
(a)
To use:
The midpoint rule for double integral with six squares to estimate the area of the given surface
Solution:
Explanation:
1) Concept:
Use the formula for surface area and midpoint rule to evaluate it.
2) Formula and rule:
i) The surface area is
ii) Midpoint rule:
Where
3) Given:
4) Calculation:
Consider the given surface,
Differentiate
Differentiate
The area of the surface is given by,
Substitute the values,
Simplify,
By using midpoint rule with
Area of each sub rectangle is
Therefore,
Substituting the values,
By using calculator,
Conclusion:
The area of the given surface is
(b)
To use:
A computer algebra system to approximate the surface area in part (a) to four decimal places and compare it to the answer in part (a)
Solution:
Explanation:
1) Concept:
Use computer algebra system to evaluate the surface area and compare it to the answer in part (a).
2) Given:
3) Calculation:
From the part (a),
By using Mathematica,
Input:
Output:
Therefore, the surface area to four decimal places is
By comparing it with answer to part (a), it is correct up to first decimal place.
Conclusion:

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Chapter 16 Solutions
UD CALC (241 ONLY) W/1 TERM ACCESS >IB
- K Find all values x = a where the function is discontinuous. For each value of x, give the limit of the function as x approaches a. Be sure to note when the limit doesn't exist. x-7 p(x) = X-7 Select the correct choice below and, if necessary, fill in the answer box(es) within your choice. (Use a comma to separate answers as needed.) OA. f is discontinuous at the single value x = OB. f is discontinuous at the single value x= OC. f is discontinuous at the two values x = OD. f is discontinuous at the two values x = The limit is The limit does not exist and is not co or - ∞. The limit for the smaller value is The limit for the larger value is The limit for the smaller value is The limit for the larger value does not exist and is not c∞ or -arrow_forwardK x3 +216 complete the table and use the results to find lim k(x). If k(x) = X+6 X-6 X -6.1 -6.01 - 6.001 - 5.999 - 5.99 -5.9 k(x) Complete the table. X -6.1 -6.01 - 6.001 - 5.999 - 5.99 - 5.9 k(x) (Round to three decimal places as needed.) Find the limit. Select the correct choice below and, if necessary, fill in the answer box within your choice.arrow_forwardSketch the slope field that represents the differential equation. × Clear Undo Redo y ४|० || 33 dy dxarrow_forward
- Sketch the slope field that represents the differential equation. × Clear Undo Redo dy 33 dx = -y "arrow_forwardMath Test 3 3 x³+y³ = Ꭹ = 9 2 2 x²+y² = 5 x+y=?arrow_forwardFor each of the following series, determine whether the absolute convergence series test determines absolute convergence or fails. For the ¿th series, if the test is inconclusive then let Mi = 4, while if the test determines absolute convergence let Mi 1 : 2: ∞ Σ(−1)"+¹ sin(2n); n=1 Σ n=1 Σ ((−1)”. COS n² 3+2n4 3: (+ 4: 5 : n=1 ∞ n 2+5n3 ПП n² 2 5+2n3 пп n² Σ(+)+ n=1 ∞ n=1 COS 4 2 3+8n3 П ηπ n- (−1)+1 sin (+727) 5 + 2m³ 4 = 8. Then the value of cos(M₁) + cos(2M2) + cos(3M3) + sin(2M) + sin(M5) is -0.027 -0.621 -1.794 -1.132 -1.498 -4.355 -2.000 2.716arrow_forward
- i need help with this question i tried by myself and so i am uploadding the question to be quided with step by step solution and please do not use chat gpt i am trying to learn thank you.arrow_forwardi need help with this question i tried by myself and so i am uploadding the question to be quided with step by step solution and please do not use chat gpt i am trying to learn thank you.arrow_forward1. 3 2 fx=14x²-15x²-9x- 2arrow_forward
- No it is not a graded assignment, its a review question but i only have the final answer not the working or explanationarrow_forwardClass, the class silues, and the class notes, whether the series does alternate and the absolute values of the terms decrease), and if the test does apply, determine whether the series converges or diverges. For the ith series, if the test does not apply the let Mi = 2, while if the test determines divergence then M¿ = 4, and if it determines convergence then M¿ = 8. 1: 2: 3 : 4: 5 : ∞ n=1 ∞ (−1)n+1. Σ(-1) +1 n=1 ∞ п 3m² +2 Σ(-1)+1 sin(2n). n=1 ∞ 2n² + 2n +3 4n2 +6 1 e-n + n² 3n23n+1 9n² +3 In(n + 1) 2n+1 Σ(-1) +1 n=1 ∞ Σ(-1)". n=1 Then the value of cos(M₁) + cos(2M2) + cos(3M3) + sin(2M4) + sin(M5) is 1.715 0.902 0.930 -1.647 -0.057 ● 2.013 1.141 4.274arrow_forward3. FCX14) = x²+3xx-y3 +.arrow_forward
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