Foundations of College Chemistry, Binder Ready Version
Foundations of College Chemistry, Binder Ready Version
15th Edition
ISBN: 9781119083900
Author: Morris Hein, Susan Arena, Cary Willard
Publisher: WILEY
bartleby

Videos

Question
Book Icon
Chapter 17, Problem 14PE

(a)

Interpretation Introduction

Interpretation:

The below equation through change in oxidation number method has to be balanced.

  Cu+AgNO3Ag+Cu(NO3)2

Concept Introduction:

Steps for change in oxidation number method to balance redox reactions are as follows:

1 Oxidation number of each element has to be assigned and change in oxidation number has to be identified. Then add electrons to balance charge.

2 Two half-reactions with only elements that have changed oxidation numbers have to be formed.

3 Both reactions multiplied by smallest whole number that can make electrons lost equal to electron gained.

4 Coefficient should transfer to original equation.

5 Remaining oxygen atoms are balanced through water molecules.

6 For acidic medium, charge is balanced by addition of H+ ion.

(a)

Expert Solution
Check Mark

Explanation of Solution

Given reaction is as follows:

  Cu+AgNO3Ag+Cu(NO3)2        (1)

Oxidation number of each element in equation (1) can be assigned as follows:

  Cu0+Ag+1N+5O32Ag0+Cu+2(N+5O23)2

Change in oxidation number occurred in copper and silver thus two half-reactions can be formed as follows:

Oxidation half-reaction for copper is as follows:

  Cu0Cu+2(N+5O23)2+2e        (2)

Reduction half-reaction for silver is as follows:

  Ag+1N+5O32+1eAg0        (3)

Multiply equation (3) by 2 to make same number of electron gained and loses.

  2Ag+1N+5O32+2e2Ag0        (4)

Coefficient of atoms in equation (2) and equation (4) of half reactions are transferred to equation (1). Left atoms are balanced by equalizing its number on both sides. Thus balanced equation is as follows:

  Cu+2AgNO32Ag+Cu(NO3)2

(b)

Interpretation Introduction

Interpretation:

The below equation through change in oxidation number method has to be balanced.

  MnO2+HClMnCl2+Cl2+H2O

Concept Introduction:

Refer to part (a).

(b)

Expert Solution
Check Mark

Explanation of Solution

Given reaction is as follows:

  MnO2+HClMnCl2+Cl2+H2O        (5)

Oxidation number of each element in equation (5) can be assigned as follows:

  Mn+4O22+H+1Cl1Mn+2Cl21+Cl20+H2+1O2

Change in oxidation number occurred in manganese and chlorine thus two half-reactions can be formed as follows:

Oxidation half-reaction for chlorine is as follows:

  2H+1Cl1Cl20+2e        (6)

Reduction half-reaction for manganese is as follows:

  Mn+4O22+2eMn+2Cl21        (7)

Coefficient of atoms in both half reactions is transferred to equation (5). Left atoms are balanced by equalizing its number on both sides. Thus balanced equation is as follows:

  MnO2+4HClMnCl2+Cl2+2H2O

(c)

Interpretation Introduction

Interpretation:

The below equation through change in oxidation number method has to be balanced.

  HCl+O2Cl2+H2O

Concept Introduction:

Refer to part (a).

(c)

Expert Solution
Check Mark

Explanation of Solution

Given reaction is as follows:

  HCl+O2Cl2+H2O        (9)

Oxidation number of each element in equation (9) can be assigned as follows:

  H+1Cl1+O02Cl02+H+12O2

Change in oxidation number occured in chlorine and oxygen thus two balanced half-reactions can be formed as follows:

Balanced oxidation half-reaction is as follows:

  2H+1Cl1Cl02+2e        (10)

Balanced reduction half-reaction is as follows:

  O02+4e2H+12O2        (11)

Multiply equation (10) by 2 so that number of electrons gained and lost becomes same and cancels each other. Thus, equation (10) is as follows:

  4H+1Cl12Cl02+4e        (12)

Coefficient of atoms in equation (11) and equation (12) of half reactions are transferred to equation (9). Remaining atoms are balanced by equalizing its number on both sides. Thus balanced equation is as follows:

  4HCl+O22Cl2+2H2O

(d)

Interpretation Introduction

Interpretation:

The below equation through change in oxidation number method has to be balanced.

  Ag+H2S+O2Ag2S+H2O

Concept Introduction:

Refer to part (a).

(d)

Expert Solution
Check Mark

Explanation of Solution

Given reaction is as follows:

  Ag+H2S+O2Ag2S+H2O        (13)

Oxidation number of each element in equation can be assigned as follows:

  Ag0+H+12S2+O02Ag+12S2+H+12O2

Change in oxidation number occurred in silver and oxygen thus two balanced half-reactions can be formed as follows:

Balanced oxidation half-reaction is as follows:

  2Ag0Ag+12S2+2e        (14)

Balanced reduction half-reaction is as follows:

  O2+4e2H+12O2        (15)

Multiply equation (14) by 2 so that number of electrons gained and lost becomes same and cancels each other. Thus, equation (14) becomes as follows:

  4Ag02Ag+12S2+4e        (16)

Coefficient of atoms in equation (15) and equation (16) of half reactions are transferred to equation (13). Remaining atoms are balanced by equalizing its number on both sides. Thus balanced equation is as follows:

  4Ag+2H2S+O22Ag2S+2H2O

(e)

Interpretation Introduction

Interpretation:

The below equation through change in oxidation number method has to be balanced.

