General, Organic, And Biological Chemistry, Hybrid (with Owlv2 Quick Prep For General Chemistry Printed Access Card)
General, Organic, And Biological Chemistry, Hybrid (with Owlv2 Quick Prep For General Chemistry Printed Access Card)
7th Edition
ISBN: 9781305253070
Author: STOKER, H. Stephen
Publisher: Cengage Learning
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Chapter 17, Problem 17.138EP

(a)

Interpretation Introduction

Interpretation:

Structure of missing substance in the given reaction that involves amides has to be drawn.

Concept Introduction:

Amides are synthesized using amidification reaction.  This involves a reaction between amine and carboxylic acid.  In this reaction, the OH group present in carboxylic acid and H from ammonia or amine is lost to give amide as the product.  Water is obtained as a by-product in this reaction.  The general reaction scheme for synthesis of amides can be given as,

Ammonia + Carboxylic acid 100 °C amideamine + Carboxylic acid 100 °C amideamine + Carboxylic acid 100 °C amide

(a)

Expert Solution
Check Mark

Answer to Problem 17.138EP

Structure of the missing substance is,

General, Organic, And Biological Chemistry, Hybrid (with Owlv2 Quick Prep For General Chemistry Printed Access Card), Chapter 17, Problem 17.138EP , additional homework tip  1

Explanation of Solution

Given reaction is,

General, Organic, And Biological Chemistry, Hybrid (with Owlv2 Quick Prep For General Chemistry Printed Access Card), Chapter 17, Problem 17.138EP , additional homework tip  2

The starting material is a carboxylic acid and a primary amine.  The product obtained on amidification reaction between carboxylic acid and a primary amine is a secondary amide.  This is formed by the loss of water molecule.  The structure of the secondary amide that is formed can be given as,

General, Organic, And Biological Chemistry, Hybrid (with Owlv2 Quick Prep For General Chemistry Printed Access Card), Chapter 17, Problem 17.138EP , additional homework tip  3

The complete reaction can be given as,

General, Organic, And Biological Chemistry, Hybrid (with Owlv2 Quick Prep For General Chemistry Printed Access Card), Chapter 17, Problem 17.138EP , additional homework tip  4

Conclusion

Structure of the missing compound is drawn.

(b)

Interpretation Introduction

Interpretation:

Structure of missing substance in the given reaction that involves amides has to be drawn.

Concept Introduction:

Amides are synthesized using amidification reaction.  This involves a reaction between amine and carboxylic acid.  In this reaction, the OH group present in carboxylic acid and H from ammonia or amine is lost to give amide as the product.  Water is obtained as a by-product in this reaction.  The general reaction scheme for synthesis of amides can be given as,

Ammonia + Carboxylic acid 100 °C amideamine + Carboxylic acid 100 °C amideamine + Carboxylic acid 100 °C amide

(b)

Expert Solution
Check Mark

Answer to Problem 17.138EP

Structure of the missing substance is,

General, Organic, And Biological Chemistry, Hybrid (with Owlv2 Quick Prep For General Chemistry Printed Access Card), Chapter 17, Problem 17.138EP , additional homework tip  5

Explanation of Solution

Given reaction is,

General, Organic, And Biological Chemistry, Hybrid (with Owlv2 Quick Prep For General Chemistry Printed Access Card), Chapter 17, Problem 17.138EP , additional homework tip  6

As the nitrogen atom present in the above amide has two hydrogen atoms bonded to it and the amide is a primary amide.  Primary amide is produced by the reaction of ammonia with carboxylic acid.  The structure of carboxylic acid can be found as shown below,

General, Organic, And Biological Chemistry, Hybrid (with Owlv2 Quick Prep For General Chemistry Printed Access Card), Chapter 17, Problem 17.138EP , additional homework tip  7

Hydrogen atom has to be added to the amine part and OH group has to be added to the acid part in order to obtain the parent molecules.  From this the missing compound is identified as,

General, Organic, And Biological Chemistry, Hybrid (with Owlv2 Quick Prep For General Chemistry Printed Access Card), Chapter 17, Problem 17.138EP , additional homework tip  8

The complete reaction can be given as,

General, Organic, And Biological Chemistry, Hybrid (with Owlv2 Quick Prep For General Chemistry Printed Access Card), Chapter 17, Problem 17.138EP , additional homework tip  9

Conclusion

Structure of the missing compound is drawn.

