The solution of the given inequality, − 1 ≤ − x − 4 < 7 , and graph the solution set. The solution set of the given inequality, − 1 ≤ − x − 4 < 7 , is − 3 < x ≤ 5 . Calculation: Consider the given inequality, − 1 ≤ − x − 4 < 7 . Multiply each part by − 1 by using the multiplicative property of an inequality, according to which, if c > 0 , then a < b becomes a c < b c and if c < 0 , then a > b becomes a c < b c . 1 ≥ x − 4 > − 7 Add 4 from each part by using the property of addition of a constant to an inequality, according to which, if a < b , then a < b becomes a + c < b + c . 5 ≥ x > − 3 − 3 < x ≤ 5 The solution set of the given inequality is the set of all real numbers that are greater than − 3 and less than or equal to 5 which can be denoted by − 3 , 5 . Graph: The solution set of the inequality is shown in the graph. The parenthesis at x = − 3 means that this point is not included in the solution set. The bracket at x = 5 means that this point is included in the solution set.
The solution of the given inequality, − 1 ≤ − x − 4 < 7 , and graph the solution set. The solution set of the given inequality, − 1 ≤ − x − 4 < 7 , is − 3 < x ≤ 5 . Calculation: Consider the given inequality, − 1 ≤ − x − 4 < 7 . Multiply each part by − 1 by using the multiplicative property of an inequality, according to which, if c > 0 , then a < b becomes a c < b c and if c < 0 , then a > b becomes a c < b c . 1 ≥ x − 4 > − 7 Add 4 from each part by using the property of addition of a constant to an inequality, according to which, if a < b , then a < b becomes a + c < b + c . 5 ≥ x > − 3 − 3 < x ≤ 5 The solution set of the given inequality is the set of all real numbers that are greater than − 3 and less than or equal to 5 which can be denoted by − 3 , 5 . Graph: The solution set of the inequality is shown in the graph. The parenthesis at x = − 3 means that this point is not included in the solution set. The bracket at x = 5 means that this point is included in the solution set.
Solution Summary: The author calculates the solution set of the given inequality, -1le -(x-4)7, and graphs it.
To calculate: The solution of the given inequality, −1≤−x−4<7, and graph the solution set.
The solution set of the given inequality, −1≤−x−4<7, is −3<x≤5.
Calculation:
Consider the given inequality, −1≤−x−4<7.
Multiply each part by −1 by using the multiplicative property of an inequality, according to which, if c>0, then a<b becomes ac<bc and if c<0, then a>b becomes ac<bc.
1≥x−4>−7
Add 4 from each part by using the property of addition of a constant to an inequality, according to which, if a<b, then a<b becomes a+c<b+c.
5≥x>−3−3<x≤5
The solution set of the given inequality is the set of all real numbers that are greater than −3 and less than or equal to 5 which can be denoted by −3,5.
Graph:
The solution set of the inequality is shown in the graph.
The parenthesis at x=−3 means that this point is not included in the solution set.
The bracket at x=5 means that this point is included in the solution set.
I want to learn this topic l dont know anything about it
Solve the linear system of equations attached using Gaussian elimination (not Gauss-Jordan) and back subsitution.
Remember that:
A matrix is in row echelon form if
Any row that consists only of zeros is at the bottom of the matrix.
The first non-zero entry in each other row is 1. This entry is called aleading 1.
The leading 1 of each row, after the first row, lies to the right of the leading 1 of the previous row.
PRIMERA EVALUACIÓN SUMATIVA
10. Determina la medida de los ángulos in-
teriores coloreados en cada poligono.
⚫ Octágono regular
A
11. Calcula es número de lados qu
poligono regular, si la medida
quiera de sus ángulos internos
• a=156°
A= (-2x+80
2
156 180-
360
0 = 24-360
360=24°
• a = 162°
1620-180-360
6=18-360
360=19
2=360=
18
12. Calcula las medida
ternos del cuadrilá
B
X+5
x+10
A
X+X+
Sx+6
5x=3
x=30
0
лаб
• Cuadrilátero
120°
110°
• α = 166° 40'
200=180-360
0 =
26-360
360=20
ひ=360
20
18 J
60°
⚫a=169° 42' 51.43"
169.4143180-340
0 = 10.29 54-360
360 10.2857
2=360
10.2857
@Sa
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