Explanation Given information: Mass of the slender rod AB is, m A B = 4 l b Mass of the slender rod BF is, m B F = 8 l b Mass of thin sleeve CE is, m C E = 4 l b Length of the rod AB is, L A B = 10 i n . o r 10 12 f t The motion of the link is controlled by couple M applied at rod AB. The angular velocity of rod AB is, ω A B = 30 r a d / s The angular acceleration of rod AB is, α A B = 96 r a d / s 2 ( c l o c k w i s e ) Calculations: The free body diagram of rod AB is The angular velocity of the rod BF is zero i.e. ω B F = 0 Now the angular acceleration of BE is calculated by the angular velocity of rod BE α B E = ω A B 2 α B E = ( 30 ) 2 α B E = 900 r a d / s 2 Now calculate the acceleration of centroid G, by the equation a G = L B D × α A B a G = 10 12 × 96 a G = 80 f t s To determine (b) The reaction at point D.

12th Edition

ISBN: 9781259977305

Author: BEER, Ferdinand P. (ferdinand Pierre), Johnston, E. Russell (elwood Russell), Cornwell, Phillip J., SELF, Brian P.

Publisher: Mcgraw-hill Education,

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Question

Chapter 16.2, Problem 16.140P

To determine

(a)

The magnitude of the couple M.

To determine

(b)

The reaction at point D.

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Chapter 16.2, Problem 16.139P

Chapter 16.2, Problem 16.141P

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(a) The magnitude of the couple M.

Solution Summary: The author calculates the angular acceleration of centroid G, by the equation la