Interpretation:
The term 'composite' should be defined.
Concept Introduction:
Composites are formed when two or more material of different properties combines.
Explanation of Solution
Composites are formed by materials whose physical and chemical properties are different from each other. The formation of composites results in the property which alone cannot be reached by material
The properties of material through which composites are formed are divided in two main categories
- Matrix material − it helps in supporting the relative position.
- Reinforcement material- it helps in support the
mechanical properties such as load.
For the formation of composites, matrix material is in continuous phase and reinforcement material is in dispersing phase. The individual properties and volume fraction of both the materials are considered.
Based on matrix material, the material can be polymer, metal, ceramics, and carbon.
Matrix composites are classified as polymer matrix composites, metal matrix composites, ceramic matrix composites and carbon matrix composites.
Based on reinforcement material, the material can be fibers, flakes, particulates, and microspheres.
Reinforcement composites are classified as fibers reinforcement composites, flakes reinforcement composites,flakesreinforcement composites.
Composites offer the property which cannot be achieved by matrix and reinforcement materials independently. Composites offer the following properties:
- Light weight
- Imparts strength
- Resistance to corrosion
- Flexibility of converting complex structure
- Fatigue resistant
Composites had a wide application in engineering fields and formation of different products.
Application of composites:
- Aerospace industries
- Automobile industries
- Fishing rods
- Helmets
Want to see more full solutions like this?
Chapter 17 Solutions
Essentials of Materials Science and Engineering, SI Edition
- NO AI PLEASEarrow_forwardNO AI PLEASEarrow_forwardQ.2 The girder AB as shown in Fig. 2 has a span of 18m and supports concentrated loads located as shown. Determine the plastic moment capacity MP and the plastic collapse load Pc for the given load conditions. Use either Equilibrium drVirtual Work method in your solution. [30 marks] 5P 5P C d B 6 m 6 m 6 m 18 m Fig. 2 - Prismatic Continuousarrow_forward
- P5. Although all fuses possess a thermal element that melts resulting in an open circuit, describe the difference between an "expulsion" and a "current limiting" fuse.arrow_forwardExpert only, don't use Artificial intelligence or screen shot it solvingarrow_forwardThree cables are pulling on a ring located at the origin, as shown in the diagram below. FA is 200 N in magnitude with a transverse angle of 30° and an azimuth angle of 140°. FB is 240 N in magnitude with coordinate direction angles α = 135° and β = 45°. Determine the magnitude and direction of FC so that the resultant of all 3 force vectors lies on the z-axis and has a magnitude of 300 N. Specify the direction of FC using its coordinate direction angles.arrow_forward
- Solve this. find the initial conditions ic(0-) and vc(0-) the switch opens at t=0 so it's closed at t=0- dont copy the response from previous because it's wrong. please solve in great detail explaining everything step by step. now the way i thought about it is Getting millman voltage (1/3)-2 / (1/3)+(1/2) and it's the same as Vc as both are nodal voltages but i wasn't sure if correct. because i didnt take into consideration all voltages (Vc here) even though it's the same so i'm quite confused. please explain to me if i'm correct and if not tell me why and where my thinking was flawed. thank youarrow_forward3. Consider the RL circuit with a constant voltage source shown in the diagram below. The values of the resistor, inductor, and input voltage are R = 100, L = 100 mH, and Vo = 12V, respectively. Vo - Ti(t) R w When the switch closes at time t = 0, the current begins to flow as a function of time. It follows from Kirchoff's voltage law that the current is described by the differential equation di(t) L dt + Ri(t) = Vo⋅arrow_forward4. Consider the RL circuit with a sinusoid voltage source shown in the diagram below. The values of the resistor, inductor, input voltage amplitude and frequency are R = 5, L = 50mH, and Vo = 10 V, respectively. The input voltage frequency w is variable. Assume that the circuit has reached steady state. Voejwt + ↑i(t) R سيد The input voltage can be described using the complex sinusoid function V(t) = Voejwt The current is given by a sinusoid with same the frequency was the input voltage, but a different magnitude and different phase. The physical voltage and current are obtained by taking the real part. In complex form, the current is given by i(t) Vo ejwt R1+jw/ The differential equation that describes the current follows from Kirchoff's voltage law, and is given by di(t) L + Ri(t) = Voejwt dtarrow_forward
- MATLAB: An Introduction with ApplicationsEngineeringISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons IncEssentials Of Materials Science And EngineeringEngineeringISBN:9781337385497Author:WRIGHT, Wendelin J.Publisher:Cengage,Industrial Motor ControlEngineeringISBN:9781133691808Author:Stephen HermanPublisher:Cengage Learning
- Basics Of Engineering EconomyEngineeringISBN:9780073376356Author:Leland Blank, Anthony TarquinPublisher:MCGRAW-HILL HIGHER EDUCATIONStructural Steel Design (6th Edition)EngineeringISBN:9780134589657Author:Jack C. McCormac, Stephen F. CsernakPublisher:PEARSONFundamentals of Materials Science and Engineering...EngineeringISBN:9781119175483Author:William D. Callister Jr., David G. RethwischPublisher:WILEY