Explanation Given info: ∫ 0 3 ∫ 0 9 − x 2 ∫ 0 9 − x 2 x y d z d y d x Concept used: ∫ a b ∫ h 1 ( x ) h 2 ( x ) ∫ u 1 ( x , y ) u 2 ( x , y ) x y d z d y d x Then Domain of integration a ≤ x ≤ , h 1 ( x ) ≤ y ≤ h 2 ( x ) , u 1 ( x , y ) ≤ z ≤ u 2 ( x , y ) . First evaluate the integration with respect to z , then y , and at last w . r . t x Calculation: ∫ 0 3 ∫ 0 9 − x 2 ∫ 0 9 − x 2 − y 2 x y d z d y d x You have to perform integration w . r . t z Of lim i t of z : 0 ≤ y ≤ 9 − x 2 − y 2 Then have to perform integration w . r . t y and put the limit of y of y : 0 ≤ y ≤ 9 − x 2 At last have to perform integration w . r . t x and put the lim i t of x : 0 ≤ x ≤ 3 w : 0 ≤ y ≤ 0 , 0 , y ≤ 9 − x 2 , 0 ≤ z 9 − x 2 − y 2 Perform integration: ∫ 0 3 ∫ 0 9 − x 2 ∫ 0 9 − x 2 − y 2 x y d z d y d x Fist integrate w . r . t z assumming x and y as constant ∫ 0 3 ∫ 0 9 − x 2 ∫ 0 9 − x 2 − y 2 x y d z d y d x = ∫ 0 3 ∫ 0 9 − x 2 [ x y ∫ 0 9 − x 2 − y 2 d z ] d y d x = ∫ 0 3 ∫ 0 9 − x 2 x y [ z ] 0 9 − x 2 − y 2 d y d x ( put the limit of z ) = ∫ 0 3 ∫ 0 9 − x 2 ( x y 9 − x 2 − y 2 ) d y d x d d x ( 9 − x 2 − y 2 ) = − 2 y ( assuming x as constant ) ( d ( 9 − x 2 − y 2 ) = − 2 y d y ) y d y = − 1 2 d ( 9 − x 2 − y 2 ) Put the value of y d y in above integration. = ∫ 0 3 ∫ 0 9 − x 2 ( x . 9 − x 2 − y 2 ) ( y d y ) ( d x ) . ( convert into appropriate form to integrate ) = ∫ 0 3 ∫ 0 9 − x 2 x 9 − x 2 − y 2 × − 1 2 d ( 9 − x 2 − y 2 ) d x ...

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ISBN: 9781319434526

Author: Rogawski

Publisher: MAC HIGHER

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Question

Chapter 16.3, Problem 24E

To determine

Describe the domain of interrogation and evaluate

$\int_{0}^{3} \int_{0}^{\sqrt{9 - x^{2}}} \int_{0}^{\sqrt{9 - x^{2}}} x y d z d y d x$

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Chapter 16.3, Problem 23E

Chapter 16.3, Problem 25E

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Chapter 16 Solutions

CALCULUS 4E (LL) W/ ACHIEVE ACCESS

Ch. 16.1 - Prob. 1PQ Ch. 16.1 - Prob. 2PQ Ch. 16.1 - Prob. 3PQ Ch. 16.1 - Prob. 4PQ Ch. 16.1 - Prob. 5PQ Ch. 16.1 - Prob. 6PQ Ch. 16.1 - Prob. 1E Ch. 16.1 - Prob. 2E Ch. 16.1 - Prob. 3E Ch. 16.1 - Prob. 4E

