Among the given ions, aromatic rings are to be determined. Concept introduction: A molecule must be cyclic, planar, completely conjugated and should follow Huckel’s rule to be classified as aromatic. For an antiaromatic molecule, the molecule must be cyclic, planar, completely conjugated and have 4 n π electrons. For a non-aromatic molecule, the molecule lacks the one of the requirements to be aromatic or anti aromatic molecule. According to the Huckel’s rule the number of π electrons in the molecule must be equal to ( 4 n + 2 ) .

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MISSED THIS? Read Section 19.9 (Pages 878-881); Watch IWE 19.10 Consider the following reaction: CH3OH(g) CO(g) + 2H2(g) (Note that AG,CH3OH(g) = -162.3 kJ/mol and AG,co(g)=-137.2 kJ/mol.) Part A Calculate AG for this reaction at 25 °C under the following conditions: PCH₂OH Pco PH2 0.815 atm = 0.140 atm 0.170 atm Express your answer in kilojoules to three significant figures. Ο ΑΣΦ AG = -150 Submit Previous Answers Request Answer □? kJ × Incorrect; Try Again; 2 attempts remaining Calculate the free energy change under nonstandard conditions (AGrxn) by using the following relationship: AGrxn = AGrxn + RTInQ, AGxn+RTInQ, where AGxn is the standard free energy change, R is the ideal gas constant, T is the temperature in kelvins, a is the reaction quotient. Provide Feedback Next >

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Chapter 17, Problem 17.19P

Interpretation Introduction

Interpretation: Among the given ions, aromatic rings are to be determined.

Concept introduction: A molecule must be cyclic, planar, completely conjugated and should follow Huckel’s rule to be classified as aromatic. For an antiaromatic molecule, the molecule must be cyclic, planar, completely conjugated and have 4n π electrons. For a non-aromatic molecule, the molecule lacks the one of the requirements to be aromatic or anti aromatic molecule.

According to the Huckel’s rule the number of π electrons in the molecule must be equal to (4n+2).

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MISSED THIS? Read Section 19.9 (Pages 878-881); Watch IWE 19.10 Consider the following reaction: CH3OH(g) CO(g) + 2H2(g) (Note that AG,CH3OH(g) = -162.3 kJ/mol and AG,co(g)=-137.2 kJ/mol.) Part A Calculate AG for this reaction at 25 °C under the following conditions: PCH₂OH Pco PH2 0.815 atm = 0.140 atm 0.170 atm Express your answer in kilojoules to three significant figures. Ο ΑΣΦ AG = -150 Submit Previous Answers Request Answer □? kJ × Incorrect; Try Again; 2 attempts remaining Calculate the free energy change under nonstandard conditions (AGrxn) by using the following relationship: AGrxn = AGrxn + RTInQ, AGxn+RTInQ, where AGxn is the standard free energy change, R is the ideal gas constant, T is the temperature in kelvins, a is the reaction quotient. Provide Feedback Next >

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