Chapter 16.7, Problem 6MRE

To determine

To Find: The valueof:

  ${\sec }^{2}20°-{\tan }^{2}20°$ = ?

Answer to Problem 6MRE

1

Explanation of Solution

Given: ${\sec }^{2}20°-{\tan }^{2}20°$

Formula Used: ${\sec }^2\theta -{\tan }^2\theta =1$

Here, $\theta =20°$

So, the value of ${\sec }^{2}20°-{\tan }^{2}20°=1$

Answer is 1.