Explanation Given : f ( x , y ) = e x + y , Domain D bounded by y = x − 1 , y = 12 − x for 2 ≤ y ≤ 4 Calculation : Step 1: These curves describe D as a horizontally simple region. Step 2: Computing the double integral of f ( x , y ) = e x + y over D using Theorem 2 by evaluating the following iterated integral, we get ∫ ∫ D e x + y d A = ∫ 2 4 ∫ y + 1 12 − y e x + y d x d y = ∫ 2 4 e x + y | x = y + 1

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ISBN: 9781319434526

Author: Rogawski

Publisher: MAC HIGHER

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Chapter 16.2, Problem 23E

To determine

The value of the double integral of $f (x, y) = e^{x + y}$ over the domain D bounded by $y = x - 1, y = 12 - x$ for $2 \leq y \leq 4$

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Chapter 16.2, Problem 22E

Chapter 16.2, Problem 24E

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Chapter 16 Solutions

CALCULUS 4E (LL) W/ ACHIEVE ACCESS

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The value of the double integral of f ( x , y ) = e x + y over the domain D bounded by y = x − 1 , y = 12 − x for 2 ≤ y ≤ 4

Solution Summary: The author calculates the value of the double integral of f (x, y) = e x+y over the domain D by evaluating the following iterated integral.

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The value of the double integral of $f (x, y) = e^{x + y}$ over the domain D bounded by $y = x - 1, y = 12 - x$ for $2 \leq y \leq 4$

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Chapter 16 Solutions

The value of the double integral of f ( x , y ) = e x + y over the domain D bounded by y = x − 1 , y = 12 − x for 2 ≤ y ≤ 4

Solution Summary: The author calculates the value of the double integral of f (x, y) = e x+y over the domain D by evaluating the following iterated integral.

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The value of the double integral of f(x,y)=ex+y over the domain D bounded by y=x−1,y=12−x for 2≤y≤4

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Chapter 16 Solutions

The value of the double integral of $f (x, y) = e^{x + y}$ over the domain D bounded by $y = x - 1, y = 12 - x$ for $2 \leq y \leq 4$