Concept explainers
(a)
Interpretation: The chloride salt of lead is converted to its chromate salt to test its presence, the reason has to be confirmed.
Concept introduction: Metal ions present in a solution can be identified by a set procedure known as qualitative analysis. Different metal ions show different reactions with different reagent and thus either through the color of the precipitate formed or by smell the gas evolved the metal ion present can be identified.
Some metal ions when present in an aqueous solution containing anions or neutral species called Lewis base or ligands having a tendency to donate electron pairs to metal ions then complex ion formation will take place. Complex ions are stable and thus formation of these increase the solubility of the salt containing the metal ions same as in complex ions.
Example of metal ions that form complex ions includes
Example of Lewis bases includes,
(b)
Interpretation: The presence of
Concept introduction: Metal ions present in a solution can be identified by a set procedure known as qualitative analysis. Different metal ions show different reactions with different reagent and thus either through the color of the precipitate formed or by smell the gas evolved the metal ion present can be identified.
Some metal ions when present in an aqueous solution containing anions or neutral species called Lewis base or ligands having a tendency to donate electron pairs to metal ions then complex ion formation will take place. Complex ions are stable and thus formation of these increase the solubility of the salt containing the metal ions same as in complex ions.
Example of metal ions that form complex ions includes
Example of Lewis bases includes,
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Chemistry & Chemical Reactivity
- 21). The solubility product for silver phosphate is Ksp = 1.8 x 10–18. What is the molar solubility of Ag3PO4? (a) Show the reaction of dissociation of Ag3PO4. (b) Show the Ksp expression for Ag3PO4. (c) Calculate the molar solubility s for this compound.arrow_forwardfind present, absent and in doubt. And the reasoning of the following problem (photo)arrow_forward(ii) Consider the titration of 25.00 mL of 0.02000 M CaSO4 with 0.01000 M EDTA at pH 10.00. Write the chemical equation for this titration and calculate the conditional formation constant for this reaction. (iii) From (ii) calculate the concentration of Ca2+ and pCa2+ at the volume of 20.0 mL of EDTA added.arrow_forward
- From the following data find the percentages of Na2CO3 and NaHCO3 in a mixture of these chemicals and inert constituents: a) A 0.5000 g sample required 45.50 mL 0.1050 N HCl to reach the methyl orange end point. b) 25.00 mL of 0.1000 N KOH is added to 0.2500 g of the sample; BaCl2 is added to precipitate the BaCO3 and 12.00 mL 0.1050 N HCl is required to reach the phenolphthalein end point.arrow_forwardWhat is the solubility of calcium fluoride in a buffer solution containing 0.650 M HCHO2 (formic acid) and 0.20 M NaCHO2? K„(CaF2) = 3.4 x 10-11 K.(HF) = 6.8 × 10¬4 K.(HCHO2) =1.7 × 10¬4 (Hint: Consider the equation CaF2 (8) + 2H30*(ag) = Ca²+ (aq) + 2HF(aq) + 2H20(1) and solve the equilibrium problem.) Solubility = |мarrow_forward. A solution was prepared by mixing 4.00mL of 2.00 x 10-3 M Fe(NO3)3 and 3.00mL of 5.00 x 10-3 M NaSCN and diluting the mixture with water to a total of 10.00mL. Use your average value of Kc to calculate the equilibrium concentration of FeSCN2+ in the mixture. [Hint: Use as many significant figures as you legitimately can in your calculations] my average you can find on the picture below PLS HELP ASAP!!arrow_forward
- A buffer solution with a pH of 4,9, consists of 0,25 mol∙dm–3 acetic acid (HC2H3O2; Ka= 1,8 x 10–5) and 0,35 mol∙dm–3 potassium acetate (KC2H3O2). A small quantity (0,050 mol) of solid KOH is added to 1 dm3 of the buffer. This quantity is so small that it does not affect the volume of the buffer. Calculate the new pH of the buffer solution after the KOH has been added.arrow_forwardThe value of Ksp for Cd(OH)2 is 2.5 x 10-14. (a) Whatis the molar solubility of Cd1OH22? (b) The solubilityof Cd(OH)2can be increased through formation of thecomplex ion CdBr42 - (Kf = 5 x 103). If solid Cd(OH)2 isadded to a NaBr solution, what is the initial concentrationof NaBr needed to increase the molar solubility of Cd(OH)2to 1.0 x 10-3 mol/L?arrow_forwardSometimes it is not possible to indicate the end point of a titration.a) How can one proceed then and what is the name of the type of titration that can be performed? Briefly describe. An example in which this method can be used is in the determination of mercury, which forms strong complexes with EDTA, but for which there is no suitable indicator that can indicate the end point. b) You are given the task of determining the Hg2 + concentration in a sample solution? After adding an excess of EDTA, the sample solution is titrated with a magnesium solution. 20.00 ml of a 0.0452 M EDTA solution was added to 30.00 ml of sample solutionThe excess EDTA was determined by adding 0.0500 M Mg 2+ solution, consuming 4.37 ml to the end point.arrow_forward
- 2. You are measuring the Fe(II) content of a sample of FeCl2.4H20. You weighed out 1.20g FeCl2.4H20 and dissolved it in 50 mls of 0.5M sulfuric acid. You removed 10 ml.s of this solution, mixed it with sulfuric acid and diphenylamine sulfonate indicator, and titrated it to the equivalence point with 0.0167M K2Cr207 solution. You obtained the following data. Volume of dichromate needed to reach the equiv. point = 9.5 ml.s Given that MeVEe = 6MaiVdi, (where Mre= molarity of the Fe(II) solution, Vre is the volume of the Fe(II) solution =10 mls. Mai = molarity of the dichromate solution- 0.0167M, and Vai = volume of dichromatsolution = 9.5 ml.s), calculate: %3D (a) The molarity of the Fe(Il) solution -M (b) Mass of Fe in the original solution = (Me)(0.05)(55.845) = ------ (c) The theoretical mass % Fe in FeCl2.4H20 - -% (d) The experimental mass % Fe in your sample of FeCl2.4H2O----% (e) The % error in your determination of the mass % Fe ---------%arrow_forwardThe Ksp for BaCrO4 is 1.2×10−10.1.2×10−10. Will BaCrO4 precipitate upon mixing 10 mL of 1×10−41×10−4 M Ba(NO3)2 with 10 mL of 1×10−41×10−4 M K2CrO4?arrow_forwardIn the determination of chloride by the Mob method, what will be the equiliblium concentration of silver ions in mgil, on the basis of the solubility product principle, when the chloride concentation has been reduced to 0.2 ma? (b) If the concentration of chromate indicator used is 5X M, how much excess silver ion in mgil must be present before the formation of a red precipitate will begi(a) In the defermination of chloride by the Mohr method, what will be the equilibrium concentration of silver ions in meL., an the basis of the solubility. pcoduct principle, when the chloride concencration has beea reduced to 0.2m 1.2m? (b) If -3 the concentration of chromate indicator ased is 5 x 10M, bow much excess silver ion in mel, must be present before the formatice of a red precipitate will begin?arrow_forward
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