Physics
7th Edition
ISBN: 9780321733627
Author: Douglas C. Giancoli
Publisher: PEARSON
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Textbook Question
Chapter 17, Problem 4P
How much kinetic energy will an electron gain (in joules and eV) if it accelerates through a potential difference of 18,500 V?
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Chapter 17 Solutions
Physics
Ch. 17 - Prob. 1OQCh. 17 - Prob. 1QCh. 17 - If a negative charge is initially at rest in an...Ch. 17 - State clearly the difference (a) between electric...Ch. 17 - An electron is accelerated from rest by a...Ch. 17 - Is there a point along the line joining two equal...Ch. 17 - Prob. 6QCh. 17 - Prob. 7QCh. 17 - Can two equipotential lines cross? ExplainCh. 17 - Prob. 9Q
Ch. 17 - When a battery is connected to a capacitor, why do...Ch. 17 - Prob. 11QCh. 17 - The parallel plates of an isolated capacitor carry...Ch. 17 - Prob. 13QCh. 17 - Prob. 14QCh. 17 - Prob. 15QCh. 17 - Prob. 16QCh. 17 - Prob. 17QCh. 17 - Prob. 18QCh. 17 - Prob. 1MCQCh. 17 - Two identical positive charges are placed near...Ch. 17 - Four identical point charges are arranged at the...Ch. 17 - Prob. 4MCQCh. 17 - Prob. 5MCQCh. 17 - Prob. 6MCQCh. 17 - Prob. 7MCQCh. 17 - Prob. 8MCQCh. 17 - Prob. 9MCQCh. 17 - Prob. 10MCQCh. 17 - Prob. 11MCQCh. 17 - How much work does the electric field do in moving...Ch. 17 - How much work does the electric field do in moving...Ch. 17 - What potential difference is needed to stop an...Ch. 17 - How much kinetic energy will an electron gain (in...Ch. 17 - An electron acquires 6.4510-16 J of kinetic energy...Ch. 17 - How strong is the electric field between two...Ch. 17 - An electric field of 525 V/m is desired between...Ch. 17 - The electric field between two parallel plates...Ch. 17 - What potential difference is needed to give a...Ch. 17 - Two parallel plates, connected to a 45-V power...Ch. 17 - The work done by an external force to move a -6.50...Ch. 17 - What is the speed of an electron with kinetic...Ch. 17 - Prob. 13PCh. 17 - Prob. 14PCh. 17 - An electric field greater than about 3 x 106 V/m...Ch. 17 - 16. (II) An electron starting from rest acquires...Ch. 17 - Prob. 17PCh. 17 - Prob. 18PCh. 17 - Prob. 19PCh. 17 - Prob. 20PCh. 17 - (a) What is the electric potential 2.51015m away...Ch. 17 - Prob. 22PCh. 17 - Prob. 23PCh. 17 - Prob. 24PCh. 17 - Prob. 25PCh. 17 - How much work must be done to bring three...Ch. 17 - Prob. 27PCh. 17 - Prob. 28PCh. 17 - Prob. 29PCh. 17 - Prob. 30PCh. 17 - Prob. 31PCh. 17 - Prob. 32PCh. 17 - Calculate the electric potential due to a dipole...Ch. 17 - The dipole moment, considered as a vector, points...Ch. 17 - Prob. 35PCh. 17 - Prob. 36PCh. 17 - Prob. 37PCh. 17 - Prob. 38PCh. 17 - The charge on a capacitor increases by 15 C when...Ch. 17 - Prob. 40PCh. 17 - If a capacitor has opposite 4.2 µC charges on the...Ch. 17 - Prob. 42PCh. 17 - Prob. 43PCh. 17 - Prob. 44PCh. 17 - Prob. 45PCh. 17 - Prob. 46PCh. 17 - Prob. 47PCh. 17 - What is the capacitance of a pair of circular...Ch. 17 - Prob. 49PCh. 17 - Prob. 50PCh. 17 - Prob. 51PCh. 17 - Prob. 52PCh. 17 - Prob. 53PCh. 17 - Prob. 54PCh. 17 - A homemade capacitor is assembled by placing two...Ch. 17 - Prob. 56PCh. 17 - Prob. 57PCh. 17 - Prob. 58PCh. 17 - Prob. 59PCh. 17 - Prob. 60PCh. 17 - Write the binary number 1010101010101010 as a...Ch. 17 - Prob. 62PCh. 17 - Prob. 63PCh. 17 - Prob. 64PCh. 17 - Prob. 65PCh. 17 - Prob. 66PCh. 17 - Prob. 67PCh. 17 - Prob. 68GPCh. 17 - Prob. 69GPCh. 17 - Prob. 70GPCh. 17 - Prob. 71GPCh. 17 - Prob. 72GPCh. 17 - Prob. 73GPCh. 17 - Dry air will break down if theelectric field...Ch. 17 - Prob. 75GPCh. 17 - Prob. 76GPCh. 17 - Prob. 77GPCh. 17 - Prob. 78GPCh. 17 - Prob. 79GPCh. 17 - Prob. 80GPCh. 17 - Prob. 81GPCh. 17 - Prob. 82GPCh. 17 - Prob. 83GPCh. 17 - Prob. 84GPCh. 17 - Prob. 85GPCh. 17 - Prob. 86GPCh. 17 - Prob. 87GPCh. 17 - Prob. 88GPCh. 17 - Prob. 89GPCh. 17 - Prob. 90GPCh. 17 - Prob. 91GPCh. 17 - Prob. 92GPCh. 17 - Prob. 93GPCh. 17 - In the dynamic random access memory (DRAM)of a...Ch. 17 - Prob. 95GPCh. 17 - Prob. 96GP
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- Calculate the speed of an electron (in m/s) after it accelerates from rest through a potential difference of 140 V. 7.02e25 m/s The speed of the electron v can be found using the kinetic energy equation, K = 1/2(mv^2). The change in kinetic energy is equal to the work done on the electron, K = W = -U = -qV. Using those two equations, solve for the speed v in terms of the potential V and constants. Remember that the mass of an electron is 9.1e-31 kg and its charge is 1.6e-19 C. Submit Answer Incorrect. Tries 1/2 Previous Triesarrow_forwardAn amount of charge at an electric potential of 25 volts has 150 Joules of electric potential energy. How much charge is at this electric potential?arrow_forwardAn electron in an x-ray machine is accelerated through a potential difference of 1.0 × 104 V before it hits the target. What is the kinetic energy of the electron in electron volts?arrow_forward
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