(a) Interpretation: The redox reaction , Br 2 ( l ) + NaI ( a q ) → NaBr ( a q ) + I 2 ( s ) is to be balanced with the help of oxidation number method. Concept introduction: In order to balance the redox reaction , the oxidation number of each element of both reactant and product side is first found out. Then the charge is balanced. If the charge is already balanced then that equation is balanced. If it is not the case, then multiply it by suitable coefficient in order to balance the equation.

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Answer 1

Question

Chapter 17, Problem 19E

Interpretation Introduction

(a)

Interpretation:

The redox reaction, Br2(l)+NaI(aq)→NaBr(aq)+I2(s) is to be balanced with the help of oxidation number method.

Concept introduction:

In order to balance the redox reaction, the oxidation number of each element of both reactant and product side is first found out. Then the charge is balanced. If the charge is already balanced then that equation is balanced. If it is not the case, then multiply it by suitable coefficient in order to balance the equation.

Interpretation Introduction

(b)

Interpretation:

The redox reaction, PbS(s)+O2(g)→PbO(aq)+SO2(g) is to be balanced with the help of oxidation number method.

Concept introduction:

In order to balance the redox reaction, the oxidation number of each element of both reactant and product side is first found out. Then the charge is balanced. If the charge is already balanced then that equation is balanced. If it is not the case, then multiply it by suitable coefficient in order to balance the equation.

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Answer 2

Question

Chapter 17, Problem 19E

Interpretation Introduction

(a)

Interpretation:

The redox reaction, Br2(l)+NaI(aq)→NaBr(aq)+I2(s) is to be balanced with the help of oxidation number method.

Concept introduction:

In order to balance the redox reaction, the oxidation number of each element of both reactant and product side is first found out. Then the charge is balanced. If the charge is already balanced then that equation is balanced. If it is not the case, then multiply it by suitable coefficient in order to balance the equation.

Interpretation Introduction

(b)

Interpretation:

The redox reaction, PbS(s)+O2(g)→PbO(aq)+SO2(g) is to be balanced with the help of oxidation number method.

Concept introduction:

In order to balance the redox reaction, the oxidation number of each element of both reactant and product side is first found out. Then the charge is balanced. If the charge is already balanced then that equation is balanced. If it is not the case, then multiply it by suitable coefficient in order to balance the equation.

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Answer 3

Question

Chapter 17, Problem 19E

Interpretation Introduction

(a)

Interpretation:

The redox reaction, Br2(l)+NaI(aq)→NaBr(aq)+I2(s) is to be balanced with the help of oxidation number method.

Concept introduction:

In order to balance the redox reaction, the oxidation number of each element of both reactant and product side is first found out. Then the charge is balanced. If the charge is already balanced then that equation is balanced. If it is not the case, then multiply it by suitable coefficient in order to balance the equation.

Interpretation Introduction

(b)

Interpretation:

The redox reaction, PbS(s)+O2(g)→PbO(aq)+SO2(g) is to be balanced with the help of oxidation number method.

Concept introduction:

In order to balance the redox reaction, the oxidation number of each element of both reactant and product side is first found out. Then the charge is balanced. If the charge is already balanced then that equation is balanced. If it is not the case, then multiply it by suitable coefficient in order to balance the equation.

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Answer 4

Question

Chapter 17, Problem 19E

Interpretation Introduction

(a)

Interpretation:

The redox reaction, Br2(l)+NaI(aq)→NaBr(aq)+I2(s) is to be balanced with the help of oxidation number method.

Concept introduction:

In order to balance the redox reaction, the oxidation number of each element of both reactant and product side is first found out. Then the charge is balanced. If the charge is already balanced then that equation is balanced. If it is not the case, then multiply it by suitable coefficient in order to balance the equation.

Interpretation Introduction

(b)

Interpretation:

The redox reaction, PbS(s)+O2(g)→PbO(aq)+SO2(g) is to be balanced with the help of oxidation number method.

Concept introduction:

In order to balance the redox reaction, the oxidation number of each element of both reactant and product side is first found out. Then the charge is balanced. If the charge is already balanced then that equation is balanced. If it is not the case, then multiply it by suitable coefficient in order to balance the equation.

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Answer 5

Chapter 17, Problem 19E

Interpretation Introduction

(a)

Interpretation:

The redox reaction, Br2(l)+NaI(aq)→NaBr(aq)+I2(s) is to be balanced with the help of oxidation number method.

Concept introduction:

In order to balance the redox reaction, the oxidation number of each element of both reactant and product side is first found out. Then the charge is balanced. If the charge is already balanced then that equation is balanced. If it is not the case, then multiply it by suitable coefficient in order to balance the equation.

Interpretation Introduction

(b)

Interpretation:

The redox reaction, PbS(s)+O2(g)→PbO(aq)+SO2(g) is to be balanced with the help of oxidation number method.

Concept introduction:

In order to balance the redox reaction, the oxidation number of each element of both reactant and product side is first found out. Then the charge is balanced. If the charge is already balanced then that equation is balanced. If it is not the case, then multiply it by suitable coefficient in order to balance the equation.

Answer 6

Chapter 17, Problem 19E

Interpretation Introduction

(a)

Interpretation:

The redox reaction, Br2(l)+NaI(aq)→NaBr(aq)+I2(s) is to be balanced with the help of oxidation number method.

Concept introduction:

In order to balance the redox reaction, the oxidation number of each element of both reactant and product side is first found out. Then the charge is balanced. If the charge is already balanced then that equation is balanced. If it is not the case, then multiply it by suitable coefficient in order to balance the equation.

Answer 7

Chapter 17, Problem 19E

Interpretation Introduction

(a)

Interpretation:

The redox reaction, Br2(l)+NaI(aq)→NaBr(aq)+I2(s) is to be balanced with the help of oxidation number method.

Concept introduction:

In order to balance the redox reaction, the oxidation number of each element of both reactant and product side is first found out. Then the charge is balanced. If the charge is already balanced then that equation is balanced. If it is not the case, then multiply it by suitable coefficient in order to balance the equation.

Answer 8

Interpretation Introduction

(b)

Interpretation:

The redox reaction, PbS(s)+O2(g)→PbO(aq)+SO2(g) is to be balanced with the help of oxidation number method.

Concept introduction:

In order to balance the redox reaction, the oxidation number of each element of both reactant and product side is first found out. Then the charge is balanced. If the charge is already balanced then that equation is balanced. If it is not the case, then multiply it by suitable coefficient in order to balance the equation.

Answer 9

Interpretation Introduction

(b)

Interpretation:

The redox reaction, PbS(s)+O2(g)→PbO(aq)+SO2(g) is to be balanced with the help of oxidation number method.

Concept introduction:

In order to balance the redox reaction, the oxidation number of each element of both reactant and product side is first found out. Then the charge is balanced. If the charge is already balanced then that equation is balanced. If it is not the case, then multiply it by suitable coefficient in order to balance the equation.

Answer 10

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Answer 11

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Answer 12

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Answer 13

Ch. 17 - Prob. 1CE Ch. 17 - Prob. 2CE Ch. 17 - Prob. 3CE Ch. 17 - Prob. 4CE Ch. 17 - Prob. 5CE Ch. 17 - Prob. 6CE Ch. 17 - Prob. 7CE Ch. 17 - Prob. 8CE Ch. 17 - Prob. 9CE Ch. 17 - Prob. 10CE

Solution Summary: The author explains that the oxidation number of each element of both reactant and product side is first found out, and the charge is balanced.

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