(c)

Interpretation Introduction

Interpretation:

Structure of missing substance in the given reaction that involves amides has to be drawn.

Concept Introduction:

Amides are synthesized using amidification reaction.  This involves a reaction between amine and carboxylic acid.  In this reaction, the OH group present in carboxylic acid and H from ammonia or amine is lost to give amide as the product.  Water is obtained as a by-product in this reaction.  The general reaction scheme for synthesis of amides can be given as,

Ammonia + Carboxylic acid 100 °C amideamine + Carboxylic acid 100 °C amideamine + Carboxylic acid 100 °C amide

(c)

Expert Solution
Check Mark

Answer to Problem 17.138EP

Structure of the missing substance is,

General, Organic, And Biological Chemistry, Hybrid (with Owlv2 Quick Prep For General Chemistry Printed Access Card), Chapter 17, Problem 17.138EP , additional homework tip  10

Explanation of Solution

Given reaction is,

General, Organic, And Biological Chemistry, Hybrid (with Owlv2 Quick Prep For General Chemistry Printed Access Card), Chapter 17, Problem 17.138EP , additional homework tip  11

As the nitrogen atom present in the above amide has no hydrogen atoms bonded to it, the amide is a tertiary amide.  Tertiary amide is produced by the reaction of secondary amine with carboxylic acid.  The parent compound structures can be identified as shown below,

General, Organic, And Biological Chemistry, Hybrid (with Owlv2 Quick Prep For General Chemistry Printed Access Card), Chapter 17, Problem 17.138EP , additional homework tip  12

Hydrogen atom has to be added to the amine part and OH group has to be added to the acid part in order to obtain the parent molecules.  From this the missing compound is identified as,

General, Organic, And Biological Chemistry, Hybrid (with Owlv2 Quick Prep For General Chemistry Printed Access Card), Chapter 17, Problem 17.138EP , additional homework tip  13

The complete reaction can be given as,

General, Organic, And Biological Chemistry, Hybrid (with Owlv2 Quick Prep For General Chemistry Printed Access Card), Chapter 17, Problem 17.138EP , additional homework tip  14

Conclusion

Structure of the missing compound is drawn.

(d)

Interpretation Introduction

Interpretation:

Structure of missing substance in the given reaction that involves amides has to be drawn.

Concept Introduction:

Amides are synthesized using amidification reaction.  This involves a reaction between amine and carboxylic acid.  In this reaction, the OH group present in carboxylic acid and H from ammonia or amine is lost to give amide as the product.  Water is obtained as a by-product in this reaction.  The general reaction scheme for synthesis of amides can be given as,

Ammonia + Carboxylic acid 100 °C amideamine + Carboxylic acid 100 °C amideamine + Carboxylic acid 100 °C amide

(d)

Expert Solution
Check Mark

Answer to Problem 17.138EP

Structure of the missing substance is,

General, Organic, And Biological Chemistry, Hybrid (with Owlv2 Quick Prep For General Chemistry Printed Access Card), Chapter 17, Problem 17.138EP , additional homework tip  15

Explanation of Solution

Given reaction is,

General, Organic, And Biological Chemistry, Hybrid (with Owlv2 Quick Prep For General Chemistry Printed Access Card), Chapter 17, Problem 17.138EP , additional homework tip  16

As the nitrogen atom present in the above amide has one hydrogen atom bonded to it and the amide is a secondary amide.  Secondary amide is produced by the reaction of primary amine with carboxylic acid.  The structure of carboxylic acid is given and the structure of primary amine has to be found out.

General, Organic, And Biological Chemistry, Hybrid (with Owlv2 Quick Prep For General Chemistry Printed Access Card), Chapter 17, Problem 17.138EP , additional homework tip  17

Hydrogen atom has to be added to the amine part and OH group has to be added to the acid part in order to obtain the parent molecules.  From this the missing compound is identified as,

General, Organic, And Biological Chemistry, Hybrid (with Owlv2 Quick Prep For General Chemistry Printed Access Card), Chapter 17, Problem 17.138EP , additional homework tip  18

The complete reaction can be given as,

General, Organic, And Biological Chemistry, Hybrid (with Owlv2 Quick Prep For General Chemistry Printed Access Card), Chapter 17, Problem 17.138EP , additional homework tip  19

Conclusion

Structure of the missing compound is drawn.

