An equation as to be written for the given coupled process and its equilibrium constant should be determined. Concept Information: Spontaneous process: A process which is initiated by itself, without the help of external energy source is called spontaneous process. All spontaneous process is associated with the decrease in free energy in the system. First law of thermodynamics : According to first law, the total energy of the universe remains constant. Second law of thermodynamics: According to second law of thermodynamics, the entropy of the universe is the sum of the entropy of the system and the surroundings. For all spontaneous process the entropy of the universe increases. Irreversible process: Irreversible process is the process in which the system cannot go back to its initial state. In an irreversible process there is an increase in entropy of the system. Equilibrium process: When the concentration of the reactants and products remains constant with time the process is said to be at equilibrium. ΔG 0 =-RTln K ΔG = F r e e e n e r g y ΔG 0 = S tan d a r d − s t a t e f r e e e n e r g y R = Gas Constant ( 0 .0826 l .atm/K .atm ) T = Temprature 273 K K= Equlibrium Constant (K P and K C )
An equation as to be written for the given coupled process and its equilibrium constant should be determined. Concept Information: Spontaneous process: A process which is initiated by itself, without the help of external energy source is called spontaneous process. All spontaneous process is associated with the decrease in free energy in the system. First law of thermodynamics : According to first law, the total energy of the universe remains constant. Second law of thermodynamics: According to second law of thermodynamics, the entropy of the universe is the sum of the entropy of the system and the surroundings. For all spontaneous process the entropy of the universe increases. Irreversible process: Irreversible process is the process in which the system cannot go back to its initial state. In an irreversible process there is an increase in entropy of the system. Equilibrium process: When the concentration of the reactants and products remains constant with time the process is said to be at equilibrium. ΔG 0 =-RTln K ΔG = F r e e e n e r g y ΔG 0 = S tan d a r d − s t a t e f r e e e n e r g y R = Gas Constant ( 0 .0826 l .atm/K .atm ) T = Temprature 273 K K= Equlibrium Constant (K P and K C )
Solution Summary: The author explains that a given coupled process and its equilibrium constant should be determined. Spontaneous process is associated with the decrease in free energy in the system.
Science that deals with the amount of energy transferred from one equilibrium state to another equilibrium state.
Chapter 17, Problem 17.72QP
Interpretation Introduction
Interpretation:
An equation as to be written for the given coupled process and its equilibrium constant should be determined.
Concept Information:
Spontaneous process: A process which is initiated by itself, without the help of external energy source is called spontaneous process. All spontaneous process is associated with the decrease in free energy in the system.
First law of thermodynamics: According to first law, the total energy of the universe remains constant.
Second law of thermodynamics: According to second law of thermodynamics, the entropy of the universe is the sum of the entropy of the system and the surroundings. For all spontaneous process the entropy of the universe increases.
Irreversible process: Irreversible process is the process in which the system cannot go back to its initial state. In an irreversible process there is an increase in entropy of the system.
Equilibrium process: When the concentration of the reactants and products remains constant with time the process is said to be at equilibrium.
Using the graphs could you help me explain the answers. I assumed that both graphs are proportional to the inverse of time, I think. Could you please help me.
Synthesis of Dibenzalacetone
[References]
Draw structures for the carbonyl electrophile and enolate nucleophile that react to give the enone below.
Question 1
1 pt
Question 2
1 pt
Question 3
1 pt
H
Question 4
1 pt
Question 5
1 pt
Question 6
1 pt
Question 7
1pt
Question 8
1 pt
Progress:
7/8 items
Que Feb 24 at
You do not have to consider stereochemistry.
. Draw the enolate ion in its carbanion form.
• Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner.
⚫ Separate multiple reactants using the + sign from the drop-down menu.
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4
Shown below is the mechanism presented for the formation of biasplatin in reference 1 from the Background and Experiment document. The amounts used of each reactant are shown. Either draw or describe a better alternative to this mechanism. (Note that the first step represents two steps combined and the proton loss is not even shown; fixing these is not the desired improvement.) (Hints: The first step is correct, the second step is not; and the amount of the anhydride is in large excess to serve a purpose.)
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