons. The number of signal (proton types)

    generated in 1HNMR are predicted by performing symmetry operations (rotation or reflection symmetry).

  • The 13CNMR spectrum gives information on the different electronic environments of carbon. As like 1HNMR , the number of signals generated in 13CNMR are predicted by performing symmetry operations (rotation or reflection symmetry). Only chemical shift values are reported in the spectrum but not the multiplicity and integration values because the coupling between two neighboring 13C13C nuclei are weakly involved due to the low abundance of 13C isotopes of carbon atom.
  • HDI Calculation:

            HDI=2(C)+2+N-H-X2whereCrepresentthenumberofcarbonNrepresentthenumberofnitrogenHrepresentthenumberofhydrogenXrepresentthenumberofhalogen.

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1,4-Dimethyl-1,3-cyclohexadiene can undergo 1,2- or 1,4-addition with hydrogen halides. (a) 1,2-Addition i. Draw the carbocation intermediate(s) formed during the 1,2-addition of hydrobromic acid to 1,4-dimethyl-1,3-cyclohexadiene. ii. What is the major 1,2-addition product formed during the reaction in (i)? (b) 1,4-Addition i. Draw the carbocation intermediate(s) formed during the 1,4-addition of hydrobromic acid to 1,4-dimethyl-1,3-cyclohexadiene. ii. What is the major 1,4-addition product formed from the reaction in (i)? (c) What is the kinetic product from the reaction of one mole of hydrobromic acid with 1,4-dimethyl-1,3-cyclohexadiene? Explain your reasoning. (d) What is the thermodynamic product from the reaction of one mole of hydrobro-mic acid with 1,4-dimethyl-1,3-cyclohexadiene? Explain your reasoning. (e) What major product will result when 1,4-dimethyl-1,3-cyclohexadiene is treated with one mole of hydrobromic acid at - 78 deg * C ? Explain your reasoning.
Give the product of the bimolecular elimination from each of the isomeric halogenated compounds. Reaction A Reaction B. КОВ CH₂ HotBu +B+ ко HOIBU +Br+ Templates More QQQ Select Cv Templates More Cras QQQ One of these compounds undergoes elimination 50x faster than the other. Which one and why? Reaction A because the conformation needed for elimination places the phenyl groups and to each other Reaction A because the conformation needed for elimination places the phenyl groups gauche to each other. ◇ Reaction B because the conformation needed for elimination places the phenyl groups gach to each other. Reaction B because the conformation needed for elimination places the phenyl groups anti to each other.
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