Ch. 16.1 - Prob. 5E Ch. 16.1 - Prob. 6E Ch. 16.1 - Prob. 7E Ch. 16.1 - Prob. 8E Ch. 16.1 - Prob. 9E Ch. 16.1 - Prob. 10E Ch. 16.1 - Prob. 11E Ch. 16.1 - Prob. 12E Ch. 16.1 - Prob. 13E Ch. 16.1 - Prob. 14E Ch. 16.1 - Prob. 15E Ch. 16.1 - Prob. 16E Ch. 16.1 - Prob. 17E Ch. 16.1 - Prob. 18E Ch. 16.1 - Prob. 19E Ch. 16.1 - Prob. 20E Ch. 16.1 - Prob. 21E Ch. 16.1 - Prob. 22E Ch. 16.1 - Prob. 23E Ch. 16.1 - Prob. 24E Ch. 16.1 - Prob. 25E Ch. 16.1 - Prob. 26E Ch. 16.1 - Prob. 27E Ch. 16.1 - Prob. 28E Ch. 16.1 - Prob. 29E Ch. 16.1 - Prob. 30E Ch. 16.1 - Prob. 31E Ch. 16.1 - Prob. 32E Ch. 16.1 - Prob. 33E Ch. 16.1 - Prob. 34E Ch. 16.1 - Prob. 35E Ch. 16.1 - Prob. 36E Ch. 16.1 - Prob. 37E Ch. 16.1 - Prob. 38E Ch. 16.1 - Prob. 39E Ch. 16.1 - Prob. 40E Ch. 16.1 - Prob. 41E Ch. 16.1 - Prob. 42E Ch. 16.1 - Prob. 43E Ch. 16.1 - Prob. 44E Ch. 16.1 - Prob. 45E Ch. 16.1 - Prob. 46E Ch. 16.1 - Prob. 47E Ch. 16.1 - Prob. 48E Ch. 16.1 - Prob. 49E Ch. 16.1 - Prob. 50E Ch. 16.1 - Prob. 51E Ch. 16.1 - Prob. 52E Ch. 16.1 - 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Prob. 2E Ch. 16.5 - Prob. 3E Ch. 16.5 - Prob. 4E Ch. 16.5 - Prob. 5E Ch. 16.5 - Prob. 6E Ch. 16.5 - Prob. 7E Ch. 16.5 - Prob. 8E Ch. 16.5 - Prob. 9E Ch. 16.5 - Prob. 10E Ch. 16.5 - Prob. 11E Ch. 16.5 - Prob. 12E Ch. 16.5 - Prob. 13E Ch. 16.5 - Prob. 14E Ch. 16.5 - Prob. 15E Ch. 16.5 - Prob. 16E Ch. 16.5 - Prob. 17E Ch. 16.5 - Prob. 18E Ch. 16.5 - Prob. 19E Ch. 16.5 - Prob. 20E Ch. 16.5 - Prob. 21E Ch. 16.5 - Prob. 22E Ch. 16.5 - Prob. 23E Ch. 16.5 - Prob. 24E Ch. 16.5 - Prob. 25E Ch. 16.5 - Prob. 26E Ch. 16.5 - Prob. 27E Ch. 16.5 - Prob. 28E Ch. 16.5 - Prob. 29E Ch. 16.5 - Prob. 30E Ch. 16.5 - Prob. 31E Ch. 16.5 - Prob. 32E Ch. 16.5 - Prob. 33E Ch. 16.5 - Prob. 34E Ch. 16.5 - Prob. 35E Ch. 16.5 - Prob. 36E Ch. 16.5 - Prob. 37E Ch. 16.5 - Prob. 38E Ch. 16.5 - Prob. 39E Ch. 16.5 - Prob. 40E Ch. 16.5 - Prob. 41E Ch. 16.5 - Prob. 42E Ch. 16.5 - Prob. 43E Ch. 16.5 - Prob. 44E Ch. 16.5 - Prob. 45E Ch. 16.5 - Prob. 46E Ch. 16.5 - Prob. 47E Ch. 16.5 - Prob. 48E Ch. 16.5 - Prob. 49E Ch. 16.5 - 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Prob. 29E Ch. 16.6 - Prob. 30E Ch. 16.6 - Prob. 31E Ch. 16.6 - Prob. 32E Ch. 16.6 - Prob. 33E Ch. 16.6 - Prob. 34E Ch. 16.6 - Prob. 35E Ch. 16.6 - Prob. 36E Ch. 16.6 - Prob. 37E Ch. 16.6 - Prob. 38E Ch. 16.6 - Prob. 39E Ch. 16.6 - Prob. 40E Ch. 16.6 - Prob. 41E Ch. 16.6 - Prob. 42E Ch. 16.6 - Prob. 43E Ch. 16.6 - Prob. 44E Ch. 16.6 - Prob. 45E Ch. 16.6 - Prob. 46E Ch. 16.6 - Prob. 47E Ch. 16.6 - Prob. 48E Ch. 16.6 - Prob. 