BIOCHEMISTRY W/1 TERM ACHEIVE ACCESS
9th Edition
ISBN: 9781319425746
Author: BERG
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 17, Problem 15P
Interpretation Introduction
Interpretation:
The reason for TCA cycle known as a supramolecular enzyme.
Concept introduction:
The citric acid cycle is a catabolic process. It is a series of
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
You’ve isolated a protein and determined that the Native molecular weight of the holoenzyme is 160 kD using size exclusion chromatography. Analysis of this protein using SDS-PAGE revealed 2 bands, one at 100 kD and one at 30 kD.
The enzyme was found to be 0.829% NAD (by weight). What further can be said regarding the structure of the polypeptide?
What is the formation of glycosylated hemoglobin (the basis for the HbA1c test)? Can you describe it?
Please analze the gel electrophoresis column of the VRK1 kinase (MW: 39.71 kDa).
Also use a ruler to measure the length of the column in centimeters and calculate the MW of each band observed.
Lane 1: buffer
Lane 2 : Ladder
Lane 3: Lysate
Lane 4: Flowthrough
Lane 5: Wash
Lanes 6-8: E1, E2, E3
Lane 9: Dialyzed VRK1
Lane 10: LDH
Chapter 17 Solutions
BIOCHEMISTRY W/1 TERM ACHEIVE ACCESS
Ch. 17 - Prob. 1PCh. 17 - Prob. 2PCh. 17 - Prob. 3PCh. 17 - Prob. 4PCh. 17 - Prob. 5PCh. 17 - Prob. 6PCh. 17 - Prob. 7PCh. 17 - Prob. 8PCh. 17 - Prob. 9PCh. 17 - Prob. 10P
Ch. 17 - Prob. 11PCh. 17 - Prob. 12PCh. 17 - Prob. 13PCh. 17 - Prob. 14PCh. 17 - Prob. 15PCh. 17 - Prob. 16PCh. 17 - Prob. 17PCh. 17 - Prob. 18PCh. 17 - Prob. 19PCh. 17 - Prob. 20PCh. 17 - Prob. 21PCh. 17 - Prob. 22PCh. 17 - Prob. 23PCh. 17 - Prob. 24PCh. 17 - Prob. 25PCh. 17 - Prob. 26PCh. 17 - Prob. 27PCh. 17 - Prob. 28PCh. 17 - Prob. 29PCh. 17 - Prob. 30PCh. 17 - Prob. 31PCh. 17 - Prob. 32PCh. 17 - Prob. 33PCh. 17 - Prob. 34PCh. 17 - Prob. 35PCh. 17 - Prob. 36PCh. 17 - Prob. 37PCh. 17 - Prob. 38PCh. 17 - Prob. 39PCh. 17 - Prob. 40PCh. 17 - Prob. 41PCh. 17 - Prob. 42PCh. 17 - Prob. 43PCh. 17 - Prob. 44P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biochemistry and related others by exploring similar questions and additional content below.Similar questions
- Do sensory neurons express ACE2 or only neurolipin-1 receptors for COVID19 virus particle binding?arrow_forwardExplain the process of CNS infiltration of COVID19 through sensory neurons from beginning to end, including processes like endocytosis, the different receptors/proteins that are involved, how they are transported and released, etc.,arrow_forwardH2C CH2 HC-COOO CH2 ܘHO-C-13c-O isocitrate C-S-COA H213c CH2 C-OO 13C-S-COA CH2 C-00 the label will not be present in succinyl CoA C-S-COA succinyl-CoAarrow_forward
- A culture of kidneys cells contains all intermediates of the citric acid cycle. It is treated with an irreversible inhibitor of malate dehydrogenase, and then infused withglucose. Fill in the following list to account for the number of energy molecules that are formed from that one molecule of glucose in this situation. (NTP = nucleotidetriphosphate, e.g., ATP or GTP)Net number of NTP:Net number of NADH:Net number of FADH2:arrow_forward16. Which one of the compounds below is the final product of the reaction sequence shown here? OH A B NaOH Zn/Hg aldol condensation heat aq. HCI acetone C 0 D Earrow_forward2. Which one of the following alkenes undergoes the least exothermic hydrogenation upon treatment with H₂/Pd? A B C D Earrow_forward
- 6. What is the IUPAC name of the following compound? A) (Z)-3,5,6-trimethyl-3,5-heptadiene B) (E)-2,3,5-trimethyl-1,4-heptadiene C) (E)-5-ethyl-2,3-dimethyl-1,5-hexadiene D) (Z)-5-ethyl-2,3-dimethyl-1,5-hexadiene E) (Z)-2,3,5-trimethyl-1,4-heptadienearrow_forwardConsider the reaction shown. CH2OH Ex. CH2 -OH CH2- Dihydroxyacetone phosphate glyceraldehyde 3-phosphate The standard free-energy change (AG) for this reaction is 7.53 kJ mol-¹. Calculate the free-energy change (AG) for this reaction at 298 K when [dihydroxyacetone phosphate] = 0.100 M and [glyceraldehyde 3-phosphate] = 0.00300 M. AG= kJ mol-1arrow_forwardIf the pH of gastric juice is 1.6, what is the amount of energy (AG) required for the transport of hydrogen ions from a cell (internal pH of 7.4) into the stomach lumen? Assume that the membrane potential across this membrane is -70.0 mV and the temperature is 37 °C. AG= kJ mol-1arrow_forward
- Consider the fatty acid structure shown. Which of the designations are accurate for this fatty acid? 17:2 (48.11) 18:2(A9.12) cis, cis-A8, A¹¹-octadecadienoate w-6 fatty acid 18:2(A6,9)arrow_forwardClassify the monosaccharides. H-C-OH H. H-C-OH H-C-OH CH₂OH H-C-OH H-C-OH H-C-OH CH₂OH CH₂OH CH₂OH CH₂OH D-erythrose D-ribose D-glyceraldehyde Dihydroxyacetone CH₂OH CH₂OH C=O Answer Bank CH₂OH C=0 HO C-H C=O H-C-OH H-C-OH pentose hexose tetrose H-C-OH H-C-OH H-C-OH aldose triose ketose CH₂OH CH₂OH CH₂OH D-erythrulose D-ribulose D-fructosearrow_forwardFatty acids are carboxylic acids with long hydrophobic tails. Draw the line-bond structure of cis-A9-hexadecenoate. Clearly show the cis-trans stereochemistry.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
BiochemistryBiochemistryISBN:9781305577206Author:Reginald H. Garrett, Charles M. GrishamPublisher:Cengage Learning
BiochemistryBiochemistryISBN:9781305961135Author:Mary K. Campbell, Shawn O. Farrell, Owen M. McDougalPublisher:Cengage Learning
Biology 2eBiologyISBN:9781947172517Author:Matthew Douglas, Jung Choi, Mary Ann ClarkPublisher:OpenStax
Biochemistry
Biochemistry
ISBN:9781305577206
Author:Reginald H. Garrett, Charles M. Grisham
Publisher:Cengage Learning
Biochemistry
Biochemistry
ISBN:9781305961135
Author:Mary K. Campbell, Shawn O. Farrell, Owen M. McDougal
Publisher:Cengage Learning
Biology 2e
Biology
ISBN:9781947172517
Author:Matthew Douglas, Jung Choi, Mary Ann Clark
Publisher:OpenStax
Macromolecules | Classes and Functions; Author: 2 Minute Classroom;https://www.youtube.com/watch?v=V5hhrDFo8Vk;License: Standard youtube license