Electric Circuits, Student Value Edition Format: Unbound (saleable)
Electric Circuits, Student Value Edition Format: Unbound (saleable)
11th Edition
ISBN: 9780134747170
Author: NILSSON, James W.^riedel, Susan
Publisher: Prentice Hall
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Chapter 17, Problem 5P

(a)

To determine

Calculate the Fourier transform of the function f(t)=|t|ea|t|, where a is a positive real constant and t.

(b)

To determine

Calculate the Fourier transform of the function f(t)=t3ea|t|, where a is a positive real constant and t.

(c)

To determine

Calculate the Fourier transform of the function f(t)=ea|t|cosω0t, where a is a positive real constant and t.

(d)

To determine

Calculate the Fourier transform of the function f(t)=ea|t|sinω0t, where a is a positive real constant and t.

(e)

To determine

Calculate the Fourier transform of the function f(t)=Δ(tt0), where a is a positive real constant and t.

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2. Laboratory Preliminary Discussion First-order High-pass RC Filter Analysis The first-order high-pass RC filter shown in figure 3 below represents all voltages and currents in the time domain. We will again convert the circuit to its s-domain equivalent as shown in figure 4 and apply Laplace transform techniques. ic(t) C vs(t) i₁(t) + + vc(t) R1 ww Vi(t) || 12(t) V2(t) R₂ Vout(t) VR2(t) = V2(t) Figure 3: A first-order high-pass RC filter represented in the time domain. Ic(s) C + Vs(s) I₁(s) + + Vc(s) R₁ www V₁(s) 12(s) V₂(s) R₂ Vout(S) = VR2(S) = V2(s) Figure 4: A first-order high-pass RC filter represented in the s-domain. Again, to generate the s-domain expression for the output voltage, You (S) = V2 (s), for the circuit shown in figure 4 above, we can apply voltage division in the s-domain as shown in equation 2 below. Equation 2 will be used in the prelab computations to find an expression for the output voltage, xc(t), in the time domain. equation (2) R₂ Vout(s) = V₂(s) = R₂+…
Can you show me the steps to get the last part after the second equal sign.
Prelab Information 1. Laboratory Preliminary Discussion First-order Low-pass RC Filter Analysis The first-order low-pass RC filter shown in figure 1 below represents all voltages and currents in the time domain. It is of course possible to solve for all circuit voltages using time domain differential equation techniques, but it is more efficient to convert the circuit to its s-domain equivalent as shown in figure 2 and apply Laplace transform techniques. vs(t) i₁(t) + R₁ ww V₁(t) 12(t) Lic(t) Vout(t) = V2(t) R₂ Vc(t) C Vc(t) VR2(t) = V2(t) + Vs(s) Figure 1: A first-order low-pass RC filter represented in the time domain. I₁(s) R1 W + V₁(s) V₂(s) 12(s) Ic(s) + Vout(S) == Vc(s) Vc(s) Zc(s) = = VR2(S) V2(s) Figure 2: A first-order low-pass RC filter represented in the s-domain.
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