EBK WEBASSIGN FOR ZUMDAHL'S CHEMICAL PR
8th Edition
ISBN: 9780357119099
Author: ZUMDAHL
Publisher: VST
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Chapter 17, Problem 130CP
Plants that thrive in salt water must have internal solutions (inside the plant cells) that are isotonic (same osmotic pressure) with the surrounding solution. A leaf of a saltwater plant is able to thrive in an aqueous salt solution (at 25°C) that has a freezing point equal to 20.621°C. You would like to use this information to calculate the osmotic pressure of the solution in the cell.
a. In order to use the freezing-point depression to calculate osmotic pressure, what assumption must you
make (in addition to ideal behavior of the solutions, which we will assume)?
b. Under what conditions is the assumption in part a reasonable?
c. Solve for the osmotic pressure (at 25°C) of the solution in the plant cell.
d. The plant leaf is placed in an aqueous salt solution (at 25°C) that has a boiling point of 102.0°C. What will happen to the plant cells in the leaf?
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Chapter 17 Solutions
EBK WEBASSIGN FOR ZUMDAHL'S CHEMICAL PR
Ch. 17 - Prob. 1DQCh. 17 - Consider Fig. 17.8. Suppose that instead of having...Ch. 17 - Prob. 3DQCh. 17 - Prob. 4DQCh. 17 - Prob. 5DQCh. 17 - Prob. 6DQCh. 17 - Prob. 7DQCh. 17 - Prob. 8DQCh. 17 - Prob. 9DQCh. 17 - Prob. 10DQ
Ch. 17 - Prob. 11DQCh. 17 - Prob. 12ECh. 17 - Prob. 13ECh. 17 - Prob. 14ECh. 17 - Prob. 15ECh. 17 - Prob. 16ECh. 17 - Prob. 17ECh. 17 - Prob. 18ECh. 17 - Prob. 19ECh. 17 - Prob. 20ECh. 17 - Prob. 21ECh. 17 - Prob. 22ECh. 17 - Prob. 23ECh. 17 - Prob. 24ECh. 17 - Prob. 25ECh. 17 - Prob. 26ECh. 17 - Prob. 27ECh. 17 - Prob. 28ECh. 17 - Prob. 29ECh. 17 - Prob. 30ECh. 17 - Prob. 31ECh. 17 - Prob. 32ECh. 17 - Prob. 33ECh. 17 - Prob. 34ECh. 17 - Prob. 35ECh. 17 - Prob. 36ECh. 17 - Prob. 37ECh. 17 - Prob. 38ECh. 17 - Prob. 39ECh. 17 - Prob. 40ECh. 17 - Rationalize the temperature dependence of the...Ch. 17 - Prob. 42ECh. 17 - Prob. 43ECh. 17 - Prob. 44ECh. 17 - Prob. 45ECh. 17 - Prob. 46ECh. 17 - Prob. 47ECh. 17 - Prob. 48ECh. 17 - Prob. 49ECh. 17 - Prob. 50ECh. 17 - Prob. 51ECh. 17 - Prob. 52ECh. 17 - Prob. 53ECh. 17 - Prob. 54ECh. 17 - Prob. 55ECh. 17 - Prob. 56ECh. 17 - The following plot shows the vapor pressure of...Ch. 17 - Prob. 58ECh. 17 - Prob. 59ECh. 17 - Prob. 60ECh. 17 - Prob. 61ECh. 17 - Prob. 62ECh. 17 - Prob. 63ECh. 17 - Prob. 64ECh. 17 - Prob. 65ECh. 17 - Prob. 66ECh. 17 - Prob. 67ECh. 17 - An aqueous solution of 10.00 g of catalase, an...Ch. 17 - Prob. 69ECh. 17 - What volume of ethylene glycol (C2H6O2) , a...Ch. 17 - Prob. 71ECh. 17 - Erythrocytes are red blood cells containing...Ch. 17 - Prob. 73ECh. 17 - Prob. 74ECh. 17 - Prob. 75ECh. 17 - Prob. 76ECh. 17 - Prob. 77ECh. 17 - Prob. 78ECh. 17 - Prob. 79ECh. 17 - Prob. 80ECh. 17 - Consider the following solutions: 0.010 m Na3PO4...Ch. 17 - From the following: pure water solution of...Ch. 17 - Prob. 83ECh. 17 - Prob. 84ECh. 17 - Prob. 85ECh. 17 - Prob. 86ECh. 17 - Prob. 87ECh. 17 - Prob. 88ECh. 17 - Prob. 89ECh. 17 - Prob. 90ECh. 17 - Prob. 91ECh. 17 - Prob. 92ECh. 17 - Prob. 93AECh. 17 - Prob. 94AECh. 17 - Prob. 95AECh. 17 - Prob. 96AECh. 17 - The term proof is defined as twice the percent by...Ch. 17 - Prob. 98AECh. 17 - Prob. 99AECh. 17 - Prob. 100AECh. 17 - Prob. 101AECh. 17 - Prob. 102AECh. 17 - Prob. 103AECh. 17 - Prob. 104AECh. 17 - Prob. 105AECh. 17 - Prob. 106AECh. 17 - Prob. 107AECh. 17 - Prob. 108AECh. 17 - Prob. 109AECh. 17 - Prob. 110AECh. 17 - Prob. 111AECh. 17 - Prob. 112AECh. 17 - Prob. 113AECh. 17 - Prob. 114AECh. 17 - Formic acid (HCO2H) is a monoprotic acid that...Ch. 17 - Prob. 116AECh. 17 - Prob. 117AECh. 17 - Prob. 118AECh. 17 - Prob. 119AECh. 17 - Prob. 120AECh. 17 - Prob. 121AECh. 17 - Prob. 122AECh. 17 - Prob. 123AECh. 17 - Prob. 124AECh. 17 - Prob. 125AECh. 17 - Prob. 126AECh. 17 - Prob. 127CPCh. 17 - Prob. 128CPCh. 17 - Prob. 129CPCh. 17 - Plants that thrive in salt water must have...Ch. 17 - Prob. 131CPCh. 17 - Prob. 132CPCh. 17 - Prob. 133CPCh. 17 - Prob. 134CPCh. 17 - Prob. 135CPCh. 17 - Prob. 136CP
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Solutions: Crash Course Chemistry #27; Author: Crash Course;https://www.youtube.com/watch?v=9h2f1Bjr0p4;License: Standard YouTube License, CC-BY