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Chapter 17 Solutions

General, Organic, And Biological Chemistry, Hybrid (with Owlv2 Quick Prep For General Chemistry Printed Access Card)

Ch. 17.4 - Prob. 1QQCh. 17.4 - Prob. 2QQCh. 17.5 - Prob. 1QQCh. 17.5 - Prob. 2QQCh. 17.5 - Prob. 3QQCh. 17.6 - Prob. 1QQCh. 17.6 - Prob. 2QQCh. 17.6 - Prob. 3QQCh. 17.7 - Prob. 1QQCh. 17.7 - Prob. 2QQCh. 17.7 - Prob. 3QQCh. 17.8 - Prob. 1QQCh. 17.8 - Prob. 2QQCh. 17.8 - Prob. 3QQCh. 17.8 - Prob. 4QQCh. 17.9 - Prob. 1QQCh. 17.9 - Prob. 2QQCh. 17.10 - Prob. 1QQCh. 17.10 - Prob. 2QQCh. 17.10 - Prob. 3QQCh. 17.10 - Prob. 4QQCh. 17.11 - Prob. 1QQCh. 17.11 - Prob. 2QQCh. 17.11 - Prob. 3QQCh. 17.12 - Prob. 1QQCh. 17.12 - Prob. 2QQCh. 17.12 - Prob. 3QQCh. 17.12 - Prob. 4QQCh. 17.13 - Prob. 1QQCh. 17.13 - Prob. 2QQCh. 17.13 - Prob. 3QQCh. 17.13 - Prob. 4QQCh. 17.14 - Prob. 1QQCh. 17.14 - Prob. 2QQCh. 17.14 - Prob. 3QQCh. 17.15 - Prob. 1QQCh. 17.15 - Prob. 2QQCh. 17.16 - Prob. 1QQCh. 17.16 - Prob. 2QQCh. 17.16 - Prob. 3QQCh. 17.17 - Prob. 1QQCh. 17.17 - Prob. 2QQCh. 17.17 - Prob. 3QQCh. 17.18 - Prob. 1QQCh. 17.18 - Prob. 2QQCh. 17.18 - Prob. 3QQCh. 17.19 - Prob. 1QQCh. 17.19 - Prob. 2QQCh. 17.19 - Prob. 3QQCh. 17.19 - Prob. 4QQCh. 17 - Prob. 17.1EPCh. 17 - Prob. 17.2EPCh. 17 - Prob. 17.3EPCh. 17 - Prob. 17.4EPCh. 17 - Prob. 17.5EPCh. 17 - Prob. 17.6EPCh. 17 - Indicate whether or not each of the following...Ch. 17 - Indicate whether or not each of the following...Ch. 17 - Prob. 17.9EPCh. 17 - Prob. 17.10EPCh. 17 - Prob. 17.11EPCh. 17 - Prob. 17.12EPCh. 17 - Prob. 17.13EPCh. 17 - Prob. 17.14EPCh. 17 - Prob. 17.15EPCh. 17 - Assign a common name to each of the following...Ch. 17 - Prob. 17.17EPCh. 17 - Prob. 17.18EPCh. 17 - Prob. 17.19EPCh. 17 - Prob. 17.20EPCh. 17 - Prob. 17.21EPCh. 17 - Prob. 17.22EPCh. 17 - Prob. 17.23EPCh. 17 - Prob. 17.24EPCh. 17 - Prob. 17.25EPCh. 17 - Prob. 17.26EPCh. 17 - Prob. 17.27EPCh. 17 - Prob. 17.28EPCh. 17 - Prob. 17.29EPCh. 17 - Prob. 17.30EPCh. 17 - Prob. 17.31EPCh. 17 - Prob. 17.32EPCh. 17 - Prob. 17.33EPCh. 17 - Prob. 17.34EPCh. 17 - Determine the maximum number of hydrogen bonds...Ch. 17 - Prob. 17.36EPCh. 17 - Prob. 17.37EPCh. 17 - Prob. 17.38EPCh. 17 - Prob. 17.39EPCh. 17 - Prob. 17.40EPCh. 17 - Prob. 17.41EPCh. 17 - Prob. 17.42EPCh. 17 - Prob. 17.43EPCh. 17 - Prob. 17.44EPCh. 17 - Prob. 17.45EPCh. 17 - Prob. 17.46EPCh. 17 - Prob. 17.47EPCh. 17 - Prob. 17.48EPCh. 17 - Prob. 17.49EPCh. 17 - Prob. 17.50EPCh. 17 - Prob. 17.51EPCh. 17 - Prob. 17.52EPCh. 17 - Prob. 17.53EPCh. 17 - Prob. 17.54EPCh. 17 - Prob. 