Explanation Given The concentration of lactic acid solution is 0.10 M . The pH of the solution is 2.44 . Lactic acid ( CH 3 CH ( OH ) COOH ) is a weak acid so it will ionize partially and release H + ions in the aqueous solution. The chemical reaction of lactic acid in aqueous solution with H + ion as a product is, CH 3 CH ( OH ) COOH ( a q ) ⇌ H + ( a q ) + CH 3 CH ( OH ) COO − ( a q ) pH is the negative logarithm in the base 10 of [ H + ] . The concentration of H + ion is calculated by the formula, pH = − log [ H + ] [ H + ] = 10 − pH Where, [ H + ] is the concentration of H + ions. Substitute the value of pH in the above formula. [ H + ] = 10 − pH = 10 − 2 .44 = 3.63 × 10 − 3 M K a is the dissociation constant of acids. Weak acids ionize partially in aqueous solution. So, the dissociation constant of acids is used for determining the extent to which a weak acid ionizes. The initial concentration of lactic acid is 0.10 M and the concentration of H + ion after dissociation is 3.63 × 10 − 3 M . The ICE table for the dissociation reaction of lactic acid is, CH 3 CH ( OH ) COOH ( a q ) ⇌ H + ( a q ) + CH 3 CH ( OH ) COO − ( a q ) Initial: 0.10 M 0 0 Change: − 3.63 × 10 − 3 M 3.63 × 10 − 3 M 3

Test Prep Series for AP Chemistry for Chemistry: The Central Science 14th ed AP

14th Edition

ISBN: 9780134661483

Author: Edward L Waterman

Publisher: PEARSON

See similar textbooks

Videos

Question

Chapter 16, Problem 51E

Interpretation Introduction

To determine: The dissociation constant (Ka) for lactic acid that has one acidic hydrogen.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 16, Problem 50E

Chapter 16, Problem 52E

Students have asked these similar questions

[In this question, there are multiple answers to type in a "fill-in-the-blank" fashion - in each case, type in a whole number.] Consider using Slater's Rules to calculate the shielding factor (S) for the last electron in silicon (Si). There will be electrons with a 0.35 S-multiplier, electrons with a 0.85 S-multiplier, and electrons with a 1.00 S-multiplier.

Provide the unknown for the given data.

Draw the Lewis structures of two methanol (CH3OH) molecules and depict hydrogenbonding between them with dashed lines. Show all lone pairs. Provide a thorough analysis to apply concept idea into other problems.

Chapter 16 Solutions

Test Prep Series for AP Chemistry for Chemistry: The Central Science 14th ed AP

Ch. 16.2 - Practice Exercise 1 Consider the following...Ch. 16.2 - Prob. 16.1.2PE Ch. 16.2 - Prob. 16.2.1PE Ch. 16.2 - Practice Exercise 2 When lithium oxide (Li2O) is...Ch. 16.2 - Based on information in Figure 16.4, place the...Ch. 16.2 - Practice Exercise 2 For each reaction, use Figure...Ch. 16.3 - Practice Exercise 1 In a certain acidic solution...Ch. 16.3 - Practice Exercise 2 Indicate whether solutions...Ch. 16.3 - Prob. 16.5.1PE Ch. 16.3 - Prob. 16.5.2PE

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

The dissociation constant ( K a ) for lactic acid that has one acidic hydrogen.

Videos

To determine: The dissociation constant (Ka) for lactic acid that has one acidic hydrogen.

Want to see the full answer?

Chapter 16 Solutions