Organic Chemistry (6th Edition)
6th Edition
ISBN: 9781260119107
Author: Janice Gorzynski Smith
Publisher: McGraw Hill Education
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Chapter 1.7, Problem 20P
Using the principles of VSEPR theory, you can predict the geometry around any atom in any molecule, no matter how complex. Enanthotoxin is a poisonous compound isolated from a common variety of hemlock grown in England. Predict the geometry around the highlighted atoms in enanthotoxin.
Enanthotoxin
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Students have asked these similar questions
Using the principles of VSEPR theory, you can predict the geometry or electron arrangement around any atom in any molecule, no matter how complex. Predict
the electron arrangement geometry around the indicated atoms in the structure shown.
a
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Part 1 of 2
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Atom a: (Choose one)
linear
trigonal planar
tetrahedral
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Which of the following explains the VSEPR geometry of an ammonia molecule?
It is trigonal pyramidal because there are four bonded pairs around nitrogen.
It is tetrahedral because there are four bonded pairs around nitrogen.
It is trigonal pyramidal because there are three bonded pairs and one lone pair around nitrogen.
It is tetrahedral because there are three bonded pairs and one lone pair around nitrogen.
Group X elements can conduct electricity and heat. As a chemistry student, Explain the characteristics of Group X elements. Explain the chemical properties of Group X elements . Discuss the trends of Group X elements when going down the group
Using the knowledge of Lewis Diagram, show the formation of bond from any ONE of the element from Group X and any ONE non-metal element.
State the electronic configuration of the cation and anion from the bond formed above.
Draw the orbital diagram of the carbon and anion from thw bond formed above.
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Rubric: Part A; Choose your rubric based on the Bloom's.
Part B; Assess originality.
Chapter 1 Solutions
Organic Chemistry (6th Edition)
Ch. 1.1 - While the most common isotope of nitrogen has a...Ch. 1.2 - Label each bond in the following compounds as...Ch. 1.3 - Draw a valid Lewis structure for each species. a....Ch. 1.3 - Prob. 9PCh. 1.4 - Draw Lewis structures for each molecular formula....Ch. 1.6 - Classify each pair of compounds as isomers or...Ch. 1.6 - Prob. 12PCh. 1.6 - Prob. 13PCh. 1.6 - Prob. 14PCh. 1.6 - Prob. 16P
Ch. 1.6 - Prob. 17PCh. 1.7 - Prob. 18PCh. 1.7 - Prob. 19PCh. 1.7 - Using the principles of VSEPR theory, you can...Ch. 1.8 - Convert each condensed formula to a Lewis...Ch. 1.8 - Prob. 22PCh. 1.8 - Prob. 23PCh. 1.8 - Convert each skeletal structure to a complete...Ch. 1 - Citric acid is responsible for the tartness of...Ch. 1 - Zingerone gives ginger its pungent taste. a.What...Ch. 1 - Assign formal charges to each and atom in the...Ch. 1 - Prob. 44PCh. 1 - Prob. 46PCh. 1 - Draw all possible isomers for each molecular...Ch. 1 - 1.45 Draw Lewis structures for the nine isomers...Ch. 1 - Prob. 52PCh. 1 - Prob. 53PCh. 1 - Prob. 54PCh. 1 - Consider compounds A-D, which contain both a...Ch. 1 - Draw in all the carbon and hydrogen atoms in each...Ch. 1 - 1.61 Convert each molecule into a skeletal...Ch. 1 - Prob. 65PCh. 1 - Predict the hybridization and geometry around each...Ch. 1 - Prob. 68PCh. 1 - Ketene, , is an unusual organic molecule that has...Ch. 1 - Rank the following bonds in order of increasing...Ch. 1 - Two useful organic compounds that contain Cl atoms...Ch. 1 - Use the symbols + and to indicate the polarity of...Ch. 1 - Prob. 74PCh. 1 - Anacin is an over-the-counter pain reliever that...Ch. 1 - 1.77 Stalevo is the trade name for a medication...Ch. 1 - 1.78 and are two highly reactive carbon...Ch. 1 - 1.79 The N atom in (acetamide) is hybridized,...Ch. 1 - Prob. 83PCh. 1 - Prob. 84PCh. 1 - Prob. 85PCh. 1 - Prob. 86PCh. 1 - Prob. 87PCh. 1 - Prob. 88P
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- Methylcyanoacrylate is the active ingredient in super glues. Its Lewis structure is (a) Give values for the three bond angles indicated. (b) Indicate the most polar bond in the molecule. (c) Circle the shortest carbon-oxygen bond. (d) Circle the shortest carbon-carbon bond.arrow_forwardPredict the ideal bond angles around each central atom in this molecule. PH oxygen: carbon: نیٹ H H H H O Oarrow_forwardPredicting the arrangement of electron groups around the central atom of a molecule.arrow_forward
- How does adding an atom affect the position and angles of existing atoms or lone pairs? How does adding a lone pair affect the position and angles of existing atoms and lone pairs? Is the effect of adding bonded atoms and lone pairs to the central similar? Explain your answer. Describe what is meant by the "Steric #". Explain the difference between the terms "Electron Geometry" and "Molecule Geometry". How does changing a bond to a double or triple bond affect the shape of the molecules? List the molecules in Part III where the real bond angles differ from the theoretical model values. Why do you think the values differ?arrow_forwardDraw the 2D and the 3D Lewis structure for each molecule. You do not need to show resonance structures here. Determine the electron pair geometry (EPG), the molecular geometry (MG), the bond angle (BA) around the central atom, and the hybridization of the central or bold atom. Circle the formula of any polar molecule. For molecules with more than one central atom (e.g. CH3CH20H) give the structure around the bold atom. Molecule ЕPG Hyb (circle if 2D Lewis Structure 3D Lewis Structure MG polar) ВА CH2S GeO2 CF4arrow_forwardDepending on the protein under study, the bond angle of a drug molecule can become critical to successfully deactivating a viral protein. For this reason, chemists are frequently concerned with the 3D shape of their molecules and their bond angles. The oxygen atom shown in the structure has a tetrahedral electronic geometry, meaning we would predict that it would have 109.5° bond angles. However, the actual structure, the bond angles are smaller than 109.5°. Explain why this compression occurs. Make sure to discuss what’s happening around/what groups are present around the oxygen atom.arrow_forward
- Mark the correct statements related to the bonding, shape and polarity of molecules. A - Only valence electrons are used when Lewis structures are drawn. B - Valence electrons occupying pi bonding orbitals are not considered when determining the molecular shape with the VSEPR theory C- The lone pairs on the central atom does not influence the molecular shape of a molecule. D- Molecules with polar bonds are polar. E - Molecules with a tetrahedral electron pair geometry are non-polar.arrow_forwardIn addition to the items required for part A, divide the naming of the geometry into a name for the arrangement about each atom that can be considered central to two or more it is bound to. Make only one overall ball-and-stick sketch and judge overall polarity. Fill in the blanks here!arrow_forwardName Section Table 1: Complete this table with your partner. You may ask the instructor to check your work. Formula Lewis structure Molecular geometry and bond angle(s) around central atoms(s) Polar or nonpolar, draw dipole arrow Hybridization of each atom Orbitals involved in each bond CO2 2 x C=O: sp- sp o o=c=o° C: sp O: sp Linear, 180° Non-polar 2 x C=O: p-p TC COF2 CH2CH2 SCI2 SF4 atoms. atomarrow_forward
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