EP PRE-ALGEBRA,COMMON CORE-1 YEAR CODE

12th Edition

ISBN: 9780547615011

Author: Larson

Publisher: HM HS

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Question

Chapter 1.7, Problem 28E

To determine

To find : The mean of the positions.

Expert Solution

Answer to Problem 28E

The mean of the positions is −49 meters.

Explanation of Solution

Given information :

The positions of the five free dives from the graph are −46,−40,−48,−51,−60

Calculation :

The mean of the position is the sum of the values of position divided by the number of values. Therefore,

Mean=−46+(−40)+(−48)+(−51)+(−60)5Mean=−2455Mean=−49 m

Thus, the mean of the position is −49 meters.

To determine

To find : The median of the positions.

Expert Solution

Answer to Problem 28E

The median of the positions is −48 meters.

Explanation of Solution

Given information :

The positions of the five free dives from the graph are −46,−40,−48,−51,−60

Calculation :

The median of the position is the middle value of positions when the positions are written in numerical order.

First, arrange the position in order from least to greatest. Therefore,

−60,−51,−48,−46,−40

Since, the number of position is five (i. e. odd), so the median is middle most value (i.e. third value).

Therefore,

Median=−48 m

Thus, the median of the position is −48 meters.

To determine

To compare : Does the mean or the median represent a lower position?

Expert Solution

Answer to Problem 28E

The median represents the lower position.

Explanation of Solution

From part (a) and (b) it can be observed that median is smaller than mean. Therefore, median represents the lower position.

Thus, the median represents the lower position.

Chapter 1.7, Problem 27E

Chapter 1.7, Problem 29E

Chapter 1 Solutions

EP PRE-ALGEBRA,COMMON CORE-1 YEAR CODE

Ch. 1.1 - Prob. 1C Ch. 1.1 - Prob. 2C Ch. 1.1 - Prob. 3C Ch. 1.1 - Prob. 4C Ch. 1.1 - Prob. 1E Ch. 1.1 - Prob. 2E Ch. 1.1 - Prob. 3E Ch. 1.1 - Prob. 4E Ch. 1.1 - Prob. 5E Ch. 1.1 - Prob. 6E

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