(a) Explanation The given values are: The initial concentration of niacin solution is 0.010 M . The acid dissociation constant of niacin is 1.5 × 10 − 5 . The structural formula of niacin is, Figure 1 The pyridine ring in niacin is replaced by substituent R for the simplification of the structure. Now, the general structure is RCOOH .The dissociation of niacin is given as, RCOOH ( a q ) ⇌ H + ( a q ) + RCOO − ( a q ) The ICE table for the above reaction is, RCOOH ( a q ) ⇌ H + ( a q ) + RCOO − ( a q ) Initial ( M ) 0.010 0.0 0.0 Change ( M ) − x + x + x Equilibrium ( M ) ( 0.010 − x ) x x The change in the concentration ( x ) of niacin is calculated by the formula, K a = [ H + ] [ RCOO − ] [ RCOOH ] Where, [ H + ] is the concentration of H + ions at equilibrium. [ RCOO − ] is the concentration of RCOO − ions at equilibrium. [ RCOOH ] is the concentration of niacin at equilibrium. K a is the dissociation constant of niacin (b) Interpretation Introduction To determine: The percentage ionization of niacin at given concentration.

Test Prep Series for AP Chemistry for Chemistry: The Central Science 14th ed AP

14th Edition

ISBN: 9780134661483

Author: Edward L Waterman

Publisher: PEARSON

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Chapter 16.6, Problem 16.13.2PE

(a)

Interpretation Introduction

To determine: The percentage ionization of niacin at given concentration.

(b)

Interpretation Introduction

To determine: The percentage ionization of niacin at given concentration.

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Chapter 16.6, Problem 16.13.1PE

Chapter 16.6, Problem 16.14.1PE

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Test Prep Series for AP Chemistry for Chemistry: The Central Science 14th ed AP

Ch. 16.2 - Practice Exercise 1 Consider the following...Ch. 16.2 - Prob. 16.1.2PE Ch. 16.2 - Prob. 16.2.1PE Ch. 16.2 - Practice Exercise 2 When lithium oxide (Li2O) is...Ch. 16.2 - Based on information in Figure 16.4, place the...Ch. 16.2 - Practice Exercise 2 For each reaction, use Figure...Ch. 16.3 - Practice Exercise 1 In a certain acidic solution...Ch. 16.3 - Practice Exercise 2 Indicate whether solutions...Ch. 16.3 - Prob. 16.5.1PE Ch. 16.3 - Prob. 16.5.2PE

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