![Bundle: Organic Chemistry, 9th, Loose-Leaf + OWLv2, 4 terms (24 months) Printed Access Card](https://www.bartleby.com/isbn_cover_images/9781305701021/9781305701021_largeCoverImage.gif)
Concept explainers
a)
Interpretation:
Starting from benzene as the only source of
Concept introduction:
In aromatic electrophilic substitution reactions halogens are ortho and para directing groups while the keto group is a meta directing group. Hence to prepare p-chloroacetophenone, benzene has to be halogenated and the halobenzene obtained should be subjected to Friedal-Crafts acylation.
To state:
Starting from benzene as the only source of aromatic compounds and assuming that the ortho and para isomers can be separated, if necessary, how p-chloroacetophenone can be synthesized.
b)
Interpretation:
Starting from benzene as the only source of aromatic compounds and assuming that the ortho and para isomers can be separated, if necessary, how m-bromonitrobenzene can be synthesized is to be stated.
Concept introduction:
In aromatic electrophilic substitution reactions halogens are ortho and para directing groups while the nitro group is a meta directing group. Hence to prepare m-bromonitrobenzene, benzene has to be first nitrated and the nitrobenzene obtained should be halogenated.
To state:
Starting from benzene as the only source of aromatic compounds and assuming that the ortho and para isomers can be separated, if necessary, how m–bromonitrobenzene can be synthesized.
c)
Interpretation:
Starting from benzene as the only source of aromatic compounds and assuming that the ortho and para isomers can be separated, if necessary, how o-bromobenzenesulfonic acid can be synthesized is to be stated.
Concept introduction:
In aromatic electrophilic substitution reactions halogens are ortho and para directing groups while the sulfonic acid group is a meta directing group. Hence to prepare o-bromobenzenesulfonic acid, benzene has to be halogenated and the halobenzene obtained should be subjected to sulfonation.
To state:
Starting from benzene as the only source of aromatic compounds and assuming that the ortho and para isomers can be separated, if necessary, how o-bromobenzenesulfonic acid can be synthesized.
d)
Interpretation:
Starting from benzene as the only source of aromatic compounds and assuming that the ortho and para isomers can be separated, if necessary, how m-chlorobenzenesulfonic acid can be synthesized is to be stated.
Concept introduction:
In aromatic electrophilic substitution reactions halogens are ortho and para directing groups while the sulfonic acid group is a meta directing group. Hence to prepare m-chlorobenzenesulfonic acid, benzene has to be sulfonated and the benzenesulfonicacid obtained should be halogenated.
To state:
Starting from benzene as the only source of aromatic compounds and assuming that the ortho and para isomers can be separated, if necessary, how m-chlorobenzenesulfonic acid can be synthesized.
![Check Mark](/static/check-mark.png)
Trending nowThis is a popular solution!
![Blurred answer](/static/blurred-answer.jpg)
Chapter 16 Solutions
Bundle: Organic Chemistry, 9th, Loose-Leaf + OWLv2, 4 terms (24 months) Printed Access Card
- Part V. Label ad match the carbons in compounds Jane and Diane w/ the corresponding peak no. in the Spectra (Note: use the given peak no. To label the carbons, other peak no are intentionally omitted) 7 4 2 -0.13 -0.12 -0.11 -0.10 -0.08 8 CI Jane 1 -0.09 5 210 200 190 180 170 160 150 140 130 120 110 100 -8 90 f1 (ppm) 11 8 172.4 172.0 f1 (ppr HO CI NH Diane 7 3 11 80 80 -80 -R 70 60 60 2 5 -8 50 40 8. 170 160 150 140 130 120 110 100 90 -0 80 70 20 f1 (ppm) 15 30 -20 20 -60 60 -0.07 -0.06 -0.05 -0.04 -0.03 -0.02 -0.01 -0.00 -0.01 10 -0.17 16 15 56 16 -0.16 -0.15 -0.14 -0.13 -0.12 -0.11 -0.10 -0.09 -0.08 -0.07 -0.06 -0.05 -0.04 17.8 17.6 17.4 17.2 17.0 f1 (ppm) -0.03 -0.02 550 106 40 30 20 20 -0.01 -0.00 F-0.01 10 0arrow_forwardConsider the reaction of 2-methylpropane with a halogen. With which halogen will the product be almost exclusively 2-halo-2-methylpropane? 1. F2 2. Cl2 3. Br2 4. I2arrow_forwardNonearrow_forward
- Nonearrow_forwardn Feb 3 A T + 4. (2 pts) Draw the structure of the major component of the Limonene isolated. Explain how you confirmed the structure. 5. (2 pts) Draw the fragment corresponding to the base peak in the Mass spectrum of Limonene. 6. (1 pts) Predict the 1H NMR spectral data of R-Limonene. Proton NMR: 5.3 pon multiplet (H Ringarrow_forwardPart VI. Ca H 10 O is the molecular formula of compound Tom and gives the in the table below. Give a possible structure for compound Tom. 13C Signals summarized C1 C2 C3 C4 C5 C6 C7 13C shift (ppm) 23.5 27.0 33.0 35.8 127 162 205 DEPT-90 + DEPT-135 + +arrow_forward
- 2. Using the following data to calculate the value of AvapH o of water at 298K. AvapH o of water at 373K is 40.7 kJ/mol; molar heat capacity of liquid water at constant pressure is 75.2J mol-1 K-1 and molar heat capacity of water vapor at constant pressure is 33.6 J mol-1 K-1.arrow_forwardPart VII. Below are the 'HNMR 13 3 C-NMR, COSY 2D- NMR, and HSQC 20-NMR (Similar with HETCOR but axes are reversed) spectra of an organic compound with molecular formula C6H13 O. Assign chemical shift values to the H and c atoms of the compound. Find the structure. Show complete solutions. Predicted 1H NMR Spectrum ли 4.7 4.6 4.5 4.4 4.3 4.2 4.1 4.0 3.9 3.8 3.7 3.6 3.5 3.4 3.3 3.2 3.1 3.0 2.9 2.8 2.7 2.6 2.5 2.4 2.3 2.2 2.1 2.0 1.9 1.8 1.7 1.6 1.5 1.4 1.3 1.2 1.1 1.0 0.9 0.8 f1 (ppm)arrow_forward3. Draw the expanded structural formula, the condensed structural formula, and the skeletal structural formula for 2-pentene. expanded structure: Condensed structure: Skeletal formula: 4. Draw the expanded structural formula, the condensed structural formula, and the skeletal structural formula for 2-methyl-3-heptene. expanded structure: Condensed structure: Skeletal formula: following structurearrow_forward
- Part IV. Propose a plausible Structure w/ the following descriptions: a) A 5-carbon hydrocarbon w/ a single peak in its proton decoupled the DEPT-135 Spectrum shows a negative peak C-NMR spectrum where b) what cyclohexane dione isomer gives the largest no. Of 13C NMR signals? c) C5H120 (5-carbon alcohol) w/ most deshielded carbon absent in any of its DEPT Spectivaarrow_forward13C NMR is good for: a) determining the molecular weight of the compound b) identifying certain functional groups. c) determining the carbon skeleton, for example methyl vs ethyl vs propyl groups d) determining how many different kinds of carbon are in the moleculearrow_forward6 D 2. (1 pt) Limonene can be isolated by performing steam distillation of orange peel. Could you have performed this experiment using hexane instead of water? Explain. 3. (2 pts) Using GCMS results, analyze and discuss the purity of the Limonene obtained from the steam distillation of orange peel.arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305580350/9781305580350_smallCoverImage.gif)