How is the air pressure in a tightly sealed house affected by operating the furnace? Explain.

Question

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Answer 1

Textbook Question

Chapter 17, Problem 1CQ

How is the air pressure in a tightly sealed house affected by operating the furnace? Explain.

Expert Solution & Answer

To determine

The reason due to which the air pressure in a tightly sealed house affected by operating the furnace.

Answer to Problem 1CQ

The air pressure increases in the tightly sealed house by operating the furnace due to the increase in the temperature.

Explanation of Solution

Write the expression for ideal gas equation.

PV=nRT

Here,

n is the number of moles.

R is the ideal gas constant.

T is the temperature in Kelvin.

V is the volume.

P is the pressure.

Since the furnace is operated in the tightly sealed house due to which the temperature in the tightly sealed house is increased and the volume is constant

From ideal gas equation, it is seen that the pressure is directly proportional to the temperature.

P∝T

So the air pressure is increased in the tightly sealed house.

Conclusion:

Therefore, the air pressure increases in the tightly sealed house by operating the furnace due to the increase in the temperature.

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Answer 2

Textbook Question

Chapter 17, Problem 1CQ

How is the air pressure in a tightly sealed house affected by operating the furnace? Explain.

Expert Solution & Answer

To determine

The reason due to which the air pressure in a tightly sealed house affected by operating the furnace.

Answer to Problem 1CQ

The air pressure increases in the tightly sealed house by operating the furnace due to the increase in the temperature.

Explanation of Solution

Write the expression for ideal gas equation.

PV=nRT

Here,

n is the number of moles.

R is the ideal gas constant.

T is the temperature in Kelvin.

V is the volume.

P is the pressure.

Since the furnace is operated in the tightly sealed house due to which the temperature in the tightly sealed house is increased and the volume is constant

From ideal gas equation, it is seen that the pressure is directly proportional to the temperature.

P∝T

So the air pressure is increased in the tightly sealed house.

Conclusion:

Therefore, the air pressure increases in the tightly sealed house by operating the furnace due to the increase in the temperature.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Textbook Question

Chapter 17, Problem 1CQ

How is the air pressure in a tightly sealed house affected by operating the furnace? Explain.

Expert Solution & Answer

To determine

The reason due to which the air pressure in a tightly sealed house affected by operating the furnace.

Answer to Problem 1CQ

The air pressure increases in the tightly sealed house by operating the furnace due to the increase in the temperature.

Explanation of Solution

Write the expression for ideal gas equation.

PV=nRT

Here,

n is the number of moles.

R is the ideal gas constant.

T is the temperature in Kelvin.

V is the volume.

P is the pressure.

Since the furnace is operated in the tightly sealed house due to which the temperature in the tightly sealed house is increased and the volume is constant

From ideal gas equation, it is seen that the pressure is directly proportional to the temperature.

P∝T

So the air pressure is increased in the tightly sealed house.

Conclusion:

Therefore, the air pressure increases in the tightly sealed house by operating the furnace due to the increase in the temperature.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Textbook Question

Chapter 17, Problem 1CQ

How is the air pressure in a tightly sealed house affected by operating the furnace? Explain.

Expert Solution & Answer

To determine

The reason due to which the air pressure in a tightly sealed house affected by operating the furnace.

Answer to Problem 1CQ

The air pressure increases in the tightly sealed house by operating the furnace due to the increase in the temperature.

Explanation of Solution

Write the expression for ideal gas equation.

PV=nRT

Here,

n is the number of moles.

R is the ideal gas constant.

T is the temperature in Kelvin.

V is the volume.

P is the pressure.

Since the furnace is operated in the tightly sealed house due to which the temperature in the tightly sealed house is increased and the volume is constant

From ideal gas equation, it is seen that the pressure is directly proportional to the temperature.

P∝T

So the air pressure is increased in the tightly sealed house.

Conclusion:

Therefore, the air pressure increases in the tightly sealed house by operating the furnace due to the increase in the temperature.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution & Answer

To determine

The reason due to which the air pressure in a tightly sealed house affected by operating the furnace.

Answer to Problem 1CQ

The air pressure increases in the tightly sealed house by operating the furnace due to the increase in the temperature.

Explanation of Solution

Write the expression for ideal gas equation.

PV=nRT

Here,

n is the number of moles.

R is the ideal gas constant.

T is the temperature in Kelvin.

V is the volume.

P is the pressure.

Since the furnace is operated in the tightly sealed house due to which the temperature in the tightly sealed house is increased and the volume is constant

From ideal gas equation, it is seen that the pressure is directly proportional to the temperature.

P∝T

So the air pressure is increased in the tightly sealed house.

Conclusion:

Therefore, the air pressure increases in the tightly sealed house by operating the furnace due to the increase in the temperature.

Answer 8

Expert Solution & Answer

To determine

The reason due to which the air pressure in a tightly sealed house affected by operating the furnace.

Answer to Problem 1CQ

The air pressure increases in the tightly sealed house by operating the furnace due to the increase in the temperature.

Explanation of Solution

Write the expression for ideal gas equation.

PV=nRT

Here,

n is the number of moles.

R is the ideal gas constant.

T is the temperature in Kelvin.

V is the volume.

P is the pressure.

Since the furnace is operated in the tightly sealed house due to which the temperature in the tightly sealed house is increased and the volume is constant

From ideal gas equation, it is seen that the pressure is directly proportional to the temperature.

P∝T

So the air pressure is increased in the tightly sealed house.

Conclusion:

Therefore, the air pressure increases in the tightly sealed house by operating the furnace due to the increase in the temperature.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

To determine

The reason due to which the air pressure in a tightly sealed house affected by operating the furnace.

Answer 12

Answer to Problem 1CQ

The air pressure increases in the tightly sealed house by operating the furnace due to the increase in the temperature.

Answer 13

Explanation of Solution

Write the expression for ideal gas equation.

PV=nRT

Here,

n is the number of moles.

R is the ideal gas constant.

T is the temperature in Kelvin.

V is the volume.

P is the pressure.

Since the furnace is operated in the tightly sealed house due to which the temperature in the tightly sealed house is increased and the volume is constant

From ideal gas equation, it is seen that the pressure is directly proportional to the temperature.

P∝T

So the air pressure is increased in the tightly sealed house.

Conclusion:

Therefore, the air pressure increases in the tightly sealed house by operating the furnace due to the increase in the temperature.