Introduction to Statistics and Data Analysis
5th Edition
ISBN: 9781305115347
Author: Roxy Peck; Chris Olsen; Jay L. Devore
Publisher: Brooks Cole
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Chapter 16.1, Problem 6E
To determine
Interpret the 90% distribution free confidence
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1. Analyze the data as a two way factorial design.
Johnson and Leone (Statistics and Experimental
Design in Engineering and the Physical Sciences, Wiley,
977) describe an experiment to investigate warping of
copper plates. The two factors studied were the temperature
and the copper content of the plates. The response variable
was a measure of the amount of warping. The data were as
follows:
Temperature (°C)
50
75
100
125
40
17, 20
12,9
16, 12
21, 17
Copper Content (%)
60
80
16, 21
18, 13
18, 21
23, 2!
24, 22
17, 12
25, 23
23, 22
100
28, 27
27, 31
30, 23
29, 31
Fill the chi square for Cross 1 and Cross 2 from the following data in the attached image:
Cross 1:
Phenotypes
Ratio
Observed
Expected
(O-E)2/E
Totals
X2 =
Cross 2:
Phenotypes
Ratio
Observed
Expected
(O-E)2/E
Totals
X2 =
Listed below are pulse rates (beats per minute) from samples of adult males and females. Does there appear to be adifference? Find the coefficient of variation for each of the two samples; then compare the variation.
A. The coefficient of variation for the male pulse rates iS
(Type an integer or decimal rounded to one decimal place as needed.)
B. The coefficient of variation for the female pulse rates is
(Type an integer or decimal rounded to one decimal place as needed.)
Chapter 16 Solutions
Introduction to Statistics and Data Analysis
Ch. 16.1 - Urinary fluoride concentration (in parts per...Ch. 16.1 - Prob. 2ECh. 16.1 - Prob. 3ECh. 16.1 - A blood lead level of 70 mg/ml has been commonly...Ch. 16.1 - The effectiveness of antidepressants in treating...Ch. 16.1 - Prob. 6ECh. 16.1 - Prob. 7ECh. 16.2 - The effect of a restricted diet in the treatment...Ch. 16.2 - Peak force (N) on the hand was measured just prior...Ch. 16.2 - In an experiment to study the way in which...
Ch. 16.2 - Prob. 11ECh. 16.2 - Prob. 12ECh. 16.2 - Prob. 13ECh. 16.2 - Prob. 14ECh. 16.2 - Prob. 15ECh. 16.2 - Prob. 16ECh. 16.2 - Prob. 17ECh. 16.2 - The signed-rank test can be adapted for use in...Ch. 16.3 - Prob. 19ECh. 16.3 - Prob. 20ECh. 16.3 - The given data on phosphorus concentration in...Ch. 16.3 - Prob. 22ECh. 16.3 - Prob. 23ECh. 16.3 - The following data on amount of food consumed (g)...Ch. 16.3 - The article Effect of Storage Temperature on the...
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- 3.) A population has a mean of 300 and a variance of 80. If we get 160 samples from this population, what wili be the mean and standard deviation of the sampling distribution of sample mean? A.) Hg = 300 and og =0.53 B.) µg = 300 and og =0.71 C.) µg = 300 and og =6.32 D.) µg = 300 and og =80 %3D %3Darrow_forwardPsi is a measure of compressive strength, or the ability of the material to carry loads and handle compression. The desired concrete psi rating used for sidewalks and residential driveways ranges from 2500psi to 3000psi obtained from mixing cement, stone, and sand in different ratios but with the same amount of water. The summary of the psi's of three (3) such concrete mixes made by three (3) different civil engineering students is given as follows: Mean vector: The variance-covariance matrix: Concrete mix Mean Concrete mix 1 Concrete mix 2 Concrete mix 3 Concrete mix 1 | Concrete mix 2 2700 18 12 2 3000 12 16 3 2400 Concrete mix 3 16 25 Let the random variable Y be the vector of the psi's of concrete mixes obtained by the students, i.e. Y1, denotes the psi of concrete mix made by student 1, Y2 is the psi of concrete mix made by student 2 and Y3 is the psi of concrete mix psi made by student 3. (a) Find (i) the multivariate probability distribution function (pdf) of Y. (ii) the…arrow_forwardDo males make significantly more money than females at RIT? Be sure to weight the variables in SPSS Ver.29. Interpret all results. Gender Salaries Weight Male $88,000 15 Male $99,000 16 Male $80,000 10 Male $90,000 10 Male $99,999 12 Male $79,000 11 Female $50,000 10 Female $62,000 15 Female $55,000 10 Female $45,000 10 Female $24,000 15 (I need a output from SPSS; and Interpretion)If you are unable to provide the output from SPSS then please provide the instructions step-by-step on how I can get the text output.arrow_forward
- A group of students measure the length and width of a random sample of beans. They are interested in investigating the relationship between the length and width. Their summary statistics are displayed in the table below. All units, if applicable, are millimeters. Mean width: 7.555 Stdev width: 0.914 Mean height: 12.686 Stdev height: 1.634 Correlation coefficient: 0.8203 d) If the students are interested in using the height of the beans to predict the width, calculate the slope of this new regression equation. e) Write the equation of the best-fit line that can be used to predict bean widths. Use x to represent height and y to represent width.arrow_forward4.) A person's muscle mass is expected to decrease with age. To explore this relationship, a researcher randomly selected 10 persons from ages 40 to 79 years old and measured their muscle mass (unit). The result is as follows: X (age) Y (muscle mass) 71 64 43 67 56 73 68 56 76 65 82 91 100 68 87 73 78 80 65 84 Based on the given data, do the following: a) Plot the scatter diagram of the given data. [3pts] b) Obtain the regression line equation. [4pts] c) Estimate the muscle mass when age of the person is 60 years old. [3pts] 5.) Recognize how each shape has transformed. [2pts each] a.) b.) c.)arrow_forwardConsider the following measurements of blood hemoglobin concentrations (in g/dL) from three human populations at different geographic locations: population1 = [ 14.7 , 15.22, 15.28, 16.58, 15.10 ] population2 = [ 15.66, 15.91, 14.41, 14.73, 15.09] population3 = [ 17.12, 16.42, 16.43, 17.33] If you run ANOVA on the data for the three populations, what is the range of the P-value? Greater than 0.05 between 0.05 and 0.025 between 0.025 and 0.01 less than 0.01arrow_forward
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