17.55EPCh. 17 - Prob. 17.56EPCh. 17 - Prob. 17.57EPCh. 17 - Prob. 17.58EPCh. 17 - Prob. 17.59EPCh. 17 - Prob. 17.60EPCh. 17 - Prob. 17.61EPCh. 17 - Prob. 17.62EPCh. 17 - Prob. 17.63EPCh. 17 - Prob. 17.64EPCh. 17 - Prob. 17.65EPCh. 17 - Prob. 17.66EPCh. 17 - Prob. 17.67EPCh. 17 - Prob. 17.68EPCh. 17 - Prob. 17.69EPCh. 17 - Prob. 17.70EPCh. 17 - Prob. 17.71EPCh. 17 - Prob. 17.72EPCh. 17 - Prob. 17.73EPCh. 17 - Prob. 17.74EPCh. 17 - Prob. 17.75EPCh. 17 - Prob. 17.76EPCh. 17 - Prob. 17.77EPCh. 17 - Prob. 17.78EPCh. 17 - Prob. 17.79EPCh. 17 - Prob. 17.80EPCh. 17 - Prob. 17.81EPCh. 17 - Prob. 17.82EPCh. 17 - Prob. 17.83EPCh. 17 - Prob. 17.84EPCh. 17 - Prob. 17.85EPCh. 17 - Prob. 17.86EPCh. 17 - Prob. 17.87EPCh. 17 - Prob. 17.88EPCh. 17 - Prob. 17.89EPCh. 17 - Prob. 17.90EPCh. 17 - Prob. 17.91EPCh. 17 - Prob. 17.92EPCh. 17 - Prob. 17.93EPCh. 17 - Prob. 17.94EPCh. 17 - Prob. 17.95EPCh. 17 - Prob. 17.96EPCh. 17 - Prob. 17.97EPCh. 17 - Prob. 17.98EPCh. 17 - Indicate whether or not each of the following...Ch. 17 - Indicate whether or not each of the following...Ch. 17 - Classify each of the following amides as...Ch. 17 - Classify each of the following amides as...Ch. 17 - Classify each of the amides in Problem 17-101 as a...Ch. 17 - Prob. 17.104EPCh. 17 - Prob. 17.105EPCh. 17 - Prob. 17.106EPCh. 17 - Prob. 17.107EPCh. 17 - Prob. 17.108EPCh. 17 - Prob. 17.109EPCh. 17 - Prob. 17.110EPCh. 17 - Assign an IUPAC name to each of the following...Ch. 17 - Assign an IUPAC name to each of the following...Ch. 17 - Prob. 17.113EPCh. 17 - Prob. 17.114EPCh. 17 - Prob. 17.115EPCh. 17 - Prob. 17.116EPCh. 17 - Prob. 17.117EPCh. 17 - Prob. 17.118EPCh. 17 - Prob. 17.119EPCh. 17 - What is the relationship between the acronym DEET...Ch. 17 - Prob. 17.121EPCh. 17 - Prob. 17.122EPCh. 17 - Prob. 17.123EPCh. 17 - Prob. 17.124EPCh. 17 - Prob. 17.125EPCh. 17 - Prob. 17.126EPCh. 17 - Prob. 17.127EPCh. 17 - Prob. 17.128EPCh. 17 - Prob. 17.129EPCh. 17 - Prob. 17.130EPCh. 17 - Prob. 17.131EPCh. 17 - Prob. 17.132EPCh. 17 - Prob. 17.133EPCh. 17 - Prob. 17.134EPCh. 17 - Prob. 17.135EPCh. 17 - Prob. 17.136EPCh. 17 - Prob. 17.137EPCh. 17 - Prob. 17.138EPCh. 17 - Prob. 17.139EPCh. 17 - Prob. 17.140EPCh. 17 - Prob. 17.141EPCh. 17 - Prob. 17.142EPCh. 17 - Prob. 17.143EPCh. 17 - Prob. 17.144EPCh. 17 - Prob. 17.145EPCh. 17 - Prob. 17.146EPCh. 17 - Prob. 17.147EPCh. 17 - Prob. 17.148EPCh. 17 - Prob. 17.149EPCh. 17 - Prob. 17.150EPCh. 17 - Prob. 17.151EPCh. 17 - Prob. 17.152EPCh. 17 - Prob. 17.153EPCh. 17 - Prob. 17.154EP
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