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Use the observed
aromatic. C shows
signals at
extent?
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Organic Chemistry
- The 'H NMR spectrum of compound A (C3H100) has four signals: a multiplet at 8 = 7.25-7.32 ppm (5 H), a singlet at d = 5.17 ppm (1 H), a quartet at d = 4.98 ppm (1 H), and a doublet at ô = 1.49 ppm (3 H). There are 6 signals in its 13C NMR spectrum. The IR spectrum has a broad absorption in the -3200 cm-1 region. Compound A reacts with KMNO4 in a basic solution followed by acidification to give compound B with the molecular formula C7H6O2. Draw structures for compounds A and B.arrow_forwardAll-cis cyclodecapentaene is a stable molecule that shows a single absorption in its1HNMR spectrum at 5.67 δ. Tell whether it is aromatic, and explain its NMR spectrumarrow_forwardBased on the structures given below, which of the following statements is entirely true? N Quinoline NH Isoquinoline Indole Isoindole All four compounds are non-aromatic, with 12 pi-electrons each and are equal in basicity. All four compounds are aromatic, with 10 pi-electrons each and are equal in basicity. Only quinoline and isoquinoline having 10 pi-electrons each are aromatic while indole and isoindole are antiaromatic having 8 pi-electrons each. All four compounds are aromatic, with 10 pi-electrons each, and with quinoline and isoquinoline being stronger bases than indole and isoindole. The nitrogen atoms of quinoline and isoquinoline are sp2 hybridized while the nitrogen atoms of indole and isoindole are sp³ hybridized Previousarrow_forward
- Explain why the carbonyl carbon of an aldehyde or ketone absorbs farther downeld than the carbonyl carbon of an ester in a 13C NMR spectrum.arrow_forwardPropose a structural formula for each compound consistent with its 1H-NMR and 13C-NMR spectra.arrow_forwardWhen compound A (C5H12O) is treated with HBr, it forms compound B (C5H11Br). The 1H NMR spectrum of compound A has a 1H singlet, a 3Hdoublet, a 6H doublet, and two 1H multiplets. The 1H NMR spectrum of compound B has a 6H singlet, a 3H triplet, and a 2H quartet. Identifycompounds A and B.arrow_forward
- Propose a structural formula for each compound consistent with its 1H-NMR and 13C-NMR spectra.arrow_forwardExplain why the carbonyl carbon of an aldehyde or ketone absorbs farther downfield than the carbonyl carbon of an ester in a 13C NMR spectrum.arrow_forwardPropose a structural formula for each compound consistent with its 1H-NMR and 13C-NMR spectra.arrow_forward
- Select the most accurate statement about the following compound. The compound is aromatic because there are 4n+2 pi electrons. O The compound is aromatic because it is completely conjugated throughout the entire ring. O The compound is non-aromatic (not aromatic) because it is not planar. O The compound is anti-aromatic because there are 4n pi electrons.arrow_forwardis what i chose the correct answer to the queshtionarrow_forwardCompound P has molecular formula C5H9ClO2. Deduce the structure of P from its 1H and 13C NMR spectra.arrow_forward
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