(a) Explanation Given info: The speed of the dump truck is 19.7 m / s the time interval for two trucks is 3 min and the speed of the cycle is 4.47 m / s . The expression for frequency is, f = n T Here, n is the number of the trucks. T is the time interval. Substitute 2 for n and 3 min for T in above expression. f = 2 3 min = 0.667 per min Thus the frequency is 0.667 per min . The expression for frequency when the truck passes the cyclist is, f ' = ( v + v o v ) f Here, v is the velocity of the truck v o is the velocity of the observer (b) To determine The frequency of the trucks which passes the cyclist when the speed of cyclist is reduced to 1.56 m / s .

Physics for Scientists and Engineers (AP Edition)

9th Edition

ISBN: 9781133953951

Author: Raymond A. Serway, John W. Jewett

Publisher: Cengage Learning

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Chapter 17, Problem 17.51AP

(a)

To determine

The frequency of the trucks that pass the cyclist.

(b)

To determine

The frequency of the trucks which passes the cyclist when the speed of cyclist is reduced to 1.56 m/s .

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Chapter 17, Problem 17.50AP

Chapter 17, Problem 17.52AP

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Chapter 17 Solutions

Physics for Scientists and Engineers (AP Edition)

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The frequency of the trucks that pass the cyclist.

Solution Summary: The author determines the frequency of the trucks that pass the cyclist. The expression for frequency is f=nT.

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The frequency of the trucks that pass the cyclist.

The frequency of the trucks which passes the cyclist when the speed of cyclist is reduced to 1.56 m/s .

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Chapter 17 Solutions