Principles of Geotechnical Engineering (MindTap Course List)
Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN: 9781305970939
Author: Braja M. Das, Khaled Sobhan
Publisher: Cengage Learning
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Chapter 17, Problem 17.4P
To determine

Find the average soil friction angle ϕ by using Kulhawy and Mayne correlation.

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Hi! Kindly help me compute the following based on the attached elevation plan and floor plan: Total Perimeter of the building – to be used for layouting. Total Length of Batter Board – include all sides where batter boards will be installed. Number and spacing of Stakes – assuming a stake is placed every 1.2 meters along the perimeter. Please show the complete solution and breakdown of your computation. Thank you!
E D (B) (<) 2945 3725 250 2225 Car Port 5000 2500 Pool Area 2 3925 3465 2875 13075 Staff Room Bar Counter 1 GROUND FLOOR PLAN SCALE 1:100 Hallway 3 1560 4125 3125 $685 Laundry & Service Area 5 A Common T&B Kitchen & Dining Arear B Living Area 2425 Terrace E 2 12150 1330 2945 4150 5480 1800 3725 1925 3800 3465 2 3 9150 4125 3575 3925 Terrace Toilet & Bathroom Toilet Bathroom Bedroom 1 Bedroom 2 SECOND FLOOR PLAN SCALE Hallway 1:100 OPEN TO BELOW E B A 3 3725 2150 1330 2945 5480 4150 1925 ⑨ 2 9150 3800 4125 3465 3575 3925 Terrace R Toilet & Bathroom Toilet & Bathroom SECOND FLOOR PLAN SCALE Hallway 1:100 OPEN TO BELOW +
Q2/ In a design of a portable sprinkler system, the following information is given: • • The sprinklers are distributed in a square pattern with radius of the wetted circle of the sprinkler=15 m Consumption rate = 10 mm/day Efficiency of irrigation = 60% Net depth of irrigation (NDI)= 80 mm. Find the following: 1-Sprinkler application rate if HRS = 11. 2-Number of pipes required for irrigation. (50 Marks) 3-Discharge of sprinkler, diameter of nozzle, and the working head pressure if C=0.90. 4-Diameter of the sprinkler pipe for Slope=0. 5-Pressure head at the inlet and at the dead end of the sprinkler pipe for Slope=0. (F² + L²)((SF)² + L²) L² 2L² ≤ D² L² + S² ≤ D² A, = * 1000 S*L ≤D² N W Af m-11-P L' Hf = 1.14*109 * 1.852 * L *F,where c=120 D4.87 Source main pipe 180 m 540 m N 1 1 √m-1 F = im/Nm+1 = + + m+1 2N 6N2 i=1 Nozzle diameter (mm) 3< ds 4.8 4.8< ds 6.4 6.4
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