  KMnO4+CaC2O4+H2SO4K2SO4+MnSO4+CaSO4+CO2+H2O

Concept Introduction:

Refer to part (a).

(e)

Expert Solution
Check Mark

Explanation of Solution

Given reaction is as follows:

  KMnO4+CaC2O4+H2SO4[K2SO4+MnSO4+CaSO4+CO2+H2O]        (17)

Oxidation number of each element in equation can be assigned as follows:

  K+1Mn+7O24+Ca+2C+32O24+H+12S+6O24[K+12S+6O24+Mn+2S+6O24+Ca+2S+6O24+C+4O22+H+12O2]

Change in oxidation number occurred in manganese and carbon thus two balanced half-reactions can be formed as follows:

Balanced oxidation half-reaction for carbon is as follows:

  Ca+2C+32O242C+4O22+2e        (18)

Balanced reduction half-reaction for manganese is as follows:

  K+1Mn+7O24+5eMn+2S+6O24        (19)

Multiply equation (18) by 5 and equation (19) by 2 so that number of electrons gained and lost becomes same and cancels each other. Thus, equation (18) becomes as follows:

  5Ca+2C+32O2410C+4O22+5e        (20)

Equation (19) becomes as follows:

  2K+1Mn+7O24+10e2Mn+2S+6O24        (21)

Coefficient of atoms in equation (20) and equation (21) of half reactions are transferred to equation (17). Remaining atoms are balanced by equalizing its number on both sides. Thus balanced equation is as follows:

  2KMnO4+5CaC2O4+8H2SO4K2SO4+2MnSO4+5CaSO4+10CO2+8H2O

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
1/2 - 51% + » GAY Organic Reactions Assignment /26 Write the type of reaction that is occurring on the line provided then complete the reaction. Only include the major products and any byproducts (e.g. H₂O) but no minor products. Please use either full structural diagrams or the combination method shown in the lesson. Skeletal/line diagrams will not be accepted. H3C 1. 2. CH3 A Acid OH Type of Reaction: NH Type of Reaction: + H₂O Catalyst + HBr 3. Type of Reaction: H3C 4. Type Reaction: 5. H3C CH2 + H2O OH + [0] CH3 Type of Reaction: 6. OH CH3 HO CH3 + Type of Reaction: 7. Type of Reaction: + [H]
humbnai Concentration Terms[1].pdf ox + New Home Edit Sign in Comment Convert Page Fill & Sign Protect Tools Batch +WPS A Free Trial Share Inter Concreting Concentration forms. Hydrogen peroxide is a powerful oxidizing agent wed in concentrated solution in rocket fuels and in dilute solution as a hair bleach. An aqueous sulation of H2O2 is 30% by mass and has density of #liligime calculat the Ⓒmolality ⑥mole fraction of molarity. 20 9. B. A sample of Commercial Concentrated hydrochloric ET
If a reaction occurs, what would be the major products? Please include a detailed explanation as well as a drawing showing how the reaction occurs and what the final product is.

Chapter 17 Solutions

Foundations of College Chemistry, Binder Ready Version

Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
  • Text book image
    Chemistry & Chemical Reactivity
    Chemistry
    ISBN:9781337399074
    Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
    Publisher:Cengage Learning
    Text book image
    Chemistry & Chemical Reactivity
    Chemistry
    ISBN:9781133949640
    Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
    Publisher:Cengage Learning
    Text book image
    Chemistry
    Chemistry
    ISBN:9781305957404
    Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
    Publisher:Cengage Learning
  • Text book image
    World of Chemistry, 3rd edition
    Chemistry
    ISBN:9781133109655
    Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
    Publisher:Brooks / Cole / Cengage Learning
    Text book image
    Chemistry: An Atoms First Approach
    Chemistry
    ISBN:9781305079243
    Author:Steven S. Zumdahl, Susan A. Zumdahl
    Publisher:Cengage Learning
    Text book image
    Chemistry
    Chemistry
    ISBN:9781133611097
    Author:Steven S. Zumdahl
    Publisher:Cengage Learning
Text book image
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Text book image
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Text book image
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Text book image
World of Chemistry, 3rd edition
Chemistry
ISBN:9781133109655
Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher:Brooks / Cole / Cengage Learning
Text book image
Chemistry: An Atoms First Approach
Chemistry
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Cengage Learning
Text book image
Chemistry
Chemistry
ISBN:9781133611097
Author:Steven S. Zumdahl
Publisher:Cengage Learning
Balancing Redox Reactions in Acidic and Basic Conditions; Author: Professor Dave Explains;https://www.youtube.com/watch?v=N6ivvu6xlog;License: Standard YouTube License, CC-BY