49E Ch. 16.6 - Prob. 50E Ch. 16.6 - Prob. 51E Ch. 16.6 - Prob. 52E Ch. 16 - Prob. 1CRE Ch. 16 - Prob. 2CRE Ch. 16 - Prob. 3CRE Ch. 16 - Prob. 4CRE Ch. 16 - Prob. 5CRE Ch. 16 - Prob. 6CRE Ch. 16 - Prob. 7CRE Ch. 16 - Prob. 8CRE Ch. 16 - Prob. 9CRE Ch. 16 - Prob. 10CRE Ch. 16 - Prob. 11CRE Ch. 16 - Prob. 12CRE Ch. 16 - Prob. 13CRE Ch. 16 - Prob. 14CRE Ch. 16 - Prob. 15CRE Ch. 16 - Prob. 16CRE Ch. 16 - Prob. 17CRE Ch. 16 - Prob. 18CRE Ch. 16 - Prob. 19CRE Ch. 16 - Prob. 20CRE Ch. 16 - Prob. 21CRE Ch. 16 - Prob. 22CRE Ch. 16 - Prob. 23CRE Ch. 16 - Prob. 24CRE Ch. 16 - Prob. 25CRE Ch. 16 - Prob. 26CRE Ch. 16 - Prob. 27CRE Ch. 16 - Prob. 28CRE Ch. 16 - Prob. 29CRE Ch. 16 - Prob. 30CRE Ch. 16 - Prob. 31CRE Ch. 16 - Prob. 32CRE Ch. 16 - Prob. 33CRE Ch. 16 - Prob. 34CRE Ch. 16 - Prob. 35CRE Ch. 16 - Prob. 36CRE Ch. 16 - Prob. 37CRE Ch. 16 - Prob. 38CRE Ch. 16 - Prob. 39CRE Ch. 16 - Prob. 40CRE Ch. 16 - Prob. 41CRE Ch. 16 - Prob. 42CRE Ch. 16 - Prob. 43CRE Ch. 16 - Prob. 44CRE Ch. 16 - Prob. 45CRE Ch. 16 - Prob. 46CRE Ch. 16 - Prob. 47CRE Ch. 16 - Prob. 48CRE Ch. 16 - Prob. 49CRE Ch. 16 - Prob. 50CRE Ch. 16 - Prob. 51CRE Ch. 16 - Prob. 52CRE Ch. 16 - Prob. 53CRE Ch. 16 - Prob. 54CRE Ch. 16 - Prob. 55CRE Ch. 16 - Prob. 56CRE Ch. 16 - Prob. 57CRE Ch. 16 - Prob. 58CRE Ch. 16 - Prob. 59CRE Ch. 16 - Prob. 60CRE Ch. 16 - Prob. 61CRE

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Describe the domain of interrogation and evaluate ∫ 0 3 ∫ 0 9 − x 2 ∫ 0 9 − x 2 x y d z d y d x

Solution Summary: The author explains how to determine the domain of interrogation and evaluate it. Then evaluate the integration with respect to z, then y, and at last w.

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Describe the domain of interrogation and evaluate

$\int_{0}^{3} \int_{0}^{\sqrt{9 - x^{2}}} \int_{0}^{\sqrt{9 - x^{2}}} x y d z d y d x$

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Chapter 16 Solutions

Describe the domain of interrogation and evaluate ∫ 0 3 ∫ 0 9 − x 2 ∫ 0 9 − x 2 x y d z d y d x

Solution Summary: The author explains how to determine the domain of interrogation and evaluate it. Then evaluate the integration with respect to z, then y, and at last w.

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Describe the domain of interrogation and evaluate ∫03∫09−x2∫09−x2xydzdydx

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Chapter 16 Solutions

Describe the domain of interrogation and evaluate

$\int_{0}^{3} \int_{0}^{\sqrt{9 - x^{2}}} \int_{0}^{\sqrt{9 - x^{2}}} x y d z d y d x$